C# 数组。使用数字对字符串进行排序
我有以下示例代码:C# 数组。使用数字对字符串进行排序,c#,C#,我有以下示例代码: List<string> test = new List<string>(); test.Add("Hello2"); test.Add("Hello1"); test.Add("Welcome2"); test.Add("World"); test.Add("Hello11"); test.Add("Hello10"); test.Add("Welcome0"); test.Add("World3"); test.Add("Hello100"); t
List<string> test = new List<string>();
test.Add("Hello2");
test.Add("Hello1");
test.Add("Welcome2");
test.Add("World");
test.Add("Hello11");
test.Add("Hello10");
test.Add("Welcome0");
test.Add("World3");
test.Add("Hello100");
test.Add("Hello20");
test.Add("Hello3");
test.Sort();
有没有办法对它们进行排序,以便字符串也具有正确的数字顺序?
如果字符串末尾没有数字,则该字符串将始终位于第一位-在字母顺序之后
预期产出:
"Hello1",
"Hello2",
"Hello3",
"Hello10",
"Hello11",
"Hello20",
"Hello100",
"Welcome0",
"Welcome2",
"World",
"World3"
以下是使用LINQ的一种可能方法:
var orderedList = test
.OrderBy(x => new string(x.Where(char.IsLetter).ToArray()))
.ThenBy(x =>
{
int number;
if (int.TryParse(new string(x.Where(char.IsDigit).ToArray()), out number))
return number;
return -1;
}).ToList();
您可以将LINQ与正则表达式结合使用,以确保只使用字符串末尾的数字进行二次排序
test
.Select(t => new{match = Regex.Match(t, @"\d+$"), val = t})
.Select(x => new{sortVal = x.match.Success
?int.Parse(x.match.Value)
:-1,
val = x.val})
.OrderBy(x => x.val)
.ThenBy(x => x.sortVal)
.Select(x => x.val)
.ToList()
创建一个IComparer实现。与LINQ建议相比,这种方式的优势在于,您现在有了一个类,它可以传递给任何需要以这种方式排序的对象,而不是在其他位置重新创建LINQ查询
这是特定于从列表中调用排序的。如果要将其称为Array.Sort,请参阅版本2:
列表版本:
public class AlphaNumericComparer : IComparer<string>
{
public int Compare(string lhs, string rhs)
{
if (lhs == null)
{
return 0;
}
if (rhs == null)
{
return 0;
}
var s1Length = lhs.Length;
var s2Length = rhs.Length;
var s1Marker = 0;
var s2Marker = 0;
// Walk through two the strings with two markers.
while (s1Marker < s1Length && s2Marker < s2Length)
{
var ch1 = lhs[s1Marker];
var ch2 = rhs[s2Marker];
var s1Buffer = new char[s1Length];
var loc1 = 0;
var s2Buffer = new char[s2Length];
var loc2 = 0;
// Walk through all following characters that are digits or
// characters in BOTH strings starting at the appropriate marker.
// Collect char arrays.
do
{
s1Buffer[loc1++] = ch1;
s1Marker++;
if (s1Marker < s1Length)
{
ch1 = lhs[s1Marker];
}
else
{
break;
}
} while (char.IsDigit(ch1) == char.IsDigit(s1Buffer[0]));
do
{
s2Buffer[loc2++] = ch2;
s2Marker++;
if (s2Marker < s2Length)
{
ch2 = rhs[s2Marker];
}
else
{
break;
}
} while (char.IsDigit(ch2) == char.IsDigit(s2Buffer[0]));
// If we have collected numbers, compare them numerically.
// Otherwise, if we have strings, compare them alphabetically.
string str1 = new string(s1Buffer);
string str2 = new string(s2Buffer);
int result;
if (char.IsDigit(s1Buffer[0]) && char.IsDigit(s2Buffer[0]))
{
var thisNumericChunk = int.Parse(str1);
var thatNumericChunk = int.Parse(str2);
result = thisNumericChunk.CompareTo(thatNumericChunk);
}
else
{
result = str1.CompareTo(str2);
}
if (result != 0)
{
return result;
}
}
return s1Length - s2Length;
}
}
Array.sort版本:
创建类:
public class AlphaNumericComparer : IComparer
{
public int Compare(object x, object y)
{
string s1 = x as string;
if (s1 == null)
{
return 0;
}
string s2 = y as string;
if (s2 == null)
{
return 0;
}
int len1 = s1.Length;
int len2 = s2.Length;
int marker1 = 0;
int marker2 = 0;
// Walk through two the strings with two markers.
while (marker1 < len1 && marker2 < len2)
{
var ch1 = s1[marker1];
var ch2 = s2[marker2];
// Some buffers we can build up characters in for each chunk.
var space1 = new char[len1];
var loc1 = 0;
var space2 = new char[len2];
var loc2 = 0;
// Walk through all following characters that are digits or
// characters in BOTH strings starting at the appropriate marker.
