C# 如何向控制器发送屏幕截图?

C# 如何向控制器发送屏幕截图?,c#,javascript,jquery,asp.net-mvc,post,C#,Javascript,Jquery,Asp.net Mvc,Post,我正在使用html2canvas库从页面获取快照,如何在我的C#Controller中获取该图像 查看 $("#button").click(function () { var image; html2canvas(document.body, { onrendered: function (canvas) { image = convertCanvasToImage(canvas); $.post("../../H

我正在使用html2canvas库从页面获取快照,如何在我的C#Controller中获取该图像

查看

$("#button").click(function () {
    var image;
    html2canvas(document.body, {
        onrendered: function (canvas) {
            image = convertCanvasToImage(canvas);
            $.post("../../HomeController/SetScreenShot", {
                sendImage: image
            }, function () {});
        }
    });
});
<input type="hidden" id="hiddenScreen" />
<script>
    function convertCanvasToImage(canvas) {
                var image = new Image();
                image.src = canvas.toDataURL("image/png");
                image.id = "canvasimage";
                return image;
            }

      $("#button").click(function () {
                    var image;
                    var data;
                    html2canvas(document.body, {
                        onrendered: function(canvas) {
                            image = convertCanvasToImage(canvas);
                            $("#hiddenScreen").append(image);
                            data = $('#canvasimage').attr('src');
                        }
                    });
                     $.ajax({ 
                            type: "POST", 
                            url: '../../HomeController/SetScreenShot',
                            dataType: 'text',
                            data: {
                                base64data : data
                            }
                        });
</script>
控制器

public void SetScreenShot()
{
    HttpPostedFileBase file = new HttpPostedFileBase();
    file = Request.Form["sendImage"].ToString();
}
public void SetScreenShot()
        {
            if (Session["screenShot"] == null) Session.Add("screenShot", "");
            Session["screenShot"] = Request.Form["base64data"].ToString();
        }

我找到了如何做到这一点,只需要在页面上的隐藏输入中附加该图像,并从图像src发送它

查看

$("#button").click(function () {
    var image;
    html2canvas(document.body, {
        onrendered: function (canvas) {
            image = convertCanvasToImage(canvas);
            $.post("../../HomeController/SetScreenShot", {
                sendImage: image
            }, function () {});
        }
    });
});
<input type="hidden" id="hiddenScreen" />
<script>
    function convertCanvasToImage(canvas) {
                var image = new Image();
                image.src = canvas.toDataURL("image/png");
                image.id = "canvasimage";
                return image;
            }

      $("#button").click(function () {
                    var image;
                    var data;
                    html2canvas(document.body, {
                        onrendered: function(canvas) {
                            image = convertCanvasToImage(canvas);
                            $("#hiddenScreen").append(image);
                            data = $('#canvasimage').attr('src');
                        }
                    });
                     $.ajax({ 
                            type: "POST", 
                            url: '../../HomeController/SetScreenShot',
                            dataType: 'text',
                            data: {
                                base64data : data
                            }
                        });
</script>

简单来说,可以跳过隐藏的输入。这将实现以下目的:

$("#button").click(function () {
    html2canvas(document.body, {
        onrendered: function(canvas) {
            var image = canvas.toDataURL("image/png");
            image = image.replace('data:image/png;base64,', '');
            $.ajax({ 
                type: "POST", 
                url: '../../HomeController/SaveSnapshot',
                dataType: 'text',
                data: { base64data : image },
                success: function(result) { alert(result); }
            });
        }
    });
控制器(经过修改的版本,将图像保存到映射文件夹中):


Request.Files[“sendImage”]
maybe?哦,是的,从控制器端必须是.Files,但如何从视图端正确发送图像?因为现在我得到了异常:uncaughttypeerror:非法调用