C#:基于不同枚举类型的枚举值返回枚举值
因此,我希望有一个属性getter,它基于不同类型的枚举值返回枚举值,而不必求助于长switch语句。有没有办法使用索引或值来匹配两个枚举列表C#:基于不同枚举类型的枚举值返回枚举值,c#,enums,C#,Enums,因此,我希望有一个属性getter,它基于不同类型的枚举值返回枚举值,而不必求助于长switch语句。有没有办法使用索引或值来匹配两个枚举列表 public enum LanguageName { Arabic, Chinese, Dutch, English, Farsi, French, Hindi, Indonesian, Portugue
public enum LanguageName
{
Arabic,
Chinese,
Dutch,
English,
Farsi,
French,
Hindi,
Indonesian,
Portuguese,
Spanish,
Urdu
}
public enum LanguageISOCode
{
ara,
zho,
dut,
eng,
fas,
fre,
hin,
ind,
por,
spa,
urd
}
public class language
{
public language()
{
}
public LanguageName Name
{
get
{
// get the Name enum based on the Code enum
}
set;
}
public LanguageISOCode Code
{
get;
set;
}
}
假设值的顺序相同,您可以先进行
int
转换:
public LanguageName Name
{
get
{
int n = (int) Code;
return (LanguageName)n;
}
}
这需要确保枚举值始终按正确的顺序排列,或者显式为它们指定数值:
public enum LanguageName
{
Arabic = 1,
Chinese = 2,
...
}
public enum LanguageISOCode
{
ara = 1,
zho = 2,
...
}
上述内容不是必需的(因为标准保证它们被分配单调递增的数值),但至少在您可能决定对字段重新排序或诸如此类的情况下,它涵盖了您。假设值的顺序相同,您可以先进行
int
转换:
public LanguageName Name
{
get
{
int n = (int) Code;
return (LanguageName)n;
}
}
这需要确保枚举值始终按正确的顺序排列,或者显式为它们指定数值:
public enum LanguageName
{
Arabic = 1,
Chinese = 2,
...
}
public enum LanguageISOCode
{
ara = 1,
zho = 2,
...
}
上述内容不是必需的(因为标准保证它们会被分配单调递增的数值),但至少在您可能决定对字段重新排序或诸如此类的情况下,它涵盖了您。您可以在这两者中使用相同的int值,并强制转换为int和强制转换为enum
public enum LanguageName
{
Arabic = 1,
Chinese,
Dutch,
English,
Farsi,
French,
Hindi,
Indonesian,
Portuguese,
Spanish,
Urdu
}
public enum LanguageISOCode
{
ara = 1,
zho,
dut,
eng,
fas,
fre,
hin,
ind,
por,
spa,
urd
}
public class language
{
public language()
{
}
public LanguageName Name
{
get
{
return (LanguageName)((int)Code);
}
set;
}
public LanguageISOCode Code
{
get;
set;
}
}
或者您可以使用另一种方法,如使用[Description]并进行一些搜索。您可以在这两种方法中使用相同的int值,并强制转换为int和强制转换为enum
public enum LanguageName
{
Arabic = 1,
Chinese,
Dutch,
English,
Farsi,
French,
Hindi,
Indonesian,
Portuguese,
Spanish,
Urdu
}
public enum LanguageISOCode
{
ara = 1,
zho,
dut,
eng,
fas,
fre,
hin,
ind,
por,
spa,
urd
}
public class language
{
public language()
{
}
public LanguageName Name
{
get
{
return (LanguageName)((int)Code);
}
set;
}
public LanguageISOCode Code
{
get;
set;
}
}
或者,您可以使用另一种方法,如使用[Description]并进行一些搜索。您可以使用
字典
进行一个到另一个的显式映射
Dictionary<LanguageName, LanguageISOCode> languageCodes = new Dictionary<LanguageName, LanguageISOCode> {
{LanguageName.Arabic,LanguageISOCode.ara},
{LanguageName.Chinese,LanguageISOCode.zho},
//...
};
LanguageName lang = LanguageName.Arabic;
LanguageISOCode code = languageCodes[lang];
字典语言code=新字典{
{LanguageName.阿拉伯语,LanguageISOCode.ara},
{LanguageName.Chinese,LanguageISOCode.zho},
//...
};
LanguageName lang=LanguageName.阿拉伯语;
LanguageISOCode代码=languageCodes[lang];
您可以使用字典
进行一个到另一个的显式映射
Dictionary<LanguageName, LanguageISOCode> languageCodes = new Dictionary<LanguageName, LanguageISOCode> {
{LanguageName.Arabic,LanguageISOCode.ara},
{LanguageName.Chinese,LanguageISOCode.zho},
//...
};
LanguageName lang = LanguageName.Arabic;
LanguageISOCode code = languageCodes[lang];
字典语言code=新字典{
{LanguageName.阿拉伯语,LanguageISOCode.ara},
{LanguageName.Chinese,LanguageISOCode.zho},
//...
};
LanguageName lang=LanguageName.阿拉伯语;
LanguageISOCode代码=languageCodes[lang];
您可以明确声明一个枚举值等于另一个枚举值,如下所示:
public enum LanguageName
{
Arabic,
Chinese,
Dutch,
...
}
public enum LanguageISOCode
{
ara = LanguageName.Arabic,
zho = LanguageName.Chinese,
dut = LanguageName.Dutch,
...
}
这样你就可以在他们之间进行转换:
LanguageISOCode codeValue = LanguageISOCode.ara;
LanguageName name = (LanguageName)(int)codeValue;
或
虽然上面的内容应该回答您明确的问题,但您应该看看这个类。它提供了许多有关各种区域性的功能。您可以明确声明一个枚举值等于另一个枚举值,如下所示:
public enum LanguageName
{
Arabic,
Chinese,
Dutch,
...
}
public enum LanguageISOCode
{
ara = LanguageName.Arabic,
zho = LanguageName.Chinese,
dut = LanguageName.Dutch,
...
}
这样你就可以在他们之间进行转换:
LanguageISOCode codeValue = LanguageISOCode.ara;
LanguageName name = (LanguageName)(int)codeValue;
或
虽然上面的内容应该回答您明确的问题,但您应该看看这个类。它提供了许多关于不同文化的功能。谢谢!你给了我我所怀疑的一切。谢谢你提到CultureInfo课程。太好了,正是我想要的!谢谢你给了我我所怀疑的一切。谢谢你提到CultureInfo课程。太好了,正是我想要的!