C# 使用非常基本的if语句比较数字

我想让用户输入3个独立的整数，如果它们彼此不相等，程序会返回哪些数字彼此相等。对于我这里的代码，我可以说它们彼此相等，前两个相等，但第一个和第三个不相等。我假设这是因为我的else语句没有正确地放在大括号中

    using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using static System.Console;

namespace Compare3Numbers
{
    class Program
    {
        static void Main(string[] args)
        {


            int number1;
            int number2;
            int number3;

            Write("Enter the first number: ");
            number1 = int.Parse(ReadLine());

            Write("Enter the second number: ");
            number2 = int.Parse(ReadLine());

            Write("Enter the third number: ");
            number3 = int.Parse(ReadLine());

            if (number1 == number2 && number2 == number3)
            {
                if (number2 == number3)
                {
                    WriteLine("All your numbers are equal!");
                }
                else if (number1 == number2)
                {
                    WriteLine("Your first two numbers are equal!");
                }

                else if (number1 == number3)
                {
                    WriteLine("Your first number and third number are equal!");
                }
                else if (number2 == number3)
                {
                    WriteLine("Your second number is equal to your third number!");
                }
            }





            //debug line
            WriteLine("Press any key to continue...");
            ReadLine();
        }
    }
}

---

额外阅读

---

额外阅读

这样看吧

if (number1 == number2)
{
//rest of your if statements
}

由于1和2不相等，因此将执行if语句中的任何内容。你需要在那之外检查number1==number3。

这样看

if (number1 == number2)
{
//rest of your if statements
}

---

由于1和2不相等，因此将执行if语句中的任何内容。您需要在这之外检查number1==number3。

只有当前两个数字相等时，才会写入代码中的消息。并且没有针对第一个和第三个以及第二个和第三个号码运行的检查

尝试一步一步地调试代码以查看路径

我建议您使用代码分析器。“双重比较相同条件”问题您的代码将通过声纳Lint显示

在第二行

if (number1 == number2)

您将获得：

警告S2583更改此条件，使其不总是计算为“真”；某些后续代码永远不会执行

正确的代码可以如下所示：

if (number1 == number2)
{
     if (number2 == number3)
    {
        WriteLine("All your numbers are equal!");
    }
    else
    {
        WriteLine("Your first two numbers are equal!");
    }
}
else
{
    if (number1 == number3)
    {
        WriteLine("Your first number and third number are equal!");
    }
    // there is no need for else, because this would mean, that (number1 == number2) and this is the part, where these number differs
    if (number2 == number3)
    {
        WriteLine("Your second number and third number are equal!");
    }
}

var dictionary = new Dictionary<string, bool>
{
   { "Your first two numbers are equal!", Math.Abs(number1 - number2) == 0 },
   { "Your second number is equal to your third number!", Math.Abs(number2 - number3) == 0 },
   { "Your first number and third number are equal!", Math.Abs(number3 - number1) == 0 }
};

var output = dictionary.Where(i => i.Value).ToList();
var message = output.Count == 3 ? "All your numbers are equal!" : output.FirstOrDefault(i => i.Value).Key;            
            Console.WriteLine(message);

---

只有当前两个数字相等时，才会写入代码中的消息。并且没有针对第一个和第三个以及第二个和第三个号码运行的检查

尝试一步一步地调试代码以查看路径

我建议您使用代码分析器。“双重比较相同条件”问题您的代码将通过声纳Lint显示

在第二行

if (number1 == number2)

您将获得：

警告S2583更改此条件，使其不总是计算为“真”；某些后续代码永远不会执行

正确的代码可以如下所示：

if (number1 == number2)
{
     if (number2 == number3)
    {
        WriteLine("All your numbers are equal!");
    }
    else
    {
        WriteLine("Your first two numbers are equal!");
    }
}
else
{
    if (number1 == number3)
    {
        WriteLine("Your first number and third number are equal!");
    }
    // there is no need for else, because this would mean, that (number1 == number2) and this is the part, where these number differs
    if (number2 == number3)
    {
        WriteLine("Your second number and third number are equal!");
    }
}

var dictionary = new Dictionary<string, bool>
{
   { "Your first two numbers are equal!", Math.Abs(number1 - number2) == 0 },
   { "Your second number is equal to your third number!", Math.Abs(number2 - number3) == 0 },
   { "Your first number and third number are equal!", Math.Abs(number3 - number1) == 0 }
};

var output = dictionary.Where(i => i.Value).ToList();
var message = output.Count == 3 ? "All your numbers are equal!" : output.FirstOrDefault(i => i.Value).Key;            
            Console.WriteLine(message);

---

“n”数字的通用方法（继续插入数字，直到遇到“q”）

输出

Your 1st, 7th, 10th and 13th are equal
Your 2nd, 8th and 11th are equal
Your 3rd, 9th and 12th are equal

