C# 从类传递值以在不同的窗体上显示&是否以编程方式单击事件处理？

我目前创建了一个棋盘，上面有棋子的图像，并给棋盘上色，等等。我有两个关于点击事件方法的问题，我希望你能帮我解决？单击正方形时，我的当前方法会更改sqaure颜色，并显示一个消息框，显示xy坐标和工件类型，如果工件未占用坐标，则仅显示坐标：

问题1：如果我再次单击相同的sqaure或不同的sqaure，如何使颜色恢复到原来的颜色

问题2：如何在文本框或标签中显示Form1.cs上的信息，而不是显示meesagebox

以下是我在GridSqaure.cs类中的代码：

namespace Chess
{
    public class GridSquare : PictureBox
    {
        private int x;
        private int y;

        private ChessPiece piece;

        public int X { get { return x; } }
        public int Y { get { return y; } }

        public ChessPiece Piece 
        {
            get { return piece; }
            set 
            {
                piece = value;
                if (value == null)
                    this.BackgroundImage = null;
                else
                    this.BackgroundImage = piece.GetImage();
            }
        }

        public GridSquare(int x, int y)
        {
            int ButtonWidth = 64;
            int ButtonHeight = 64;
            int Distance = 20;
            int start_x = 10;
            int start_y = 10;

            this.x = x;
            this.y = y;

            this.Top = start_x + (x * ButtonHeight + Distance + x);
            this.Left = start_y + (y * ButtonWidth + Distance + y);
            this.Width = ButtonWidth;
            this.Height = ButtonHeight;
            this.Text = "X: " + x.ToString() + " Y: " + y.ToString();

            this.BorderStyle = System.Windows.Forms.BorderStyle.FixedSingle;

            this.Click += new System.EventHandler(gridSquare_Click);
        }

        private void gridSquare_Click(object sender, EventArgs e)
        {
            GridSquare gs = (GridSquare)sender;
            if (gs.Piece != null)
                {
                    //Change: need to show xy of sqaure clicked on a label or textbox on the main window.
                MessageBox.Show("You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")");

                //Change: need to click for change in colour, then second click to revert back
                this.BackColor = Color.LightBlue;
                } 
            else
                {
                    //Change: need to show xy of clicked square but including meesage stating the sqaure needs to be occupied by a piece.
                    MessageBox.Show("You clicked (" + gs.X + ", " + gs.Y + ")");
                }
        }
    }
}

---

首先将长方体的实际颜色存储在color类的对象中，假设对象名为BoxColor，现在查看以下代码

if (gs.Piece != null) 
{      
    //Change: need to show xy of sqaure clicked on a label or textbox on the main window.       
    label1.Text = "You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")";       
   //Change: need to click for change in colour, then second click to revert back           
  this.BackColor = Color.LightBlue;  
}        
else         
{             
    //Change: need to show xy of clicked square but including meesage stating the sqaure needs to be occupied by a piece.   
     this.BackColor = BoxColor //setting back the original color if the box is clicked again.
     label1.Text = "You clicked (" + gs.X + ", " + gs.Y + ")";     
} 

---

并且，仅当框的颜色与实际颜色发生变化时，才使用一个布尔变量启用它。现在，如果用户单击任何其他框，则检查这些标志，如果其为真，则重置颜色。

首先将框的实际颜色存储在颜色类的对象中，假设对象名为BoxColor，现在可以看到以下代码

if (gs.Piece != null) 
{      
    //Change: need to show xy of sqaure clicked on a label or textbox on the main window.       
    label1.Text = "You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")";       
   //Change: need to click for change in colour, then second click to revert back           
  this.BackColor = Color.LightBlue;  
}        
else         
{             
    //Change: need to show xy of clicked square but including meesage stating the sqaure needs to be occupied by a piece.   
     this.BackColor = BoxColor //setting back the original color if the box is clicked again.
     label1.Text = "You clicked (" + gs.X + ", " + gs.Y + ")";     
} 

并且只在框的颜色与实际颜色发生变化时才启用一个布尔变量，现在如果用户单击任何其他框，则选中这些标志，如果其为真，则重置颜色

可以在类GridSquare的作用域上创建布尔变量。然后在gridSquare上使用此变量，单击事件处理程序，如下所示：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

只需使用标签或文本框的文本属性

可以在类GridSquare的作用域上创建布尔变量。然后在gridSquare上使用此变量，单击事件处理程序，如下所示：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

