C# 使用HttpClient发布自定义类型
我有一个自定义dto类:C# 使用HttpClient发布自定义类型,c#,asp.net-web-api,dotnet-httpclient,C#,Asp.net Web Api,Dotnet Httpclient,我有一个自定义dto类: public class myObject { public string Id { get; set; } public string Name { get; set; } } 以及使用Web Api(4.5.net framework)的控制器 客户端只有4.0.net framework,因此我无法使用PostAsJsonAsync()方法。将对象从客户端传递到服务器的解决方案是什么 我试过以下方法: var response = Client.
public class myObject
{
public string Id { get; set; }
public string Name { get; set; }
}
以及使用Web Api(4.5.net framework)的控制器
客户端只有4.0.net framework,因此我无法使用PostAsJsonAsync()方法。将对象从客户端传递到服务器的解决方案是什么
我试过以下方法:
var response = Client.SendAsync(new HttpRequestMessage<myObject>(objectTest)).Result;
难道不能使用Newtonsoft.Json库吗?当然可以。只需像这样为自己创建一个新的HttpContent类
public class JsonContent : HttpContent
{
private readonly MemoryStream _Stream = new MemoryStream();
public JsonContent(object value)
{
var jw = new JsonTextWriter(new StreamWriter(_Stream)) {Formatting = Formatting.Indented};
var serializer = new JsonSerializer();
serializer.Serialize(jw, value);
jw.Flush();
_Stream.Position = 0;
}
protected override Task SerializeToStreamAsync(Stream stream, TransportContext context)
{
_Stream.CopyTo(stream);
var tcs = new TaskCompletionSource<object>();
tcs.SetResult(null);
return tcs.Task;
}
protected override bool TryComputeLength(out long length)
{
length = _Stream.Length;
return true;
}
}
创建一个继承自HttpContent的类,该类为您提供网络流,您可以直接向其写入而不使用memoryStream 大概是这样的:
using System;
using System.IO;
using System.Net;
using System.Net.Http;
using System.Text;
using System.Threading.Tasks;
using Newtonsoft.Json;
namespace Http.Helper.Extensions
{
public class JsonHttpContentSerializer : HttpContent
{
private object Value { get; set; }
public JsonHttpContentSerializer(Object value)
{
this.Value = value;
}
protected override async Task SerializeToStreamAsync(Stream stream, TransportContext context)
{
using (var streamWriter = new StreamWriter(stream, new UTF8Encoding(false), 1024, true))
{
using (var jsonTextWriter = new JsonTextWriter(streamWriter) { Formatting = Formatting.None })
{
var jsonSerializer = new JsonSerializer();
jsonSerializer.Serialize(jsonTextWriter, Value);
jsonTextWriter.Flush();
}
}
}
protected override bool TryComputeLength(out long length)
{
length = -1;
return false;
}
}
}
你会喜欢它吗
var jsonSerializeContent = new JsonHttpContentSerializer(someContent);
httpRequestMessage.Content = jsonSerializeContent;
谢谢你的解决方案。我不确定SerializeToStreamAsync做什么,TaskCompletionSource需要结果值的类型。是输入对象还是输出对象?@user1542666很抱歉,我不得不在运行中将if从.net45转换为4.0,并且忘记了
。SerializeToStream方法将在HttpClient需要时将缓冲流复制到网络流。为什么要使用缓冲流?我们可以利用网络流将对象直接写入其中?像这样的<代码>受保护的重写异步任务SerializeToStreamAsync(Stream,TransportContext上下文){StreamWriter=new StreamWriter(Stream,new UTF8Encoding(false));JsonTextWriter=new JsonTextWriter(StreamWriter){Formatting=Formatting.None};JsonSerializer.Serialize(JsonTextWriter,Value);//JsonTextWriter.Flush();}为什么不重写Dispose方法()?@jeevjyotsinghchabda是的,你可以。我通常习惯于使HttpContent类自包含。如果值对象在创建HttpContent对象之后但在写入网络之前发生更改,则有效负载将发生更改。但你的方法是100%有效的。我没有重载dispose,因为这个类没有分配非托管内存。
var content = new JsonContent(new YourObject());
var httpClient = new HttpClient();
var response = httpClient.PostAsync("http://example.org/somewhere", content);
using System;
using System.IO;
using System.Net;
using System.Net.Http;
using System.Text;
using System.Threading.Tasks;
using Newtonsoft.Json;
namespace Http.Helper.Extensions
{
public class JsonHttpContentSerializer : HttpContent
{
private object Value { get; set; }
public JsonHttpContentSerializer(Object value)
{
this.Value = value;
}
protected override async Task SerializeToStreamAsync(Stream stream, TransportContext context)
{
using (var streamWriter = new StreamWriter(stream, new UTF8Encoding(false), 1024, true))
{
using (var jsonTextWriter = new JsonTextWriter(streamWriter) { Formatting = Formatting.None })
{
var jsonSerializer = new JsonSerializer();
jsonSerializer.Serialize(jsonTextWriter, Value);
jsonTextWriter.Flush();
}
}
}
protected override bool TryComputeLength(out long length)
{
length = -1;
return false;
}
}
}
var jsonSerializeContent = new JsonHttpContentSerializer(someContent);
httpRequestMessage.Content = jsonSerializeContent;