C# 从具有相同ID的不同表中减去2列
我有两个表C# 从具有相同ID的不同表中减去2列,c#,datagridview,sql-server-2012,C#,Datagridview,Sql Server 2012,我有两个表TblAddToInventory和tblwithdrawnfromninventory。两者都有ProductID和Quantity。提取时，存货自然应扣除项目数量，但仅扣除已提取的项目。例如： TblAddToInventory TblWithdrawnFromInventory 这样，当我连接两个表并扣除特定列时，我应该有一个DataGridView，使用C#和以下数据： ProductID | Quantity | Amount 1 2
TblAddToInventorytblwithdrawnfromninventoryProductIDQuantityDataGridViewProductID | Quantity | Amount
1 2 2.00
2 1 1.00
3 2 2.00
SUMJOINSUMTblAddToInventorygroupbySUMtblwithdrawnfromninventorygroupby从TblAddToInventory
中减去列，然后TblWithdrawnFromInventory
使用分组依据
。但我认为这不是个好主意。你能帮忙吗
多谢各位
我知道如何使用SUM和JOIN，但我只是不知道如何创建一个
使用从不同表中减去两列的语法
相同的ID
这是如何执行此操作的代码：
SELECT inventory.ProductId,
inventory.Quantity - ISNULL(withdrawal.Quantity,0) AS Quantity,
inventory.Amount - ISNULL(withdrawal.Amount,0) AS Amount
FROM (
SELECT ProductId, SUM(Quantity) AS Quantity, SUM(Amount) AS Amount
FROM TblAddToInventory
GROUP BY ProductId
) AS inventory
LEFT JOIN (
SELECT ProductId, SUM(Quantity) AS Quantity, SUM(Amount) AS Amount
FROM TblWithdrawnFromInventory
GROUP BY ProductId
) AS withdrawal ON inventory.ProductId = withdrawal.ProductId
我知道如何使用SUM和JOIN，但我只是不知道如何创建一个
使用从不同表中减去两列的语法
相同的ID
这是如何执行此操作的代码：
SELECT inventory.ProductId,
inventory.Quantity - ISNULL(withdrawal.Quantity,0) AS Quantity,
inventory.Amount - ISNULL(withdrawal.Amount,0) AS Amount
FROM (
SELECT ProductId, SUM(Quantity) AS Quantity, SUM(Amount) AS Amount
FROM TblAddToInventory
GROUP BY ProductId
) AS inventory
LEFT JOIN (
SELECT ProductId, SUM(Quantity) AS Quantity, SUM(Amount) AS Amount
FROM TblWithdrawnFromInventory
GROUP BY ProductId
) AS withdrawal ON inventory.ProductId = withdrawal.ProductId
准备：
--使用数据创建临时表，强制转换第一行的日期以设置正确的数据类型
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
--使用数据创建临时表，强制转换第一行的日期以设置正确的数据类型
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
验证数据是否正确
select * from #tblAddToInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
select * from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 2 4 4.00 2012-07-09
-- 3 5 5.00 2012-07-10
验证数据是否正确
select * from #tblAddToInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
select * from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 2 4 4.00 2012-07-09
-- 3 5 5.00 2012-07-10
开始解决方案：
--使用Union All连接查询，并将第二个查询乘以-1使其为负数
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
准备：
--使用数据创建临时表，强制转换第一行的日期以设置正确的数据类型
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
--使用数据创建临时表，强制转换第一行的日期以设置正确的数据类型
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
验证数据是否正确
select * from #tblAddToInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
select * from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 2 4 4.00 2012-07-09
-- 3 5 5.00 2012-07-10
验证数据是否正确
select * from #tblAddToInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
select * from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 2 4 4.00 2012-07-09
-- 3 5 5.00 2012-07-10
开始解决方案：
--使用Union All连接查询，并将第二个查询乘以-1使其为负数
select * into #tblAddToInventory from (
