C# 使用正则表达式查找点

我有六个点

1: ([37.788353, -122.387695], [37.829853, -122.294312]) 2: ([37.429615, -122.087631], [37.487391, -122.018967]) 3: ([37.474858, -122.131577], [37.529332, -122.056046]) 4: ([37.532599,-122.218094], [37.615863,-122.097244]) 5: ([37.516262,-122.198181], [37.653383,-122.151489]) 6: ([37.504824,-122.181702], [37.633266,-122.121964])

我想通过正则表达式提取它们

(\d+:\s([\d+.\d+,\s-*\d+.\d+],\s[\d+.\d+,\s-*\d+.\d+]))

但它不起作用。任何帮助都将不胜感激。我可以使用组在列表中放置点

预期结果：

[37.788353, -122.387695], [37.829853, -122.294312]
[37.429615, -122.087631], [37.487391, -122.018967]
 ....

给你：

\[[\d-.]+[, ]+[\d-.]+\][, ]+\[[\d-.]+[, ]+[\d-.]+\]

[\d-.]匹配任何数字，并允许使用减号和小数（如果存在） [，]检查x和y坐标之间是否有逗号和空格 输出将按您希望的方式提取点，例如[37.788353，-122.387695]，[37.829853，-122.294312]作为第一个点，依此类推

注意：如果您想单独提取数字，您可以使用捕获组，如下所示

\[([\d-.]+)[, ]+([\d-.]+)\][, ]+\[([\d-.]+)[, ]+([\d-.]+)\]

假设点的格式为x1、y1、x2、y2，则 -$1或第一个捕获组将具有x1点37.788353 -$2或下一组为y1-122.387695 -$3或下一组将有x2 37.829853 -$4或下一组为y2-122.294312

包括捕获组

:

---

它不起作用的原因是你没有逃走，[]。这些在正则表达式语言中具有特殊意义

此外，还有一个错误-您没有将*用于“，”之后的空格，因此只有前3项匹配

以下解决了这些问题：

(\d+\:\s\(\[\d+.\d+,\s*-*\d+.\d+\],\s\[\d+.\d+,\s*-*\d+.\d+\]\))

---

您可以使用更简单的正则表达式来提取成对的值：

\[(?<first>[-\d.]+)\s*,\s*(?<second>[-\d.]+)]

输出：

[37.788353, -122.387695]
[37.829853, -122.294312]
[37.429615, -122.087631]
[37.487391, -122.018967]
[37.474858, -122.131577]
[37.529332, -122.056046]
[37.532599, -122.218094]
[37.615863, -122.097244]
[37.516262, -122.198181]
[37.653383, -122.151489]
[37.504824, -122.181702]
[37.633266, -122.121964]

---

您试图以什么格式获取输出？您可以使用。提供一个预期输出的示例。您可以使用正则表达式，但只解析JSON并获取值[并]生成一个字符类更为合理。所以你的意思是我必须将escape添加到或[。@Bigeyes看看这个演示：。答案中包含了代码

var pat = @"\[(?<first>[-\d.]+)\s*,\s*(?<second>[-\d.]+)]";
var s = "1: ([37.788353, -122.387695], [37.829853, -122.294312]) 2: ([37.429615, -122.087631], [37.487391, -122.018967]) 3: ([37.474858, -122.131577], [37.529332, -122.056046]) 4: ([37.532599,-122.218094], [37.615863,-122.097244]) 5: ([37.516262,-122.198181], [37.653383,-122.151489]) 6: ([37.504824,-122.181702], [37.633266,-122.121964])";
var res = Regex.Matches(s, pat)
        .Cast<Match>()
        .Select(m => new[] { m.Groups["first"].Value, m.Groups["second"].Value } );
foreach (var str in res)
{
    Console.WriteLine("[{0}, {1}]", str[0], str[1]);
}

[37.788353, -122.387695]
[37.829853, -122.294312]
[37.429615, -122.087631]
[37.487391, -122.018967]
[37.474858, -122.131577]
[37.529332, -122.056046]
[37.532599, -122.218094]
[37.615863, -122.097244]
[37.516262, -122.198181]
[37.653383, -122.151489]
[37.504824, -122.181702]
[37.633266, -122.121964]