C# 套接字接收数据错误

我在接收数据方面有一个奇怪的错误。基本上，您可以从一个客户端发送数据，也可以再次发送数据，但是如果您从第二个客户端发送数据，服务器第一次就不会收到数据，您必须再次发送数据。然后，您必须返回到另一个客户机并再次发送两次数据，以便服务器接收一次数据

我不知道这可能是什么，这里是代码，我认为可能是问题，让我知道，如果有什么我可以提供给你，以帮助我，在先进的感谢

从服务器：

public void beginReceive(object handler_obj){
    Socket handler = (Socket)handler_obj;

}

public void ReadCallback(IAsyncResult ar){
    Socket handler = (Socket)ar.AsyncState;
    try
    {
        int bytesRead = handler.EndReceive(ar);

        if (bytesRead > 0)
        {
            byte[] byteData = new byte[bytesRead];
            byteData = buffer;
            byte[] readData = new byte[byteData.Length - 1];
            Buffer.BlockCopy(byteData, 1, readData, 0, readData.Length);
            String data = Encoding.ASCII.GetString(readData);



            handlers.handleData(handlers.getHandlerType(byteData[0]), data, handler);

            buffer = new byte[BufferSize];

            handler.BeginReceive(buffer, 0, BufferSize, 0, new AsyncCallback(ReadCallback), handler);


        }
        else
        {
            handler.BeginReceive(buffer, 0, BufferSize, 0, new AsyncCallback(ReadCallback), handler);
        }
    }
    catch
    {
        Common common = new Common();
        common.appendLog("Error receiving data from " + handler.RemoteEndPoint);
    }

}

发送：从客户端发送

public void Send(String data, byte dataType)
{
    byte[] byteType = new byte[1];
    byteType[0] = dataType;

    int bufferSize = byteType.Length + Encoding.ASCII.GetBytes(data).Length;
    var ms = new MemoryStream(new byte[bufferSize], 0, bufferSize, true, true);
    ms.Write(byteType, 0, byteType.Length);
    ms.Write(Encoding.ASCII.GetBytes(data), 0, Encoding.ASCII.GetBytes(data).Length);

    byte[] byteData = ms.GetBuffer(); 

    sock.BeginSend(byteData, 0, byteData.Length, 0, new AsyncCallback(SendCallback), sock);
}

private static void SendCallback(IAsyncResult ar)
{
    try
    {
        Socket handler = (Socket)ar.AsyncState;
        int bytesSent = handler.EndSend(ar);
    }
    catch (Exception e)
    {
        MessageBox.Show(e.ToString());
    }
}