C# 4.0 在独立存储上工作时，Schedule Agent上的交叉异常无效

我正在使用Windows Phone Schedule Agent，并尝试在同步后更新图片名称。问题是，当我在此函数的“BitmapImage bmp=new BitmapImage（）；”行上遇到无效的交叉异常，我真的不明白为什么

void UpdateSyncPictureName(int AsyncStatus, int AticketID, int AsyncID, int ApictureID, int TsyncStatus = 0, int TsyncID = 0)
    {
        string filename = AsyncStatus + "-" + AticketID + "-" + AsyncID + "-" + ApictureID;
        using (IsolatedStorageFile ISF = IsolatedStorageFile.GetUserStoreForApplication())
        {
            if (ISF.FileExists(filename))
            {

                BitmapImage bmp = new BitmapImage();
                using (IsolatedStorageFileStream isoStream =
                    ISF.OpenFile(filename, System.IO.FileMode.Open))
                {
                    bmp.SetSource(isoStream);
                }
                ISF.DeleteFile(filename);
                WriteableBitmap Wbmp = new WriteableBitmap(bmp);
                using (IsolatedStorageFileStream isoStream =
                ISF.OpenFile(TsyncStatus + "-" + AticketID + "-" + TsyncID + "-" + ApictureID, System.IO.FileMode.Create))
                {
                    Extensions.SaveJpeg(Wbmp, isoStream,
                        Wbmp.PixelWidth,
                        Wbmp.PixelHeight,
                        0, 100);
                }


            }
        }
    }

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该问题源于无法在UI线程之外实例化BitmapImage这一事实。您可以通过在Dispatcher Invoke调用中包装调用来修复此问题

但是，您需要确保正确调用NotifyComplete。因此，您可能需要在Dispatcher调用中输入NotifyComplete

Deployment.Current.Dispatcher.BeginInvoke(() =>
{
    UpdateSyncPictureName(...);
    NotifyComplete();
});

---

该问题源于无法在UI线程之外实例化BitmapImage这一事实。您可以通过在Dispatcher Invoke调用中包装调用来修复此问题

但是，您需要确保正确调用NotifyComplete。因此，您可能需要在Dispatcher调用中输入NotifyComplete

Deployment.Current.Dispatcher.BeginInvoke(() =>
{
    UpdateSyncPictureName(...);
    NotifyComplete();
});