C# 将Zip文件转换为字节[]，将字节[]转换为Zip文件

我尝试将zip文件转换为byte[]并将其写入文本文件

int BufferSize=65536;
private void button1_Click(object sender, EventArgs e)
{
    DialogResult re = openFileDialog1.ShowDialog();
    if (re == DialogResult.OK)
    {
        string fileName = openFileDialog1.FileName;
        try
        {
            byte[] bytes = File.ReadAllBytes(fileName);
            File.WriteAllBytes(@"F:\Info.txt", bytes);
        }
        catch (Exception) { }
    }
}   

然后我尝试将这些字节转换为zip文件。但我做不到

我的代码在这里：

private void button2_Click(object sender, EventArgs e)
{

    DialogResult re = openFileDialog1.ShowDialog();
    if (re == DialogResult.OK)
    {
        string fileName = openFileDialog1.FileName;
        try
        {
            byte[] bytes = File.ReadAllBytes(fileName);
            using (var mstrim = new MemoryStream(bytes))
            {
                using (var inStream = new GZipStream(mstrim, CompressionMode.Compress))
                {
                    using (var outStream = File.Create("Tax.Zip"))
                    {
                        var buffer = new byte[BufferSize];
                        int readBytes;
                        while ((readBytes = inStream.Read(buffer, 0, BufferSize)) != 0)
                        {
                            outStream.Write(buffer, 0, readBytes);
                        }
                    }
                }
            }
        }
        catch (Exception) { }
    }
}

错误：文件模式无效

需要什么文件模式以及如何完成我所描述的内容？

您使用的是GZipStream，它用于GZip文件，而不是PK Zip文件。这显然行不通。请尝试ZipFile类，尽管遗憾的是，它不适用于流，只适用于文件

除了只是一种不同的文件格式外，最大的区别在于GZip仅用于压缩，而Zip也是一种存档，即它可以包含多个文件。

您使用的是GZipStream，它用于GZip文件，而不是PK Zip文件。这显然行不通。请尝试ZipFile类，尽管遗憾的是，它不适用于流，只适用于文件

除了只是一种不同的文件格式外，最大的区别在于GZip仅用于压缩，而Zip也是一种存档，即它可以包含多个文件。

试试这个

private void button1_Click(object sender, EventArgs e)
    {
         byte[] arr;
            MemoryStream ms = new MemoryStream();
            arr = File.ReadAllBytes("C:\\asik.zip");
            File.WriteAllBytes(@"D:\\asik.txt", arr);
            ms.Close();
            FileStream stream = File.OpenRead(@"D:\\asik.txt");
            byte[] fileBytes = new byte[stream.Length];
            stream.Read(fileBytes, 0, fileBytes.Length);
            stream.Close();
            MemoryStream ms1 = new MemoryStream(fileBytes);
            CreateToMemoryStream(ms1, @"D:\\asik.zip");
            ms1.Close();


    }

    public void CreateToMemoryStream(MemoryStream memStreamIn, string zipEntryName)
    {

        MemoryStream outputMemStream = new MemoryStream();
        ZipOutputStream zipStream = new ZipOutputStream(outputMemStream);

        zipStream.SetLevel(3); //0-9, 9 being the highest level of compression

        ZipEntry newEntry = new ZipEntry(zipEntryName);
        newEntry.DateTime = DateTime.Now;

        zipStream.PutNextEntry(newEntry);

        StreamUtils.Copy(memStreamIn, zipStream, new byte[4096]);
        zipStream.CloseEntry();

        zipStream.IsStreamOwner = false;    // False stops the Close also Closing the underlying stream.
        zipStream.Close();          // Must finish the ZipOutputStream before using outputMemStream.

