C# OneToMany关系在NHibernate和NET Persistence API中不起作用

我使用的是Hibernate和NET持久性API与C#的结合。我在两个实体之间有以下关系：

public class Question
{
    [OneToMany(Cascade = new CascadeType[] { CascadeType.ALL }, Fetch = FetchType.LAZY, MappedBy = "Question")]
    public virtual List<QueueLog> QueueLogs { get; set; }    
}

此外，我还尝试通过以下方式建立两个实体之间的关系：

public class Question
{
    [OneToMany(Cascade = new CascadeType[] { CascadeType.ALL }, Fetch = FetchType.LAZY)]
    [JoinColumn(Name = "question_id", ReferencedColumnName = "id")]
    public virtual List<QueueLog> QueueLogs { get; set; }    
}

公开课问题
{
[OneToMany（Cascade=new CascadeType[]{CascadeType.ALL}，Fetch=FetchType.LAZY）]
[JoinColumn（Name=“question\u id”，ReferencedColumnName=“id”）]
公共虚拟列表队列日志{get；set；}
}

及

公共类队列日志
{
[manytone（Fetch=FetchType.EAGER，TargetEntity=typeof（问题））]
[列（Name=“question\u id”，Nullable=false）]
公共虚拟列表问题{get；set；}
}

---

但我还是犯了同样的错误。有人能为我推荐解决方案吗？

我已通过以下更改修复了代码：

public class Question
{
   [OneToMany(TargetEntity = typeof(QueueLog), MappedBy = "question", Fetch = FetchType.EAGER, Cascade = new CascadeType[] { CascadeType.ALL })]
   public virtual NHibernate.Collection.PersistentBag QueueLogs { get; set; }
}

及

public class Question
{
    [OneToMany(Cascade = new CascadeType[] { CascadeType.ALL }, Fetch = FetchType.LAZY)]
    [JoinColumn(Name = "question_id", ReferencedColumnName = "id")]
    public virtual List<QueueLog> QueueLogs { get; set; }    
}

public class QueueLog
{
    [ManyToOne (Fetch = FetchType.EAGER, TargetEntity = typeof(Question))]
    [Column(Name = "question_id", Nullable = false)]
    public virtual List<Question> Question { get; set; }
}

public class Question
{
   [OneToMany(TargetEntity = typeof(QueueLog), MappedBy = "question", Fetch = FetchType.EAGER, Cascade = new CascadeType[] { CascadeType.ALL })]
   public virtual NHibernate.Collection.PersistentBag QueueLogs { get; set; }
}

public class QueueLog
{
     [ManyToOne (Fetch = FetchType.EAGER, TargetEntity = typeof(Question))]
     [JoinColumn(Name = "question_id")]
     public virtual Question question { get; set; }
}