C# 如何将递归结构封送到c sharp?
我有一个非托管结构,我想封送到c sharp,它基本上是这样的:C# 如何将递归结构封送到c sharp?,c#,marshalling,recursive-datastructures,C#,Marshalling,Recursive Datastructures,我有一个非托管结构,我想封送到c sharp,它基本上是这样的: struct MyStruct{ /* ... some stuff ... */ int numChilds; MyStruct *childs; } 我相信我必须编写一个自定义封送拆收器,但我不确定如何继续。如果您只想将其传递给某个非托管函数,您可以使用不安全的代码和stackalloc/fix数组来获取指向对象数组的指针 unsafe struct Foo {
struct MyStruct{
/* ... some stuff ... */
int numChilds;
MyStruct *childs;
}
我相信我必须编写一个自定义封送拆收器,但我不确定如何继续。如果您只想将其传递给某个非托管函数,您可以使用不安全的代码和stackalloc/fix数组来获取指向对象数组的指针
unsafe struct Foo
{
public int value;
public int fooCount;
public Foo* foos;
}
[DllImport("dll_natv.dll")]
static extern void PrintFoos(Foo f);
public unsafe static void Main()
{
Foo* foos = stackalloc Foo[10];
for (int i = 0; i < 10; ++i)
foos[i].value = i;
Foo mainFoo = new Foo();
mainFoo.fooCount = 10;
mainFoo.value = 100;
mainFoo.foos = foos;
PrintFoos(mainFoo);
}
不安全结构Foo
{
公共价值观;
公众参与人数;
公共食品*食品;
}
[DllImport(“dll_natv.dll”)]
静态外部无效打印foos(Foo f);
公共不安全静态void Main()
{
Foo*foos=stackalloc Foo[10];
对于(int i=0;i<10;++i)
foos[i].value=i;
Foo mainFoo=新的Foo();
mainFoo.fooCount=10;
mainFoo.value=100;
mainFoo.foos=foos;
PrintFoos(美孚);
}
当我不需要直接索引子项时,我喜欢使用这样的设置:
struct MyStruct
{
/* ... some stuff ... */
int numChilds;
IntPtr childData;
public IEnumerable<MyStruct> Children
{
get
{
int elementSize = Marshal.SizeOf(typeof(MyStruct));
for (int i = 0; i < this.numChilds; i++)
{
IntPtr data = new IntPtr(this.childData.ToInt64() + elementSize * i);
MyStruct child = (MyStruct)Marshal.PtrToStructure(data, typeof(MyStruct));
yield return child;
}
}
}
}
public MyStruct GetChild(int index)
{
if (index < 0)
throw new ArgumentOutOfRangeException("index", "The index must be >= 0.");
if (index >= this.numChilds)
throw new ArgumentException("The index must be less than the number of children", "index");
int elementSize = Marshal.SizeOf(typeof(MyStruct));
IntPtr data = new IntPtr(childData.ToInt64() + elementSize * index);
MyStruct child = (MyStruct)Marshal.PtrToStructure(data, typeof(MyStruct));
return child;
}