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C# 如何删除unity C中的GUI对象?_C#_User Interface_Unity3d - Fatal编程技术网

C# 如何删除unity C中的GUI对象?

C# 如何删除unity C中的GUI对象?,c#,user-interface,unity3d,C#,User Interface,Unity3d,我有一个可控的角色,当你们从地图上掉下来时,一个GUI将被创建为一个重生按钮 void OnGUI() { if(died==true){ GUI.Label(new Rect(daX, daY, 200, 40), "You died!!"); GUI.Label(new Rect(daX, daY-40, 200, 40), whyDie); if (GUI.Button(new Rect(daX-75, daY

我有一个可控的角色,当你们从地图上掉下来时,一个GUI将被创建为一个重生按钮

        void OnGUI() {
        if(died==true){
        GUI.Label(new Rect(daX, daY, 200, 40), "You died!!");
        GUI.Label(new Rect(daX, daY-40, 200, 40), whyDie);
        if (GUI.Button(new Rect(daX-75, daY+50, 150, 30), "Respawn!!!")){
            transform.position = new Vector3(-5,20,5);
        }
        if (GUI.Button(new Rect(daX-75, daY+100, 150, 30), "Screw This!!!")){
            Debug.Log("Back to menu");
        }
    }
 }
respawn和其他东西都很有效,只是我不知道如何摆脱GUI,所以respawn按钮在你重新启动后仍然存在。有人知道如何删除GUI对象吗?提前谢谢


*编辑:died、daX、daY、whyDie是我创建的有效变量

只需将died变量设置回false,就不会进行GUI调用

void OnGUI()
{
   if(died)
   {
        GUI.Label(new Rect(daX, daY, 200, 40), "You died!!");
        GUI.Label(new Rect(daX, daY-40, 200, 40), whyDie);

        if (GUI.Button(new Rect(daX-75, daY+50, 150, 30), "Respawn!!!"))
        {
            transform.position = new Vector3(-5,20,5);
            died = false; //Stop drawing died interface
        }

        if (GUI.Button(new Rect(daX-75, daY+100, 150, 30), "Screw This!!!"))
        {
            Debug.Log("Back to menu");
            Application.LoadLevel(0); //Load your first scene, where the menu is.
        }
    }
 }

或者,您可以禁用组件/游戏对象。这样就不会再调用整个OnGUI方法了。

主题外:Unity3D GUI是我见过的最差的,它适用于小型和简单的原型。但是对于更大的项目,我同意,但是有很棒的插件(NGUI!)。