C# 更改图形c的x轴值#

我对c#和visualstudio有点陌生，我正在尝试根据其他地方的csv文件的值绘制一个图形。我使用了c#中的ChartObjects和ChartWizard属性来创建图形。绘制的图形应该是我提供的列范围，在Y轴和X轴上应该有当前的行号（1,2,3,4等）。但是，默认情况下，我的图形将X轴作为csv文件中的第一列。如果我也为X轴指定了一个范围，它会正确打印，但如何才能在那里获得当前的行号

我浏览了很多文章和问题，甚至是关于堆栈溢出的，但似乎都没有帮助

以下是我的代码片段：

Microsoft.Office.Interop.Excel.Application xlexcel;
Microsoft.Office.Interop.Excel.Worksheet xlWorkSheet;

object misValue = System.Reflection.Missing.Value;
xlexcel = new Microsoft.Office.Interop.Excel.Application();

var xlWorkBooks = xlexcel.Workbooks;

xlexcel.Visible = false;

xlWorkBooks.OpenText(@"C:\" + processName + ".csv", misValue, misValue, Microsoft.Office.Interop.Excel.XlTextParsingType.xlDelimited,          Microsoft.Office.Interop.Excel.XlTextQualifier.xlTextQualifierNone, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue);

// Set Sheet 1 as the sheet you want to work with
xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBooks[1].Worksheets.get_Item(1);

xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select();

//~~> Make it a Line Chart
      xlexcel.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine);

//~~> Set the data range
xlexcel.ActiveChart.SetSourceData(xlWorkSheet.Range["E2:E200"]);
xlexcel.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType);

Microsoft.Office.Interop.Excel.ChartObjects chartObjects =(Microsoft.Office.Interop.Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing));
foreach (Microsoft.Office.Interop.Excel.ChartObject co in chartObjects)
{
    co.Select();
    Microsoft.Office.Interop.Excel.Chart chart = (Microsoft.Office.Interop.Excel.Chart)co.Chart;
    chart.Export(ConfigurationManager.AppSettings.Get("Charts") + "\\ProcessFiles" + @"\" + chartName + " (" + processName + "of" + processType + ")" + ".png", "PNG", false);
    co.Delete();
 }
 xlWorkBooks[1].Close(true, misValue, misValue);
 xlexcel.Quit();

任何指导都将不胜感激。

---

谢谢

我尝试了你的代码并做了一些修改，我希望这能奏效

using Excel = Microsoft.Office.Interop.Excel;

Excel.Application xlApp;
Excel.Workbook xlWorkBook;
Excel.Worksheet xlWorkSheet;

object misValue = System.Reflection.Missing.Value;
//string appPath = Path.GetDirectoryName(Application.ExecutablePath);
string fileName = "" + "YOUR_PATH" + "\\Templates\\myCSV.csv";

string processName = "test";
xlApp = new Excel.Application();
xlWorkBook = xlApp.Workbooks.Open(fileName);
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);

xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select();

//~~> Make it a Line Chart
            xlApp.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine);

//~~> Set the data range
xlApp.ActiveChart.SetSourceData(xlWorkSheet.Range["B1:B30"]);
string chartName = "TEST CHART", processType="TEST TYPE";
xlApp.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType);

Excel.ChartObjects chartObjects = (Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing));

foreach (Excel.ChartObject co in chartObjects)
{
  co.Select();
  Excel.Chart chart = (Excel.Chart)co.Chart;
  chart.Export("C:\\YOUR_PATH" + @"\" + chart.Name + ".png", "PNG", false);
}

xlWorkBook.Close(true, misValue, misValue);
xlApp.Quit();


xlWorkSheet = null;
xlWorkBook = null;
xlApp = null;
releaseObject(xlWorkBook);
releaseObject(xlWorkSheet);
releaseObject(xlApp);

private void releaseObject(object obj)
{
  try
  {
    System.Runtime.InteropServices.Marshal.ReleaseComObject(obj);
    obj = null;
  }
  catch (Exception ex)
  {
    obj = null;
    MessageBox.Show(ex.Message);
  }
  finally
  {
    GC.Collect();
  }
}

---

我尝试了你的代码，并做了一些修改，我希望这将工作

using Excel = Microsoft.Office.Interop.Excel;

Excel.Application xlApp;
Excel.Workbook xlWorkBook;
Excel.Worksheet xlWorkSheet;

object misValue = System.Reflection.Missing.Value;
//string appPath = Path.GetDirectoryName(Application.ExecutablePath);
string fileName = "" + "YOUR_PATH" + "\\Templates\\myCSV.csv";

string processName = "test";
xlApp = new Excel.Application();
xlWorkBook = xlApp.Workbooks.Open(fileName);
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);

xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select();

//~~> Make it a Line Chart
            xlApp.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine);

//~~> Set the data range
xlApp.ActiveChart.SetSourceData(xlWorkSheet.Range["B1:B30"]);
string chartName = "TEST CHART", processType="TEST TYPE";
xlApp.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType);

Excel.ChartObjects chartObjects = (Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing));

foreach (Excel.ChartObject co in chartObjects)
{
  co.Select();
  Excel.Chart chart = (Excel.Chart)co.Chart;
  chart.Export("C:\\YOUR_PATH" + @"\" + chart.Name + ".png", "PNG", false);
}

xlWorkBook.Close(true, misValue, misValue);
xlApp.Quit();


xlWorkSheet = null;
xlWorkBook = null;
xlApp = null;
releaseObject(xlWorkBook);
releaseObject(xlWorkSheet);
releaseObject(xlApp);

private void releaseObject(object obj)
{
  try
  {
    System.Runtime.InteropServices.Marshal.ReleaseComObject(obj);
    obj = null;
  }
  catch (Exception ex)
  {
    obj = null;
    MessageBox.Show(ex.Message);
  }
  finally
  {
    GC.Collect();
  }
}

---

是否要在excel中显示或导出为图像文件？我要将其导出为图像文件@imsome1您想在excel中显示还是导出为图像文件？我想将其导出为图像文件@imsome1感谢您@imsome1的帮助，但我的是一个控制台应用程序，所以application.ExecutablePath不起作用。除此之外，我仍然得到相同的输出。请给出您的路径而不是Application.ExecutablePath和tryYes，我尝试过了。但我仍然没有得到所需的输出。是否有任何错误？您是否正确更改了路径和文件名？它在这里工作，没有错误。只是创建的图形在我的csv中仍然有第一列作为X-Axis感谢您的帮助@imsome1，但是我的是一个控制台应用程序，所以application.ExecutablePath不起作用。除此之外，我仍然得到相同的输出。请给出您的路径而不是Application.ExecutablePath和tryYes，我尝试过了。但我仍然没有得到所需的输出。是否有任何错误？您是否正确更改了路径和文件名？它在这里工作，没有错误。只是创建的图形仍将csv中的第一列作为X轴