C# 从Gmail发送电子邮件DisplayName属性出错
下面是我删除MailAddress()的DisplayName属性时的代码。它工作正常,但接收端邮件会在显示名称上显示EmailID,如emailID@gmail.com.C# 从Gmail发送电子邮件DisplayName属性出错,c#,email,gmail,C#,Email,Gmail,下面是我删除MailAddress()的DisplayName属性时的代码。它工作正常,但接收端邮件会在显示名称上显示EmailID,如emailID@gmail.com. MailMessage mail = new MailMessage(); mail.From = new System.Net.Mail.MailAddress("emailID@domainName.com"); // The important part -- configuring the SMTP
MailMessage mail = new MailMessage();
mail.From = new System.Net.Mail.MailAddress("emailID@domainName.com");
// The important part -- configuring the SMTP client
SmtpClient smtp = new SmtpClient();
smtp.Port = 587; // [1] You can try with 465 also, I always used 587 and got success
smtp.EnableSsl = true;
smtp.DeliveryMethod = SmtpDeliveryMethod.Network; // [2] Added this
smtp.UseDefaultCredentials = false; // [3] Changed this
smtp.Credentials = new NetworkCredential(mail.From.ToString(), "password"); // [4] Added this. Note, first parameter is NOT string.
smtp.Host = "smtp.gmail.com";
mail.IsBodyHtml = true;
mail.Subject = Subject;
mail.Body = Body;
mail.To.Add(new MailAddress(To));
smtp.Send(mail);
mail.Dispose();
添加MailAddress()的显示名称时,我收到此错误消息
System.Net.Mail.SmtpException:SMTP服务器需要安全的
连接或客户端未通过身份验证。服务器响应
was:5.5.1需要身份验证。了解更多信息,请访问
System.Net.Mail.MailCommand.CheckResponse(SmtpStatusCode状态码,
字符串响应)在System.Net.Mail.SmtpTransport.SendMail(邮件地址
发件人、MailAddressCollection收件人、字符串deliveryNotify、,
布尔AllowInCode、SmtpFailedRecipientException和exception)位于
System.Net.Mail.SmtpClient.Send(MailMessage)位于***
我错在哪里
var client = new SmtpClient
{
Host = "smtp.googlemail.com",
Port = 587,
UseDefaultCredentials = false,
DeliveryMethod = SmtpDeliveryMethod.Network,
EnableSsl = true,
Credentials = new NetworkCredential(SmtpUserName, SmtpUserPassword);
};
client.Send(mail);
其中mail
是MailMessage
private static SecureString _smtpPassword;
public static SecureString SmtpUserPassword
{
get
{
if (_smtpPassword != null)
return _smtpPassword;
_smtpPassword = new SecureString();
foreach (var c in "your password here")
_smtpPassword.AppendChar(c);
_smtpPassword.MakeReadOnly();
return _smtpPassword;
}
}
谢谢你的快速回复。您在哪里提到电子邮件的显示名称?我不确定我是否理解您的问题。你说的移除是什么意思?DisplayName是我添加此邮件时的GET属性。From=new System.Net.mail.MailAddress(“emailID@domainName.com“,”姓名“);接收以上错误消息我从错误消息中读取的内容原因是身份验证。在大多数情况下,UserNam/Password中存在问题。请参阅我关于设置用户密码的更新。