C#-循环结束结果

我将尽我所能解释这一点，所以请耐心听我说。我在做一个游戏，基本上有100码。你从100开始，它在一个循环中，生成数字并从100码中减去它们。一旦数字达到0，循环将停止

请看下面的代码：

int yardsLeft = 100;
    // this is on a loop until 'yardsLeft = 0'
if (yardsLeft >= 80)
{
    // 10% chance of generating a number 80-100
    // 20% chance of generating a number 40-80
    // 70% chance of generating a number 1-40

    // Say it hits the 10% chance and generates the number 85 - there's 15 yards left
    // it will pass through the if statements entering the `if (yardsLeft < 40)` - say that hits 20 once more. at the end once the yardsLeft finally equals 0, the yards added up each loop will be over 100. in this case 120
    -------------------------------
    // but if the generated number generates a 70% chance and hits a number 1-20, it's going to stay in the `yardsLeft > 80` if statment-
    // therefore having the potential to exceed the number '100' once the `yardsLeft = 0`
}
else if (yardsLeft >= 40 && yardsLeft <= 79) { } // this would activate if the 20% chance got generated
if (yardsLeft < 40)
    {
    // 10% chance of generating a number 30-39
    // 20% chance of generating a number 10-29
    // 70% chance of generating a number 1-9
    }

这是我的变量

public static Random r = new Random();
public static int gained;
public static int yardsLeft = 100;
public static int i = 0;
public static int chance = r.Next(1, 101);

---

不要只是从最上面的if/else if/else语句返回数字，而是等到块的末尾再返回。这将允许您收集所有逻辑，以便在一个位置进行计算

private int Play(int yardsLeft) // Pass in the total yards left here
{
    var yards = 0;

    if (yardsLeft >= 80)
    {
        yards = // The result of your 10/20/70% calculation
    }
    else if (yardsLeft >= 40) { } // Same deal
    else { } // Again, same as in the if

    return yards > yardsLeft ? yardsLeft : yards;
}

---

你也可以修改它，以提供一个字符串来表示是否得分。（将

yardsLeft

参数设置为

ref

，以便您可以在该方法中调整剩余的码数。）

我认为您没有理解。每经过一个循环，就会产生一个数字。这些数字加起来直到它达到100，也使得雅兹列夫等于0。我这样做的方法会使最终结果超过100，因为当它循环，并且到达'yardsLeft>=80'时，这不是正确的计算，所以它会加上100以上。我需要精确到100。但我不知道这和你的有什么不同？为什么不在那里澄清问题？为什么最终结果不能超过100？如果你到达99码，下一个随机数是100，只需返回

（100-99）=1

。你没有领会我的意思-生成的最终随机数是多少并不重要，因为你将超过100。因此，您只需返回上一次跑步和100之间行驶的距离。

private int Play(int yardsLeft) // Pass in the total yards left here
{
    var yards = 0;

    if (yardsLeft >= 80)
    {
        yards = // The result of your 10/20/70% calculation
    }
    else if (yardsLeft >= 40) { } // Same deal
    else { } // Again, same as in the if

    return yards > yardsLeft ? yardsLeft : yards;
}