C# 要舍入文本的数字
我正在使用以下函数将数字转换为文本:C# 要舍入文本的数字,c#,C#,我正在使用以下函数将数字转换为文本: public static string NumberToText(long number) { StringBuilder wordNumber = new StringBuilder(); string[] powers = new string[] { "Thousand ", "Million ", "Billion " }; string[] tens = new string[] { "Twenty", "Thirty", "
public static string NumberToText(long number)
{
StringBuilder wordNumber = new StringBuilder();
string[] powers = new string[] { "Thousand ", "Million ", "Billion " };
string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
string[] ones = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
"Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
if (number == 0) { return "Zero"; }
if (number < 0)
{
wordNumber.Append("Negative ");
number = -number;
}
long[] groupedNumber = new long[] { 0, 0, 0, 0 };
int groupIndex = 0;
while (number > 0)
{
groupedNumber[groupIndex++] = number % 1000;
number /= 1000;
}
for (int i = 3; i >= 0; i--)
{
long group = groupedNumber[i];
if (group >= 100)
{
wordNumber.Append(ones[group / 100 - 1] + " Hundred ");
group %= 100;
if (group == 0 && i > 0)
wordNumber.Append(powers[i - 1]);
}
if (group >= 20)
{
if ((group % 10) != 0)
wordNumber.Append(tens[group / 10 - 2] + " " + ones[group % 10 - 1] + " ");
else
wordNumber.Append(tens[group / 10 - 2] + " ");
}
else if (group > 0)
wordNumber.Append(ones[group - 1] + " ");
if (group != 0 && i > 0)
wordNumber.Append(powers[i - 1]);
}
return wordNumber.ToString().Trim();
}
我如何做到这一点?也许是这样的 虽然如果你有“可打印字符OCD”,你可能会得到更小的
private static string[] suffixes = new[] { "", "K", "Mill", "Bill", "Trill", "Zill" };
public static string ToStuff(double number, int precision = 2)
{
const double unit = 1000;
var i = 0;
while (number > unit)
{
number /= unit;
i++;
}
if(i >= 5) throw new Exception("No one can count this high");
return Math.Round(number, precision, MidpointRounding.AwayFromZero) + suffixes[i];
}
免责声明:完全未经测试
更新
由于流行的需求,我用一个测试用例1测试了它,例如2500000,0
,它输出2Mill
。我想我可能会在这场计数比赛中有一份职业
更新2
由于更普遍的需求,一致认为我们不应该使用.Net默认舍入
ToEven
(银行家舍入),而应该使用AwayFromZero
可能是这样的
虽然如果你有“可打印字符OCD”,你可能会得到更小的
private static string[] suffixes = new[] { "", "K", "Mill", "Bill", "Trill", "Zill" };
public static string ToStuff(double number, int precision = 2)
{
const double unit = 1000;
var i = 0;
while (number > unit)
{
number /= unit;
i++;
}
if(i >= 5) throw new Exception("No one can count this high");
return Math.Round(number, precision, MidpointRounding.AwayFromZero) + suffixes[i];
}
免责声明:完全未经测试
更新
由于流行的需求,我用一个测试用例1测试了它,例如2500000,0
,它输出2Mill
。我想我可能会在这场计数比赛中有一份职业
更新2
由于更普遍的需求,一致认为我们不应该使用.Net默认舍入ToEven
(银行家舍入),而应该使用AwayFromZero
尝试以下方法:
if (number>1000000)
string = floor(number/1000000).ToString() + "m";
else if (number > 1000)
string = floor(number/1000).ToString() + "k";
else
string = number.ToString();
请尝试以下操作:
if (number>1000000)
string = floor(number/1000000).ToString() + "m";
else if (number > 1000)
string = floor(number/1000).ToString() + "k";
else
string = number.ToString();
通过编程?试试看。如果你写了以上内容,这应该不会太难。如果你陷入困境,在这里问一个特定的问题。通过编程?试试看。如果你写了以上内容,这应该不会太难。如果你被卡住了,在这里问一个具体的问题。谢谢。你的解决方案有效。迈克尔的回答非常清晰,教了我一些新东西。谢谢。你的解决方案有效。迈克尔的回答非常清晰,教会了我一些新东西。