C# 通过反射C获取嵌套的属性值#
我有以下代码 课程:C# 通过反射C获取嵌套的属性值#,c#,reflection,C#,Reflection,我有以下代码 课程: public class AlloyDock { public int Left { get; set; } public int Right { get; set; } } public class Charger { public int Left { get; set; } public int Right { get; set; } } public class VehicleControlTest { public Cha
public class AlloyDock
{
public int Left { get; set; }
public int Right { get; set; }
}
public class Charger
{
public int Left { get; set; }
public int Right { get; set; }
}
public class VehicleControlTest
{
public Charger Charger1 { get; set; }
}
public class BasicControlTest
{
public AlloyDock AlloyDock1 { get; set; }
}
class Appointment
{
public BasicControlTest BasicControlTest1 { get; set; }
public VehicleControlTest VehicleControlTest1 { get; set; }
}
var obj = new Appointment();
obj.BasicControlTest1 = new BasicControlTest();
obj.BasicControlTest1.AlloyDock1 = new AlloyDock();
obj.BasicControlTest1.AlloyDock1.Left = 1;
obj.BasicControlTest1.AlloyDock1.Right = 2;
obj.VehicleControlTest1 = new VehicleControlTest();
obj.VehicleControlTest1.Charger1 = new Charger();
obj.VehicleControlTest1.Charger1.Left = 3;
obj.VehicleControlTest1.Charger1.Right = 4;
var parentProperties = obj.GetType().GetProperties();
foreach (var prop in parentProperties)
{
// Get Main objects inside each test type.
var mainObjectsProperties = prop.PropertyType.GetProperties();
foreach (var property in mainObjectsProperties)
{
var leafProperties = property.PropertyType.GetProperties();
foreach (var leafProperty in leafProperties)
{
Console.WriteLine("{0}={1}", leafProperty.Name, leafProperty.GetValue(obj, null));
}
}
}
主要功能:
public class AlloyDock
{
public int Left { get; set; }
public int Right { get; set; }
}
public class Charger
{
public int Left { get; set; }
public int Right { get; set; }
}
public class VehicleControlTest
{
public Charger Charger1 { get; set; }
}
public class BasicControlTest
{
public AlloyDock AlloyDock1 { get; set; }
}
class Appointment
{
public BasicControlTest BasicControlTest1 { get; set; }
public VehicleControlTest VehicleControlTest1 { get; set; }
}
var obj = new Appointment();
obj.BasicControlTest1 = new BasicControlTest();
obj.BasicControlTest1.AlloyDock1 = new AlloyDock();
obj.BasicControlTest1.AlloyDock1.Left = 1;
obj.BasicControlTest1.AlloyDock1.Right = 2;
obj.VehicleControlTest1 = new VehicleControlTest();
obj.VehicleControlTest1.Charger1 = new Charger();
obj.VehicleControlTest1.Charger1.Left = 3;
obj.VehicleControlTest1.Charger1.Right = 4;
var parentProperties = obj.GetType().GetProperties();
foreach (var prop in parentProperties)
{
// Get Main objects inside each test type.
var mainObjectsProperties = prop.PropertyType.GetProperties();
foreach (var property in mainObjectsProperties)
{
var leafProperties = property.PropertyType.GetProperties();
foreach (var leafProperty in leafProperties)
{
Console.WriteLine("{0}={1}", leafProperty.Name, leafProperty.GetValue(obj, null));
}
}
}
我想获取叶节点的属性名和值。我可以得到name,但当我试图得到value时(分别是1,2,3,4)。我正在犯错误
对象与目标类型不匹配。
我只是拼命想解决这个问题。
有人能帮我吗。这个表达式有问题:
leafProperty.GetValue(obj, null)
您正在传入根对象以获取叶属性。处理每个属性时,需要获取其值,然后对其调用
GetValue
。将对象实例传递给GetValue
方法时,需要传递正确类型的实例:
// 1st level properties
var parentProperties = obj.GetType().GetProperties();
foreach (var prop in parentProperties)
{
// get the actual instance of this property
var propertyInstance = prop.GetValue(obj, null);
// get 2nd level properties
var mainObjectsProperties = prop.PropertyType.GetProperties();
foreach (var property in mainObjectsProperties)
{
// get the actual instance of this 2nd level property
var leafInstance = property.GetValue(propertyInstance, null);
// 3rd level props
var leafProperties = property.PropertyType.GetProperties();
foreach (var leafProperty in leafProperties)
{
Console.WriteLine("{0}={1}",
leafProperty.Name, leafProperty.GetValue(leafInstance, null));
}
}
}
您可以递归地执行此操作以简化(概括)整个过程:
static void DumpObjectTree(object propValue, int level = 0)
{
if (propValue == null)
return;
var childProps = propValue.GetType().GetProperties();
foreach (var prop in childProps)
{
var name = prop.Name;
var value = prop.GetValue(propValue, null);
// add some left padding to make it look like a tree
Console.WriteLine("".PadLeft(level * 4, ' ') + "{0}={1}", name, value);
// call again for the child property
DumpObjectTree(value, level + 1);
}
}
// usage: DumpObjectTree(obj);
您正在将父对象实例传递给叶属性信息获取程序。为什么需要反射?请指导我。“怎么做”?我不习惯思考API@BeelalAhmed-看看格罗的答案。谢谢。像charm一样工作:)@Beelal:另外,如果你不想硬编码树深度,我建议使用下面的递归方法。我会看看它。请告诉我如何在Windows Universal Application中这样做,因为它没有GetProperties()方法。