select 1 as ProductID, 2 as Quantity, 2.00 as Amount, cast('7/7/2012' as date) as [Date]
union all select 2 as ProductID, 3 as Quantity, 3.00 as Amount, '7/7/2012' as Date
union all select 3 as ProductID, 4 as Quantity, 4.00 as Amount, '7/7/2012' as Date
union all select 2 as ProductID, 2 as Quantity, 2.00 as Amount, '7/8/2012' as Date
union all select 3 as ProductID, 3 as Quantity, 3.00 as Amount, '7/8/2012' as Date
) a
select * into #tblWithdrawnFromInventory from (
select 2 as ProductID, 4 as Quantity, 4.00 as Amount, cast('7/9/2012' as date) as [Date]
union all select 3 as ProductID, 5 as Quantity, 5.00 as Amount, '7/10/2012' as Date
) b
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, Amount, Date from #tblWithdrawnFromInventory
-- ProductID Quantity Amount Date
-- ----------- ----------- ----------- ----------
-- 1 2 2.00 2012-07-07
-- 2 3 3.00 2012-07-07
-- 3 4 4.00 2012-07-07
-- 2 2 2.00 2012-07-08
-- 3 3 3.00 2012-07-08
-- 2 -4 4.00 2012-07-09
-- 3 -5 5.00 2012-07-10
select ProductID, sum(Quantity) as Quantity, sum(Amount) as Amount from (
select * from #tblAddToInventory union all
select ProductID, (Quantity * -1) as Quantity, (Amount * -1) as Amount, Date from #tblWithdrawnFromInventory
) joinedData
where [Date] >= '7/6/2012' and [Date] <= '7/11/2012'
group by ProductID
-- ProductID Quantity Amount
-- ----------- ----------- -----------
-- 1 2 2.00
-- 2 1 1.00
-- 3 2 2.00
为什么不让它成为一个InventoryActivity表，可以有正数或负数的变化？尽管如此，您仍然可以在两个select查询之间使用并集，然后对这两个查询的结果求和。您可以使用linq或lambda选择具有相同idI的每一行上的值。我还不太擅长sql。您能告诉我select命令的语法吗？为什么不将其设置为一个InventoryActivity表，该表可以有正数或负数的更改？尽管如此，您仍然可以在两个select查询之间使用并集，然后对这两个查询的结果求和。您可以使用linq或lambda选择具有相同idI的每一行上的值。我还不太擅长sql。你能告诉我select命令的语法吗？谢谢trungtin1710。但是你的代码没有给我正确的结果。这就是我想到的：选择TblAddToInventory.ProductID作为[Product ID]，选择SUM（TblAddToInventory.QUOTE）-SUM（TblWithdrawal.QUOTE）作为数量，选择SUM（TblAddToInventory.Amount）-SUM（TblWithdrawal.Amount）作为TblAddToInventory.ProductID=TblAddToInventory.ProductID的TblAddToInventory左侧外部联接TblWithdrawal上TblAddToInventory.ProductID组TblWithdrawal的金额，TblAddToInventory.ProductIDIt为我提供了正确的值，但对于那些没有取款的ProductID，它为我提供了空值。我需要的是给我TblAddToInventory中ProductID的总金额，如果没有从TblWithdrawnFromInventory中扣除“对于那些没有取款的ProductID，它给我一个空值”我认为这与您的情况相符，在您的示例数据中，我的代码可以求和productid=1它给我一个productid为1而不是2的空值，以及金额为空而不是2.00的值，因为不存在使用该productid求和的取款。我正在使用我在评论中创建的代码，因为我在使用您的代码时出错，但这就是我的想法来源。谢谢trungtin1710。但是你的代码没有给我正确的结果。这就是我想到的：选择TblAddToInventory.ProductID作为[Product ID]，选择SUM（TblAddToInventory.QUOTE）-SUM（TblWithdrawal.QUOTE）作为数量，选择SUM（TblAddToInventory.Amount）-SUM（TblWithdrawal.Amount）作为TblAddToInventory.ProductID=TblAddToInventory.ProductID的TblAddToInventory左侧外部联接TblWithdrawal上TblAddToInventory.ProductID组TblWithdrawal的金额，TblAddToInventory.ProductIDIt为我提供了正确的值，但对于那些没有取款的ProductID，它为我提供了空值。我需要的是给我TblAddToInventory中ProductID的总金额，如果没有从TblWithdrawnFromInventory中扣除“对于那些没有取款的ProductID，它给我一个空值”我认为这与您的情况相符，在您的示例数据中，我的代码可以求和productid=1它给我一个productid为1而不是2的空值，以及金额为空而不是2.00的值，因为不存在使用该productid求和的取款。我正在使用我在注释中创建的代码，因为我在使用您的代码时会出错，但这就是我的想法来源。