// Collect char arrays.
do
{
space1[loc1++] = ch1;
marker1++;
if (marker1 < len1)
{
ch1 = s1[marker1];
}
else
{
break;
}
} while (char.IsDigit(ch1) == char.IsDigit(space1[0]));
do
{
space2[loc2++] = ch2;
marker2++;
if (marker2 < len2)
{
ch2 = s2[marker2];
}
else
{
break;
}
} while (char.IsDigit(ch2) == char.IsDigit(space2[0]));
// If we have collected numbers, compare them numerically.
// Otherwise, if we have strings, compare them alphabetically.
var str1 = new string(space1);
var str2 = new string(space2);
var result = 0;
if (char.IsDigit(space1[0]) && char.IsDigit(space2[0]))
{
var thisNumericChunk = int.Parse(str1);
var thatNumericChunk = int.Parse(str2);
result = thisNumericChunk.CompareTo(thatNumericChunk);
}
else
{
result = str1.CompareTo(str2);
}
if (result != 0)
{
return result;
}
}
return len1 - len2;
}
}
Call like so:
This time test is an array instead of a list.
Array.sort(test, new AlphaNumericComparer())
只是随口说说而已,但如果你想让Hello1排在Hello10之前,最好先注入一个0,这样它就会是Hello01、Hello02等。Windows资源管理器按字母顺序对文件和文件夹进行排序时,也会采用相同的方式。可能需要查看字符串的最后2个字符,确定它们是否都是数字,如果不是,则以0开头。@sab669我不允许更改原始数据,它们对整个应用程序极为敏感。@C.J.您的欢迎。请注意,如果字符串开头或字母之间包含数字,则此操作将无法按预期进行。仅当所有字母后面都是数字时,此操作才有效。如果你想处理像这样的不同情况,请告诉我,我可以更新我的答案。+1因为我没有使用正则表达式来分割字符串和数字,而且完全依赖LINQ。@Habib:正则表达式有什么问题吗?@spender,我在发布此评论之前没有看到你的答案:,实际上我在尝试基于正则表达式的类似答案,结果变得很混乱。那只是我和REGEX。。。。
test.sort(new AlphaNumericComparer());
//RESULT
Hello1
Hello2
Hello3
Hello10
Hello11
Hello20
Hello100
Welcome0
Welcome2
World
World3
public class AlphaNumericComparer : IComparer
{
public int Compare(object x, object y)
{
string s1 = x as string;
if (s1 == null)
{
return 0;
}
string s2 = y as string;
if (s2 == null)
{
return 0;
}
int len1 = s1.Length;
int len2 = s2.Length;
int marker1 = 0;
int marker2 = 0;
// Walk through two the strings with two markers.
while (marker1 < len1 && marker2 < len2)
{
var ch1 = s1[marker1];
var ch2 = s2[marker2];
// Some buffers we can build up characters in for each chunk.
var space1 = new char[len1];
var loc1 = 0;
var space2 = new char[len2];
var loc2 = 0;
// Walk through all following characters that are digits or
// characters in BOTH strings starting at the appropriate marker.
// Collect char arrays.
do
{
space1[loc1++] = ch1;
marker1++;
if (marker1 < len1)
{
ch1 = s1[marker1];
}
else
{
break;
}
} while (char.IsDigit(ch1) == char.IsDigit(space1[0]));
do
{
space2[loc2++] = ch2;
marker2++;
if (marker2 < len2)
{
ch2 = s2[marker2];
}
else
{
break;
}
} while (char.IsDigit(ch2) == char.IsDigit(space2[0]));
// If we have collected numbers, compare them numerically.
// Otherwise, if we have strings, compare them alphabetically.
var str1 = new string(space1);
var str2 = new string(space2);
var result = 0;
if (char.IsDigit(space1[0]) && char.IsDigit(space2[0]))
{
var thisNumericChunk = int.Parse(str1);
var thatNumericChunk = int.Parse(str2);
result = thisNumericChunk.CompareTo(thatNumericChunk);
}
else
{
result = str1.CompareTo(str2);
}
if (result != 0)
{
return result;
}
}
return len1 - len2;
}
}
Call like so:
This time test is an array instead of a list.
Array.sort(test, new AlphaNumericComparer())