        //outputMemStream.Position = 0;
        //return outputMemStream;

        //// Alternative outputs:
        //// ToArray is the cleaner and easiest to use correctly with the penalty of duplicating allocated memory.
        //byte[] byteArrayOut = outputMemStream.ToArray();

        //// GetBuffer returns a raw buffer raw and so you need to account for the true length yourself.
        //byte[] byteArrayOut2 = outputMemStream.GetBuffer();
        //long len = outputMemStream.Length;
    }

试试这个

private void button1_Click(object sender, EventArgs e)
    {
         byte[] arr;
            MemoryStream ms = new MemoryStream();
            arr = File.ReadAllBytes("C:\\asik.zip");
            File.WriteAllBytes(@"D:\\asik.txt", arr);
            ms.Close();
            FileStream stream = File.OpenRead(@"D:\\asik.txt");
            byte[] fileBytes = new byte[stream.Length];
            stream.Read(fileBytes, 0, fileBytes.Length);
            stream.Close();
            MemoryStream ms1 = new MemoryStream(fileBytes);
            CreateToMemoryStream(ms1, @"D:\\asik.zip");
            ms1.Close();


    }

    public void CreateToMemoryStream(MemoryStream memStreamIn, string zipEntryName)
    {

        MemoryStream outputMemStream = new MemoryStream();
        ZipOutputStream zipStream = new ZipOutputStream(outputMemStream);

        zipStream.SetLevel(3); //0-9, 9 being the highest level of compression

        ZipEntry newEntry = new ZipEntry(zipEntryName);
        newEntry.DateTime = DateTime.Now;

        zipStream.PutNextEntry(newEntry);

        StreamUtils.Copy(memStreamIn, zipStream, new byte[4096]);
        zipStream.CloseEntry();

        zipStream.IsStreamOwner = false;    // False stops the Close also Closing the underlying stream.
        zipStream.Close();          // Must finish the ZipOutputStream before using outputMemStream.

        //outputMemStream.Position = 0;
        //return outputMemStream;

        //// Alternative outputs:
        //// ToArray is the cleaner and easiest to use correctly with the penalty of duplicating allocated memory.
        //byte[] byteArrayOut = outputMemStream.ToArray();

        //// GetBuffer returns a raw buffer raw and so you need to account for the true length yourself.
        //byte[] byteArrayOut2 = outputMemStream.GetBuffer();
        //long len = outputMemStream.Length;
    }

试试这个

            byte[] data = File.ReadAllBytes("D:\\z.7z");
            File.WriteAllBytes("D:\\t.txt", data); // Requires System.IO

            byte[] newdata = File.ReadAllBytes("D:\\t.txt");
            File.WriteAllBytes("D:\\a.7z", newdata); // Requires System.IO

试试这个

            byte[] data = File.ReadAllBytes("D:\\z.7z");
            File.WriteAllBytes("D:\\t.txt", data); // Requires System.IO

            byte[] newdata = File.ReadAllBytes("D:\\t.txt");
            File.WriteAllBytes("D:\\a.7z", newdata); // Requires System.IO

---

这种缩进样式确实没有帮助。按Ctrl-K，D。实际上，您必须解压缩zip文件。从zip文件中读取字节不会提供文件中已压缩的实际数据。这就是为什么不能从刚才读取的字节重新创建zip文件的原因。使用DotNetZIP:可以在比Gzip更少的时间和精力内完成更多的工作这种缩进样式确实没有帮助。按Ctrl-K，D。实际上，您必须解压缩zip文件。从zip文件中读取字节不会提供文件中已压缩的实际数据。这就是为什么不能从刚才读取的字节重新创建zip文件的原因。使用DotNetZIP:可以在比Gzip更少的时间和精力内完成更多的工作通过扩展异常类创建一个名为MoreZipeException的自定义异常类请编辑答案并为您提供的代码添加解释。在doc文件夹中只有一个.zip文件，否则它将引发异常，如果有一个.zip文件，它将为您提供字节[]通过扩展异常类创建一个名为MoreZipeException的自定义异常类请编辑答案并对您提供的代码添加解释。在doc文件夹中，将只有一个.zip文件，否则它将引发异常，如果有一个.zip文件，它将为您提供该文件的字节[]。