C# 使用JSON响应将jQuery Ajax文件上载到ASP.NET web服务

我正在尝试使用jqueryajax将一个文件上传到一个cweb服务.asmx。然后，Web服务处理该文件，并将操作结果异步返回给调用JavaScript

文件上传工作正常。但是，它要求我省略contentType选项：“application/json；调用$.ajax函数时，charset=utf-8'。这会导致结果不会序列化为XML而不是预期的JSON。这反过来会导致jQuery调用错误处理程序而不是成功处理程序

这是我的客户端代码：

$.ajax({
    url: global.ajaxServiceUrl + '/StartStructureSynchronisation',
    type: 'POST',
    dataType: 'json',
    //Ajax events
    success: function (msg) {
      // this handler is never called
    error: function () {
      // this handler is called even when the call returns HTTP 200 OK
    },
    data: data, // this is a valid FormData() object
    //Options to tell jQuery not to process data or worry about content-type.
    cache: false,
    contentType: false,
    processData: false
});

[WebMethod(EnableSession = true)]
public string StartStructureSynchronisation()
{
    return this.Execute(delegate
    {
        if (HttpContext.Current.Request.Files.Count == 0)
        {
            Global.StructureSyncResult = new SyncResult() { Result = false, Log = new List<string>() { "No file uploaded." } };
        }
        else if (!new List<string>() { ".xls", ".xlsx" }.Contains(Path.GetExtension(HttpContext.Current.Request.Files[0].FileName).ToLower()))
        {
            Global.StructureSyncResult = new SyncResult() { Result = false, Log = new List<string>() { String.Format("({0}) is not a valid Excel file.", HttpContext.Current.Request.Files[0].FileName) } };
        }
        else
        {
            Global.StructureSyncResult = new Synchronization().SyncStructure(HttpContext.Current.Request.Files[0].InputStream, ref Global.DocSyncCurrent, ref Global.DocSyncMax);
        }

        return Global.Serializer.Serialize(Global.StructureSyncResult);
    });
}

这是我的服务器端代码：

$.ajax({
    url: global.ajaxServiceUrl + '/StartStructureSynchronisation',
    type: 'POST',
    dataType: 'json',
    //Ajax events
    success: function (msg) {
      // this handler is never called
    error: function () {
      // this handler is called even when the call returns HTTP 200 OK
    },
    data: data, // this is a valid FormData() object
    //Options to tell jQuery not to process data or worry about content-type.
    cache: false,
    contentType: false,
    processData: false
});

[WebMethod(EnableSession = true)]
public string StartStructureSynchronisation()
{
    return this.Execute(delegate
    {
        if (HttpContext.Current.Request.Files.Count == 0)
        {
            Global.StructureSyncResult = new SyncResult() { Result = false, Log = new List<string>() { "No file uploaded." } };
        }
        else if (!new List<string>() { ".xls", ".xlsx" }.Contains(Path.GetExtension(HttpContext.Current.Request.Files[0].FileName).ToLower()))
        {
            Global.StructureSyncResult = new SyncResult() { Result = false, Log = new List<string>() { String.Format("({0}) is not a valid Excel file.", HttpContext.Current.Request.Files[0].FileName) } };
        }
        else
        {
            Global.StructureSyncResult = new Synchronization().SyncStructure(HttpContext.Current.Request.Files[0].InputStream, ref Global.DocSyncCurrent, ref Global.DocSyncMax);
        }

        return Global.Serializer.Serialize(Global.StructureSyncResult);
    });
}

所以，基本上，我要找的是两件事之一：

使用contentType:'application/json；字符集=utf-8'。这样，响应将被序列化为JSON。我甚至可以将该文件作为WebMethod的参数来访问，而不用使用HttpContext.Current.Request.Files。 或者找到一种方法来强制Web服务始终将返回值序列化为JSON，而不管客户机怎么说。 有什么想法吗

事先非常感谢，并致以亲切的问候

Chris。

您可以使用Ajax库query.Ajax\u upload.0.6.js，使用起来很简单

我的代码只是为了提示

Button1基本上是从文件选择器对话框中选择文件的按钮

$(document).ready(function () {
    function  uploadFile(parameters) {
        /* example 1 */
        var button = $('#button1'), interval;
        $.ajax_upload(button, {
            action: "FileHandler.ashx?test=" + $("#paramter").val(),
            name: Selectedval,
            onSubmit: function (file, ext) {
                StartLoading();
            },
            onComplete: function (file, response) {                 
                StopLoading();                  
            }
        });
        uploadButton();//Register Event
    });
});

<html>
    <a id="button1"  style="width: 70%" class="button orange">Select File</a>
</html>

---

谢谢你的回答。虽然您的解决方案可能允许返回JSON序列化结果，但它完全绕过了web服务。您能想出一个仍然涉及web服务的解决方案吗？