C# 使用RestSharp客户端反序列化嵌套JSON

C# 使用RestSharp客户端反序列化嵌套JSON,c#,json,deserialization,C#,Json,Deserialization,我想使用RESTAPI并反序列化嵌套的JSON响应。我使用json2csharp.com创建了这些类 JSON消费 { id: 32, name: "test supply object", formId: 4, sortOrder: 0, created: 1572902163907, creator: "jsingler", attributes: [ { id: 144, attribute: { attribut

我想使用RESTAPI并反序列化嵌套的JSON响应。我使用json2csharp.com创建了这些类

JSON消费

{
  id: 32,
  name: "test supply object",
  formId: 4,
  sortOrder: 0,
  created: 1572902163907,
  creator: "jsingler",
  attributes: [
    {
      id: 144,
      attribute: {
        attributeName: "Description",
        attributeType: "TextArea",
        id: 8
      },
      attributeValue: "for development testing. do not delete or use."
    },
    {
      id: 145,
      attribute: {
        attributeName: "Quantity",
        attributeType: "NumberLong",
        id: 10
      },
      attributeValue: "4"
    }
  ]
}
JSON2CSHARP.COM输出

public partial class Asset
{
    [JsonProperty(PropertyName = "id")]
    public int id { get; set; }
    [JsonProperty(PropertyName = "name")]
    public string name { get; set; }
    [JsonProperty(PropertyName = "formId")]
    public int formId { get; set; }
    [JsonProperty(PropertyName = "sortOrder")]
    public int sortOrder { get; set; }
    [JsonProperty(PropertyName = "created")]
    public long created { get; set; }
    [JsonProperty(PropertyName = "creator")]
    public string creator { get; set; }
    public List<Attribute> attributes { get; set; }
}

public partial class Attribute
{
    [JsonProperty(PropertyName = "ida")]
    public int id { get; set; }
    [JsonProperty(PropertyName = "attribute")]
    public List<Attribute1> attribute { get; set; }
    [JsonProperty(PropertyName = "attributeValue")]
    public string attributeValue { get; set; }
}

public partial class Attribute1
{
    [JsonProperty(PropertyName = "attributeName")]
    public string attributeName { get; set; }
    [JsonProperty(PropertyName = "attributeType")]
    public string attributeType { get; set; }
    [JsonProperty(PropertyName = "ida1")]
    public int id { get; set; }
}

这总是失败。

您的JSON无效。转到并检查所有错误


属性名称必须在引号之间,如果希望它是一个数组,则需要将其设置为一个数组,并在json的开头和结尾添加方括号-[]。

首先确保json有效。你可以看看这个 json属性必须在引号内,如下所示

“id”

除此之外,根对象不是列表。因此,您必须将反序列化代码更改为:

var AssetList = JsonConvert.DeserializeObject<Asset>(response.Content);
var AssetList=JsonConvert.DeserializeObject(response.Content);

您可以发布正在解析的实际JSON吗。样品看起来不错,谢谢。这很有帮助。我现在在格式化RestSharp Put语句时遇到问题。@AaronComstock很高兴听到这个消息。如果你能投票并签署正确的答案,如果它解决了你的问题,我会很高兴。JSON格式正确。我只是将Chrome渲染的示例JSON粘贴到更可读的格式中。
[HttpPut]
public void Send(Asset newJA, int Qty)
{
    var client = new RestClient("URL_TO_USE" + newJA.id + ".json");
    var request = new RestRequest("", Method.PUT);
    request.AddObject(newJA);

    client.Authenticator = new HttpBasicAuthenticator("USERNAME", "PW");
    client.ExecuteAsync(request, response => {
          Console.WriteLine(response.Content);
          Debug.WriteLine(response.Content);
     });
}
var AssetList = JsonConvert.DeserializeObject<Asset>(response.Content);