C# 根据可能性计算要执行的随机操作

我有一个枚举，其中包含一些可能的操作

internal enum Action
{
    Stay,
    MoveLeft,
    MoveRight
}

以及一个对象，该对象保存有关此操作的当前机会的信息

internal class ActionWithPossibility
{
    public Action Action { get; }
    public int ActionChancePercent { get; }

    public ActionWithPossibility(Action action, int actionChancePercent)
    {
        Action = action;
        ActionChancePercent = actionChancePercent;
    }
}

机会从0到100。有机会的一系列行动可能是

        List<ActionWithPossibility> actionsWithPossibilities = new List<ActionWithPossibility>() {
            new ActionWithPossibility(Action.Stay, 40),
            new ActionWithPossibility(Action.MoveLeft, 30),
            new ActionWithPossibility(Action.MoveRight, 30)
        };

列表

但是正如我之前提到的，可能的操作数量是未知的，所以我不能使用三个if语句。也许有一个技巧是使用一些数学来完全避免if语句。
intthreshold=0；
int threshold = 0;
int randomNumber = random.Next(0, 100);
for (var i = 0; i < actionsWithPossibilities.Count; i++)
{
    var item = actionsWithPossibilities[i];
    threshold += item.ActionChancePercent;

    if (randomNumber <= threshold)
    {
        //first action that's under the defined threshold is placed in result
        result = item.Action;
        break;
    }
}

int randomNumber=random.Next（0，100）；
for（var i=0；iif（randomNumber如果您在列表中列出了您的操作，并且希望将生成的随机数映射到正确的对象。您可以这样想：

林克：

actionswith可能性
.OrderBy（x=>x.actionChancePercent）//按递增顺序排序概率
.首先（y=>randomNumber可能重复使用三个if语句：if（randomNumber）我更新了我的问题
        List<ActionWithPossibility> actionsWithPossibilities = new List<ActionWithPossibility>() {
            new ActionWithPossibility(Action.Stay, 30),
            new ActionWithPossibility(Action.MoveLeft, 60),
            new ActionWithPossibility(Action.MoveRight, 10)
        };

    public void NextAction(List<ActionWithPossibility> actionsWithPossibilities)
    {
        int randomNumber = random.Next(0, 100);

        // ...

        Action targetAction = null; // ?
    }

int threshold = 0;
int randomNumber = random.Next(0, 100);
for (var i = 0; i < actionsWithPossibilities.Count; i++)
{
    var item = actionsWithPossibilities[i];
    threshold += item.ActionChancePercent;

    if (randomNumber <= threshold)
    {
        //first action that's under the defined threshold is placed in result
        result = item.Action;
        break;
    }
}

actionsWithPossibilities
   .OrderBy(x => x.actionChancePercent) // Sort probabilities in increasing order
   .First(y => randomNumber <= y.actionChancePercent)
   // Find the correct 'bracket' by checking when the 
   // random number passes the thresholds.