C# WPF Datagrid两次显示列
通过将数据绑定到数据库列,我已经成功地在datagrid中显示了数据,但问题是,所有数据列在完全显示后出现了两次,即(id、user\u id、status、id、user\u id、status等)。如何摆脱这种情况,这是我的代码C# WPF Datagrid两次显示列,c#,wpf,linq,datagrid,C#,Wpf,Linq,Datagrid,通过将数据绑定到数据库列,我已经成功地在datagrid中显示了数据,但问题是,所有数据列在完全显示后出现了两次,即(id、user\u id、status、id、user\u id、status等)。如何摆脱这种情况,这是我的代码 <DataGrid x:Name="Grid_display" Grid.ColumnSpan="3" Margin="63,51,36,10" Grid.RowSpan="2"> <DataGrid.Columns
<DataGrid x:Name="Grid_display" Grid.ColumnSpan="3" Margin="63,51,36,10" Grid.RowSpan="2">
<DataGrid.Columns>
<DataGridTextColumn Header="ID" Binding="{Binding Path=id}"/>
<DataGridTextColumn Header="Publisher ID" Binding="{Binding Path=user_id}"/>
<DataGridTextColumn Header="Publication Title" Binding="{Binding Path=title}"/>
<DataGridTextColumn Header="Published Date of Document" Binding="{Binding Path=published_date}"/>
<DataGridTextColumn Header="File" Binding="{Binding Path=file}"/>
<DataGridTextColumn Header="Status" Binding="{Binding Path=status}"/>
</DataGrid.Columns>
</DataGrid>
private void display_btn_Click(object sender, RoutedEventArgs e)
{
List<publication> q = (from p in db.publications where p.user_id == get_id select p).ToList();
Grid_display.ItemsSource = q;
}
私有无效显示\u btn\u单击(对象发送方,路由目标)
{
列表q=(来自db.publications中的p,其中p.user_id==get_id选择p);
Grid_display.ItemsSource=q;
}
您必须在数据网格上设置AutoGenerateColumns=“False”
。默认情况下,它为true,并且正在添加另一组列
<DataGrid x:Name="Grid_display" Grid.ColumnSpan="3" AutoGenerateColumns="False"
Margin="63,51,36,10" Grid.RowSpan="2"/>
ya这应该是答案:)