获得下周的约会（C#）

我需要从表中获取数据，

Date

是从下周（从周一到周日）到今天的日期

以下是我如何获取今天和明天日期的数据：

 public JsonResult GetTodayList()
    {
        var items = db.Appointments.Where(x => x.Date == DateTime.Today)
            .Select(x => new
            {
                title = x.Title,
                time = x.Start_appointment

            }).ToList();

        return Json(items, JsonRequestBehavior.AllowGet);

    }

    public JsonResult GetTommorowList()
    {
        DateTime tommorow = DateTime.Today.AddDays(1);
        var items = db.Appointments.Where(x => x.Date == tommorow)
            .Select(x => new
            {
                title = x.Title,
                time = x.Start_appointment
            }).ToList();
        return Json(items, JsonRequestBehavior.AllowGet);
    }

---

如何获取下周日期的数据？

您可以尝试以下方法：

//first get next monday (thanks to this answer: https://stackoverflow.com/a/6346190/6170890 )
DateTime today = DateTime.Today;
int daysUntilMonday = ((int)DayOfWeek.Monday - (int)today.DayOfWeek + 7) % 7;
//if today is monday, add seven days
if (daysUntilMonday == 0)
    daysUntilMonday = 7;

//create DateTime variables for next week's beginning and end
DateTime nextWeekMonday = today.AddDays(daysUntilMonday);
DateTime nextWeekSunday = nextWeekMonday.AddDays(6);

//finally, do your select
var items = db.Appointments.Where(x => x.Date >= nextWeekMonday && x.Date <= nextWeekSunday)
.Select(x => new
{
    title = x.Title,
    time = x.Start_appointment
}).ToList();
return Json(items, JsonRequestBehavior.AllowGet);

//下周一第一次获取（多亏了这个答案：https://stackoverflow.com/a/6346190/6170890 )
DateTime today=DateTime.today；
int daysUntilMonday=（（int）DayOfWeek.Monday-（int）today.DayOfWeek+7）%7；
//如果今天是星期一，加上七天
如果（daysUntilMonday==0）
daysUntilMonday=7；
//为下周的开始和结束创建日期时间变量
DateTime nextWeekMonday=今天.AddDays（daysUntilMonday）；
DateTime nextWeekSunday=nextWeekMonday.AddDays（6）；
//最后，做你的选择
var items=db.appoints.Where（x=>x.Date>=nextWeekMonday&&x.datenew）
{
title=x.title，
时间=x.开始约会
}).ToList（）；
返回Json（items，JsonRequestBehavior.AllowGet）；

我在计算即将上映的电影的放映时间时遇到了类似的问题

以下内容用于计算到下一个所需开始日期的偏移量

public int CalculateOffset(DayOfWeek current, DayOfWeek desired) {
    // f( c, d ) = [7 - (c - d)] mod 7
    // f( c, d ) = [7 - c + d] mod 7
    // c is current day of week and 0 <= c < 7
    // d is desired day of the week and 0 <= d < 7
    int c = (int)current;
    int d = (int)desired;
    int offset = (7 - c + d) % 7;
    return offset == 0 ? 7 : offset;
}

---

然后，您可以根据计算的日期范围进行筛选。

使用dupe计算下一个星期一和下一个星期一的可能重复，然后调整where子句

where（x=>x.date>=nextMonday和x.date

DateTime today = DateTime.Today;
var currentDayOfWeek = today.DayOfWeek;
var desiredDayOfWeek = DayOfWeek.Monday; //Start of the week

int offset = CalculateOffset(currentDayOfWeek, desiredDayOfWeek);

var minDate = today.AddDays(offset); // Monday 12:00:00 AM 
var maxDate = minDate.AddDays(7).AddSeconds(-1); // Sunday 12:59:59 PM