C# 从名称数组中随机选取的示例名称生成器

是否存在从名称数组中随机选择的linq随机选择器

 var randomname = {"Jess", "Jay", "Jen", "Jack", "Jan"}.select(a => a.random());

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简单，只需使用随机数生成器并对其进行排序：

Random rnd = new Random();
var randomname = {"Jess", "Jay", "Jen", "Jack", "Jan"}.OrderBy(a => rnd.NextDouble()).First();

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简单，只需使用随机数生成器并对其进行排序：

Random rnd = new Random();
var randomname = {"Jess", "Jay", "Jen", "Jack", "Jan"}.OrderBy(a => rnd.NextDouble()).First();

---

简单，只需使用随机数生成器并对其进行排序：

Random rnd = new Random();
var randomname = {"Jess", "Jay", "Jen", "Jack", "Jan"}.OrderBy(a => rnd.NextDouble()).First();

---

简单，只需使用随机数生成器并对其进行排序：

Random rnd = new Random();
var randomname = {"Jess", "Jay", "Jen", "Jack", "Jan"}.OrderBy(a => rnd.NextDouble()).First();

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这里不需要林克。只需使用上限和下限：

string[] items = { "Jess", "Jay", "Jen", "Jack", "Jan" };
Random r = new Random();

int index = r.Next(0, items.Length);
string randomItem = items[index];

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示例：

这里不需要LINQ。只需使用上限和下限：

string[] items = { "Jess", "Jay", "Jen", "Jack", "Jan" };
Random r = new Random();

int index = r.Next(0, items.Length);
string randomItem = items[index];

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示例：

这里不需要LINQ。只需使用上限和下限：

string[] items = { "Jess", "Jay", "Jen", "Jack", "Jan" };
Random r = new Random();

int index = r.Next(0, items.Length);
string randomItem = items[index];

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示例：

这里不需要LINQ。只需使用上限和下限：

string[] items = { "Jess", "Jay", "Jen", "Jack", "Jan" };
Random r = new Random();

int index = r.Next(0, items.Length);
string randomItem = items[index];

示例：

您可以使用.skip

Random rand = new Random();
int toSkip = rand.Next(0, randomname.Count  );
randomname.Skip(toSkip).Take(1).First(); //Or without linq a randomname[toSkipe];

你可以使用.skip

Random rand = new Random();
int toSkip = rand.Next(0, randomname.Count  );
randomname.Skip(toSkip).Take(1).First(); //Or without linq a randomname[toSkipe];

你可以使用.skip

Random rand = new Random();
int toSkip = rand.Next(0, randomname.Count  );
randomname.Skip(toSkip).Take(1).First(); //Or without linq a randomname[toSkipe];

你可以使用.skip

Random rand = new Random();
int toSkip = rand.Next(0, randomname.Count  );
randomname.Skip(toSkip).Take(1).First(); //Or without linq a randomname[toSkipe];