C++ 未知格式的二次方程求解器输出

我试图做一个二次方程求解器，但由于某种原因，我的程序以未知的格式给我答案

我输入了一个简单的二次方程x^2+2x+1=0，期望我的程序给出x=-1或x=-1，但它给出了x=0138151E或x=0138152D。它看起来像是为x输出这些值，用于任何无法识别和捕捉不真实答案的输入。这是为什么？我如何修复它

#include "../std_lib_facilities_revised.h"

class Imaginary {};

double square(int a)
{
    return a * a;
}

double quadratic_solver_pos(int a, int b, int c)
{
    double x = 0.0;
    double radicand = square(b) - 4 * a * c;
    if (radicand < 0) throw Imaginary{};
    x = (-b + sqrt(radicand)) / (2 * a);
    return x;
}

double quadratic_solver_neg(int a, int b, int c)
{
    double x = 0.0;
    double radicand = square(b) - 4 * a * c;
    if (radicand < 0) throw Imaginary{};
    x = (-b - sqrt(radicand)) / (2 * a);
    return x;
}

int main()
try {
    cout << "This program is a quadratic equation solver.\n";
    cout << "Quadratic equations are of the form: ax^2 + bx + c = 0\n";
    cout << "Enter a, b, and c, respectively:\n";
    double a = 0; 
    double b = 0;
    double c = 0;
    cin >> a >> b >> c;
    cout << "Your quadratic equation: " << a << "x^2 + " << b << "x + " << c << " = 0\n";
    cout << "x = " << quadratic_solver_pos << " or x = " << quadratic_solver_neg << '\n';
}
catch (Imaginary) {
    cout << "x is unreal\n";
}

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您不会将变量传递给函数

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你需要像这样做二次解算器

为什么你要打印出你函数的地址而不是调用函数呢？投票结束就像打字一样。您需要调用该函数。顺便说一句，删除square函数并用x*x替换调用。简单操作不需要调用函数。拥有两个函数二次解算器pos和二次解算器neg似乎也是多余的。恕我直言，但一个编写良好的函数可以处理这两种情况。另外：我是否应该大胆地问一下include../std_lib_facilities\u revision.h是什么？谢谢，我没有看到。