只需使用标签或文本框的文本属性

---

我会避免让一个类处理它自己的事件。这不是一个好的做法

相反，我会使用回调策略

首先，像这样重新编码GridSquare：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

现在您只需要定义clicked（单击每个GridSquare时的回调），代码如下所示：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

很明显，这段代码在创建网格正方形之前就开始了

这应该是比较容易理解的，但如果没有，请提问，我会详细说明

---

让我知道这是否适合您。

我会避免让类处理自己的事件。这不是一个好的做法

相反，我会使用回调策略

首先，像这样重新编码GridSquare：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

现在您只需要定义clicked（单击每个GridSquare时的回调），代码如下所示：

public class GridSquare : PictureBox
{
   bool isFirstClick = true;
   .....
   .....
   .....
   private void gridSquare_Click(object sender, EventArgs e)
    {
           if(isFirstClick)
           {
               isFirstClick = false; 
               //Set one color
            }
           else
           {
               isFirstClick = true;
               //Set other color
           } 
     } 
}

public class GridSquare : PictureBox
{
    /* As before */

    public GridSquare(int x, int y, Action<GridSquare> clicked)
    {
        /* As before */
        this.Click += (s, e) => clicked(this);
    }

    /* NO private void gridSquare_Click(object sender, EventArgs e) */
}

for (var x = 0; x < 8; x++)
{
    for (var y = 0; y < 8; y++)
    {
        this.Controls.Add(new GridSquare(x, y, clicked));
    }
}

GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;

Action<GridSquare> clicked = gs =>
{
    lastClicked.BackColor = lastBackColor;
    if (!lastClicked.Equals(gs))
    {
        lastClicked = gs;
        lastBackColor = gs.BackColor;
        gs.BackColor = Color.LightBlue;
        var inner = gs.Piece != null
            ? String.Format("a {0} at ", gs.Piece.GetName())
            : "";
        var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
        MessageBox.Show(msg);
    }
};

很明显，这段代码在创建网格正方形之前就开始了

这应该是比较容易理解的，但如果没有，请提问，我会详细说明

---

让我知道这是否适用于您。

这是我将原始代码添加到的内容：

namespace Chess
{
public class GridSquare : PictureBox
{
    private int x;
    private int y;

    private static GridSquare lastClicked;
    private static ChessBoard board;

    private ChessPiece piece;

    public int X { get { return x; } }
    public int Y { get { return y; } }
    public static ChessBoard Board { set { board = value; } }

    Color LightTile = Color.Beige;
    Color DarkTile = Color.SandyBrown;

    public ChessPiece Piece 
    {
        get { return piece; }
        set 
        {
            piece = value;
            if (value == null)
                this.BackgroundImage = null;
            else
                this.BackgroundImage = piece.GetImage();
        }
    }

    public GridSquare(int x, int y)
    {
        int ButtonWidth = 64;
        int ButtonHeight = 64;
        int Distance = 20;
        int start_x = 10;
        int start_y = 10;

        this.x = x;
        this.y = y;

        this.Top = start_x + (x * ButtonHeight + Distance + x);
        this.Left = start_y + (y * ButtonWidth + Distance + y);
        this.Width = ButtonWidth;
        this.Height = ButtonHeight;
        this.Text = "X: " + x.ToString() + " Y: " + y.ToString();

        this.BorderStyle = System.Windows.Forms.BorderStyle.FixedSingle;

        this.Click += new System.EventHandler(gridSquare_Click);
    }

    private void gridSquare_Click(object sender, EventArgs e)
    {
        GridSquare gs = (GridSquare)sender;

        if (lastClicked != null)
            lastClicked.ResetColour();

        //Change: need to click for change in colour, then second click to revert back
        this.BackColor = Color.LightBlue;
        lastClicked = this;

        if (gs.Piece != null)
        {
            board.StatusLabel.Text = "You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")";
        }
        else
        {
            board.StatusLabel.Text = "You clicked (" + gs.X + ", " + gs.Y + ")";
        }
    }

    public void ResetColour()
    {
        if (x % 2 == 0)
            if (y % 2 == 0)
                // If x=Even y=Even
                this.BackColor = LightTile;
            else
                // If x=Even y=Odd
                this.BackColor = DarkTile;
        else
            if (y % 2 == 0)
                // If x=Odd y=Even
                this.BackColor = DarkTile;
            else
                // If x=Odd y=Odd
                this.BackColor = LightTile;
    }
}

