C# Ajax更新面板和样式
我有一个带有js和css样式的按钮,每次我点击按钮(回发)时,它都会在更新面板中,它会失去样式吗C# Ajax更新面板和样式,c#,asp.net,ajax,panels,C#,Asp.net,Ajax,Panels,我有一个带有js和css样式的按钮,每次我点击按钮(回发)时,它都会在更新面板中,它会失去样式吗 <asp:ScriptManager ID="ScriptManager1" runat="server"> </asp:ScriptManager> </div> <asp:UpdatePanel ID="UpdatePanel1" runat="server"> <ContentTemplate>
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
很确定这是个容易的问题,知道吗
<html xmlns="http://www.w3.org/1999/xhtml">
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
函数artButtonSetupJShover(类名){
变量标签=[“输入”、“a”、“按钮”];
对于(var j=0;j
}
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
添加(函数(){artButtonSetupJShover(“艺术按钮”);}) 我能想到一些案例
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
。如果您给我们提供代码,也许我们可以看到问题所在。如果您使用js设置样式,您可能需要在页面上的ScriptManager中注册该js。这样,脚本将被加载到部分页面回发中。您可能在onload事件中用js设置样式,但此事件仅触发一次,然后在每次回发中更新面板不会通过它。您必须像这样附加到PageRequestManager pageloaded事件:
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
在ScriptManager声明之后,您编写此代码,并且每次在内部执行回发时脚本都将运行
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
<script type="text/jscript">
<!--
var prm = Sys.WebForms.PageRequestManager.getInstance();
prm.add_pageLoaded(pageLoaded);
function pageLoaded(sender, args) {
document.getElementById("Button1").style.fontWeight = "bold";
}
-->
</script>
或直接从Sys.Application.add\u加载:
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
</div>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="Button1" runat="server" class="art-button" Text="Button" />
</ContentTemplate>
</asp:UpdatePanel>
</form>
<script type="text/jscript">
<!--
Sys.Application.add_load(
function pageLoaded(sender, args) {
document.getElementById("Button1").style.fontWeight = "bold";
});
-->
</script>
如何使用i而不是Sys.Application.add\u load(代码)我执行Sys.Application.add\u load(jsfile)?您必须在脚本管理器中注册脚本并调用add中的方法_load@Stacker这是两个选项,在我缺席的情况下另一个答案。