C# 并非所有代码路径都返回一个"；“价值”；

您好，我正在尝试制作一个智囊团游戏，让用户猜测4-10之间的数字序列，而不是颜色，但出于某种原因，我的GetRandomNumberCount和我的GeneratorAndomNumber给了我一个错误，并非所有代码路径都返回一个值

如有任何指导，将不胜感激

public static int GetRandomNumberCount()
{
      //Create the secret code
      Random RandomClass = new Random();

      int first = RandomClass.Next(1, 5);
      int second = RandomClass.Next(1,5);
      int third = RandomClass.Next(1,5);
      int forth = RandomClass.Next(1,5);

      Console.WriteLine ("You are playing with M@sterB@t");
      Console.WriteLine ("Bot Says : You Go First");
      Console.WriteLine("Game Settings ");
      Console.WriteLine("The Game Begins");
}

---

这是因为它们不返回值。例如，GetRandomNumberCount将

Int

设置为其返回类型，但没有返回语句。如果不想返回任何内容，请将返回类型设置为void。以此为例,

 public static int[] GetRandomNumberCount()
{
    //Create the secret code
    Random RandomClass = new Random();

    int first = RandomClass.Next(1, 5);
    int second = RandomClass.Next(1,5);
    int third = RandomClass.Next(1,5);
    int forth = RandomClass.Next(1,5);

    Console.WriteLine ("You are playing with M@sterB@t");
    Console.WriteLine ("Bot Says : You Go First");
    Console.WriteLine("Game Settings ");
    Console.WriteLine("The Game Begins");

    //This is where you would return a value, but in this case it seems you want to return an array of ints
    //Notice how I changed the return type of the method to Int[]
   int[] numbers = new int[4];
   numbers.Add(first);
   numbers.Add(second);
   numbers.Add(third);
   numbers.Add(fourth);

   //This is the actual return statement that your methods are missing
   return numbers;

    }

不管你是否真的想要返回一个int数组都是没有意义的，我只是在猜测。真正的好处是

int[]

in

public static int[] GetRandomNumberCount()

---

声明返回类型，这意味着您需要返回语句

您得到了这个错误，因为您的方法签名说它返回一个

int

，但您没有返回任何内容。我看到的是，由于您只是在打印行，所以您希望有一个带有

void

返回类型的方法，如下所示

public static void GetRandomNumberCount()
{
      //Create the secret code
      Random RandomClass = new Random();

      int first = RandomClass.Next(1, 5);
      int second = RandomClass.Next(1,5);
      int third = RandomClass.Next(1,5);
      int forth = RandomClass.Next(1,5);

      Console.WriteLine ("You are playing with M@sterB@t");
      Console.WriteLine ("Bot Says : You Go First");
      Console.WriteLine("Game Settings ");
      Console.WriteLine("The Game Begins");
}

---

只发布相关的代码，而不是你的整个项目。他显然想返回这些INT，否则这些INT是为注释而创建的，然后就退出了scope@psoshmo除非OP公司澄清，否则这只是目前的猜测。此外，你认为你将如何返回所有的随机数？在一个整数数组中，但你是对的，我在这里假设，我不应该这样做。