---

}

这是我将原始代码添加到的内容：

namespace Chess
{
public class GridSquare : PictureBox
{
    private int x;
    private int y;

    private static GridSquare lastClicked;
    private static ChessBoard board;

    private ChessPiece piece;

    public int X { get { return x; } }
    public int Y { get { return y; } }
    public static ChessBoard Board { set { board = value; } }

    Color LightTile = Color.Beige;
    Color DarkTile = Color.SandyBrown;

    public ChessPiece Piece 
    {
        get { return piece; }
        set 
        {
            piece = value;
            if (value == null)
                this.BackgroundImage = null;
            else
                this.BackgroundImage = piece.GetImage();
        }
    }

    public GridSquare(int x, int y)
    {
        int ButtonWidth = 64;
        int ButtonHeight = 64;
        int Distance = 20;
        int start_x = 10;
        int start_y = 10;

        this.x = x;
        this.y = y;

        this.Top = start_x + (x * ButtonHeight + Distance + x);
        this.Left = start_y + (y * ButtonWidth + Distance + y);
        this.Width = ButtonWidth;
        this.Height = ButtonHeight;
        this.Text = "X: " + x.ToString() + " Y: " + y.ToString();

        this.BorderStyle = System.Windows.Forms.BorderStyle.FixedSingle;

        this.Click += new System.EventHandler(gridSquare_Click);
    }

    private void gridSquare_Click(object sender, EventArgs e)
    {
        GridSquare gs = (GridSquare)sender;

        if (lastClicked != null)
            lastClicked.ResetColour();

        //Change: need to click for change in colour, then second click to revert back
        this.BackColor = Color.LightBlue;
        lastClicked = this;

        if (gs.Piece != null)
        {
            board.StatusLabel.Text = "You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")";
        }
        else
        {
            board.StatusLabel.Text = "You clicked (" + gs.X + ", " + gs.Y + ")";
        }
    }

    public void ResetColour()
    {
        if (x % 2 == 0)
            if (y % 2 == 0)
                // If x=Even y=Even
                this.BackColor = LightTile;
            else
                // If x=Even y=Odd
                this.BackColor = DarkTile;
        else
            if (y % 2 == 0)
                // If x=Odd y=Even
                this.BackColor = DarkTile;
            else
                // If x=Odd y=Odd
                this.BackColor = LightTile;
    }
}

---

}

我只是想了解一下，我遵循了您的逻辑，但是我发现了两个错误，第一个是您的初始代码集，最后一行显示了一个错误“clicked”名称在当前上下文中不存在。其次，从第二组代码中，它给出了一个错误chess.gridSqaure不包含接受3个参数的构造函数。@Rg786-听起来您没有从我的代码中正确复制“GridSquare”构造函数签名。它应该是“publicGridSquareIntX，IntY，ActionClicked”。我想我可能把自己弄糊涂了，我重新思考了一下，并在“GridSquareR”中添加了一个名为resetColor的方法。然后在click方法中添加了一个If语句，该语句包含resetcolor。看起来很好用。至于标签，我也重新考虑了一下，选择了ToolStripStatusLabel，它也很好用。。。到目前为止……我只是想了解一下，我遵循了你的逻辑，但是我得到了两个错误，第一个是从你的初始代码集中得到的，最后一行显示了一个错误“clicked”这个名称在当前上下文中不存在。其次，从第二组代码中，它给出了一个错误chess.gridSqaure不包含接受3个参数的构造函数。@Rg786-听起来您没有从我的代码中正确复制“GridSquare”构造函数签名。它应该是“publicGridSquareIntX，IntY，ActionClicked”。我想我可能把自己弄糊涂了，我重新思考了一下，并在“GridSquareR”中添加了一个名为resetColor的方法。然后在click方法中添加了一个If语句，该语句包含resetcolor。看起来很好用。至于标签，我也重新考虑了一下，选择了ToolStripStatusLabel，它也很好用。。。到目前为止……@Kvn-感谢您的投入，您的方式确实让我想到了其他方法来获得我所做的。请参阅第一个响应。@Kvn-感谢您的输入，您的方式确实让我想到了o

---

f获得我所做的事情的其他方法。请参阅第一个回复。谢谢，您的回复给了我一个在代码中设置颜色的想法。请参阅第一个响应代码谢谢，您的响应给了我一个在代码中设置颜色的想法。请参阅第一个响应代码