C# 如何分割CSV文件

İN EXCEL

"0.0.0.0,""0.255.255.255"",""ZZ"""                
"1.0.0.0,""1.0.0.255"",""AU"""
"1.0.1.0,""1.0.3.255"",""CN"""
"1.0.4.0,""1.0.7.255"",""AU"""
"1.0.8.0,""1.0.15.255"",""CN"""
"1.0.16.0,""1.0.31.255"",""JP"""
"1.0.32.0,""1.0.63.255"",""CN"""
"1.0.64.0,""1.0.127.255"",""JP"""
"1.0.128.0,""1.0.255.255"",""TH"""
"1.1.0.0,""1.1.0.255"",""CN"""
"1.1.1.0,""1.1.1.255"",""AU"""
"1.1.2.0,""1.1.63.255"",""CN"""
"1.1.64.0,""1.1.127.255"",""JP"""
"1.1.128.0,""1.1.255.255"",""TH"""

如何拆分此CSV文件

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例如，第一行为0.0.0.0 0.255.255.255 ZZ，以及如何添加带有3列的datagridview。您可以通过以下方式执行此操作

0.0.0.0,"0.255.255.255","ZZ"
1.0.0.0,"1.0.0.255","AU"
1.0.1.0,"1.0.3.255","CN"
1.0.4.0,"1.0.7.255","AU"
1.0.8.0,"1.0.15.255","CN"
1.0.16.0,"1.0.31.255","JP"
1.0.32.0,"1.0.63.255","CN"
1.0.64.0,"1.0.127.255","JP"
1.0.128.0,"1.0.255.255","TH"
1.1.0.0,"1.1.0.255","CN"
1.1.1.0,"1.1.1.255","AU"
1.1.2.0,"1.1.63.255","CN"
1.1.64.0,"1.1.127.255","JP"
1.1.128.0,"1.1.255.255","TH"
1.2.0.0,"1.2.2.255","CN"
1.2.3.0,"1.2.3.255","AU"
1.2.4.0,"1.2.127.255","CN"
1.2.128.0,"1.2.255.255","TH"
1.3.0.0,"1.3.255.255","CN"
1.4.0.0,"1.4.0.255","AU"
1.4.1.0,"1.4.127.255","CN"
1.4.128.0,"1.4.255.255","TH"

CSV文件可以是制表符分隔的文件，也可以是逗号分隔的文件。也就是说；您必须逐行读取文件，然后根据分隔符分隔行中的可用值。CSV文件中通常出现的第一行通常是标题，您可以使用这些标题生成键值对，以提高收集效率。例如：

using System.IO;
static void Main(string[] args)
{
    using(var reader = new StreamReader(@"C:\test.csv"))
    {
        List<string> listA = new List<string>();
        List<string> listB = new List<string>();
        while (!reader.EndOfStream)
        {
            var line = reader.ReadLine();
            var values = line.Split(','); // or whatever yur get by reading that file

            listA.Add(values[0]);
            listB.Add(values[1]);
        }
    }
}

---

如果CSV的数据结构是恒定的，并且将来不会更改，则可以开发强类型数据模型并去掉字典类型。这种方法将更加优雅和高效

首先，您的CSV行被引号包围。是复制/粘贴错误吗？如果没有，则需要将文件清理为有效的CSV文件

您可以尝试使用开源库将CSV文件加载到datatable，然后将其分配给DataGridView源

我会告诉你们两个方法，如何处理

有效CSV:test.CSV

阅读CSV：

下一个方法

无效的CSV:test.CSV

阅读CSV：

---

希望能有所帮助。

到目前为止您尝试了什么？顺便说一句，它可能是csv的副本，而不是使用专用的csv阅读器，例如，这不是一个有效的CSV。你应该解释一下你的答案，让它成为一个好答案。当字符串值中有一个r\n时，你可以在中间砍掉一个记录。使用制表符作为分隔符的类似结构文本文件不是CSV。@PepitoSh：在数据挖掘项目中，有时逗号分隔的CSV很麻烦，所以我们选择制表符分隔的CSV。这就是我提到它的原因。你不应该用逗号分隔你读到的行。可以拆分包含逗号的字符串值。此外，您还可以读取部分记录，\r\n因为它可能是字符串值的一部分。解析CSV有点复杂。@PepitoSh：您可以拆分一个包含逗号的字符串值，为什么？它是由“，”分隔的行，而不是单个记录！否。CSV中的列用逗号分隔。请参阅规范：我同意，制表符可以用作分隔符：

 Dictionary<int, Dictionary<String, String>> values = new Dictionary<int, Dictionary<String,String>>();
 using(FileStream fileStream = new FileStream(@"D:\MyCSV.csv", FileMode.Open, FileAccess.Read, FileShare.Read)) {
     using(StreamReader streamReader = new StreamReader(fileStream)){
          //You can skip this line if there is no header
          // Then instead of Dictionary<String,String> you use List<String>
          var headers = streamReader.ReadLine().Split(',');
          String line = null;
          int lineNumber = 1;
          while(!streamReader.EndOfStream){
               line = streamReader.ReadLine().split(',');
               if(line.Length == headers.Length){
                   var temp = new Dictionary<String, String>();
                   for(int i = 0; i < headers.Length; i++){
                      // You can remove '"' character by line[i].Replace("\"", "") or through using the Substring method
                      temp.Add(headers[i], line[i]);
                   }
                   values.Add(lineNumber, temp);
               }
               lineNumber++;
          }              
     }

0.0.0.0,"0.255.255.255","ZZ"
1.0.0.0,"1.0.0.255","AU"
1.0.1.0,"1.0.3.255","CN"
1.0.4.0,"1.0.7.255","AU"
1.0.8.0,"1.0.15.255","CN"
1.0.16.0,"1.0.31.255","JP"
1.0.32.0,"1.0.63.255","CN"
1.0.64.0,"1.0.127.255","JP"
1.0.128.0,"1.0.255.255","TH"
1.1.0.0,"1.1.0.255","CN"
1.1.1.0,"1.1.1.255","AU"
1.1.2.0,"1.1.63.255","CN"
1.1.64.0,"1.1.127.255","JP"
1.1.128.0,"1.1.255.255","TH"

using (var p = new ChoCSVReader("test.csv"))
{
    var dt = p.AsDataTable();
    //Assign dt to DataGridView
}

"0.0.0.0,""0.255.255.255"",""ZZ"""
"1.0.0.0,""1.0.0.255"",""AU"""
"1.0.1.0,""1.0.3.255"",""CN"""
"1.0.4.0,""1.0.7.255"",""AU"""
"1.0.8.0,""1.0.15.255"",""CN"""
"1.0.16.0,""1.0.31.255"",""JP"""
"1.0.32.0,""1.0.63.255"",""CN"""
"1.0.64.0,""1.0.127.255"",""JP"""
"1.0.128.0,""1.0.255.255"",""TH"""
"1.1.0.0,""1.1.0.255"",""CN"""
"1.1.1.0,""1.1.1.255"",""AU"""
"1.1.2.0,""1.1.63.255"",""CN"""
"1.1.64.0,""1.1.127.255"",""JP"""
"1.1.128.0,""1.1.255.255"",""TH"""

using (var p = new ChoCSVReader("Sample6.csv"))
{
    p.SanitizeLine += (o, e) =>
    {
        string line = e.Line as string;
        if (line != null)
        {
            line = line.Substring(1, line.Length - 2);
            line = line.Replace(@"""""", @"""");
        }

        e.Line - line;
    };

    var dt = p.AsDataTable();
    //Assign dt to DataGridView
}