---

“n”数字的通用方法（继续插入数字，直到遇到“q”）

输出

Your 1st, 7th, 10th and 13th are equal
Your 2nd, 8th and 11th are equal
Your 3rd, 9th and 12th are equal

---

我会这样做：

if (number1 == number2)
{
     if (number2 == number3)
    {
        WriteLine("All your numbers are equal!");
    }
    else
    {
        WriteLine("Your first two numbers are equal!");
    }
}
else
{
    if (number1 == number3)
    {
        WriteLine("Your first number and third number are equal!");
    }
    // there is no need for else, because this would mean, that (number1 == number2) and this is the part, where these number differs
    if (number2 == number3)
    {
        WriteLine("Your second number and third number are equal!");
    }
}

var dictionary = new Dictionary<string, bool>
{
   { "Your first two numbers are equal!", Math.Abs(number1 - number2) == 0 },
   { "Your second number is equal to your third number!", Math.Abs(number2 - number3) == 0 },
   { "Your first number and third number are equal!", Math.Abs(number3 - number1) == 0 }
};

var output = dictionary.Where(i => i.Value).ToList();
var message = output.Count == 3 ? "All your numbers are equal!" : output.FirstOrDefault(i => i.Value).Key;            
            Console.WriteLine(message);

var字典=新字典
{
{“你的前两个数字相等！”，Math.Abs（number1-number2）==0}，
{“你的第二个数字等于你的第三个数字！”，Math.Abs（number2-number3）==0}，
{“你的第一个数字和第三个数字相等！”，Math.Abs（number3-number1）==0}
};
var output=dictionary.Where（i=>i.Value.ToList（）；
var消息=输出。计数=3？“所有数字都相等！”：output.FirstOrDefault（i=>i.Value）.Key；
控制台写入线（消息）；

我会这样做：

if (number1 == number2)
{
     if (number2 == number3)
    {
        WriteLine("All your numbers are equal!");
    }
    else
    {
        WriteLine("Your first two numbers are equal!");
    }
}
else
{
    if (number1 == number3)
    {
        WriteLine("Your first number and third number are equal!");
    }
    // there is no need for else, because this would mean, that (number1 == number2) and this is the part, where these number differs
    if (number2 == number3)
    {
        WriteLine("Your second number and third number are equal!");
    }
}

var dictionary = new Dictionary<string, bool>
{
   { "Your first two numbers are equal!", Math.Abs(number1 - number2) == 0 },
   { "Your second number is equal to your third number!", Math.Abs(number2 - number3) == 0 },
   { "Your first number and third number are equal!", Math.Abs(number3 - number1) == 0 }
};

var output = dictionary.Where(i => i.Value).ToList();
var message = output.Count == 3 ? "All your numbers are equal!" : output.FirstOrDefault(i => i.Value).Key;            
            Console.WriteLine(message);

var字典=新字典
{
{“你的前两个数字相等！”，Math.Abs（number1-number2）==0}，
{“你的第二个数字等于你的第三个数字！”，Math.Abs（number2-number3）==0}，
{“你的第一个数字和第三个数字相等！”，Math.Abs（number3-number1）==0}
};
var output=dictionary.Where（i=>i.Value.ToList（）；
var消息=输出。计数=3？“所有数字都相等！”：output.FirstOrDefault（i=>i.Value）.Key；
控制台写入线（消息）；

const int ONE=1和什么有什么关系？啊，我忘了把代码拿出来，以为我要用它，但现在可能不用了。

const int ONE=1

和什么有什么关系？啊，代码我忘了拿出来，以为我要用它，但现在可能不用了。所以当我运行这个时，它仍然不会显示第一个和第二个或第二个和第三个相等的消息。@boothegreat在编辑之后，代码的状态甚至比编辑之前更糟。现在，只有当所有数字相等时，它才会显示一条消息。因此，当我运行此程序时，它仍然不会显示第一个和第二个或第二个和第三个相等的消息。@boothegreat编辑后，代码的状态甚至比编辑前更糟。现在，只有当所有数字相等时，它才会显示一条消息。@boothegreat everything，请看我的示例抱歉，我没有真正理解。我不使用大括号吗？这是第二个if语句吗？@boothegreat这就是你嵌套Ifs的方式。@boothegreat所有的事情，看看我的例子抱歉我没有真正理解。我不使用大括号吗？这是第二个if语句吗？@boothegreat这就是你嵌套Ifs的方式。有趣的方法。同时感谢

AddOrdinal

。我不知道，计算后缀的规则是这样的。（我只从电脑和互联网上学习英语，所以我不知道这个规则。）有趣的方法。同时感谢

AddOrdinal

。我不知道，计算后缀的规则是这样的。（我只从电脑和互联网上学习英语，所以我不知道这条规则。）