C# LINQ中的分组聚合函数
我有一个以下类型的SQL查询,我试图使用LINQ在我的C#应用程序中获取数据C# LINQ中的分组聚合函数,c#,.net,linq,group-by,aggregate,C#,.net,Linq,Group By,Aggregate,我有一个以下类型的SQL查询,我试图使用LINQ在我的C#应用程序中获取数据 select sum(CASE when outcome = 0 then samplingweight else 0 end) tpcount, sum(CASE when outcome = 1 then samplingweight else 0 end) fpcount, sum(CASE when outcome = 2 then samplingweight else 0 end) mismatch,
select
sum(CASE when outcome = 0 then samplingweight else 0 end) tpcount,
sum(CASE when outcome = 1 then samplingweight else 0 end) fpcount,
sum(CASE when outcome = 2 then samplingweight else 0 end) mismatch,
sum(CASE when outcome = 3 then samplingweight else 0 end) fncount,
sum(CASE when outcome = 4 then samplingweight else 0 end) tncount,
sum(samplingweight) totalweight,
__date,
scenario from MyTable
where __date = '30-Dec-16 12:00:00 AM' and scenario = 'parcels'
group by __date, scenario
注意:samplingweight
是以DB为单位的双精度值
我正在努力,并且能够到达下面的状态
from pr in this.context.ComputedPrSet
where
pr.Date.Equals(date) && pr.Scenario.Equals(scenario)
group pr by new { pr.Date, pr.Scenario }
into grp
select new
{
grp.Key.Date,
grp.Key.Scenario,
TruePositiveCount = grp.Sum(x => x.SamplingWeight) //I am stuck here. Not sure how to aggregate the properties
};
注意:上述LINQ查询中的date
和scenario
作为执行函数的参数
关于如何进行的任何想法或提示?您可以使用
?:
操作符在执行零件时执行案例
from pr in this.context.ComputedPrSet
where
pr.Date.Equals(date) && pr.Scenario.Equals(scenario)
group pr by new { pr.Date, pr.Scenario }
into grp
select new
{
grp.Key.Date,
grp.Key.Scenario,
TruePositiveCount = grp.Sum(x => x.Outcome == 0?x.SamplingWeight:0)
};
您可以使用?:
运算符在执行零件时执行案例
from pr in this.context.ComputedPrSet
where
pr.Date.Equals(date) && pr.Scenario.Equals(scenario)
group pr by new { pr.Date, pr.Scenario }
into grp
select new
{
grp.Key.Date,
grp.Key.Scenario,
TruePositiveCount = grp.Sum(x => x.Outcome == 0?x.SamplingWeight:0)
};
您有两个容易看到的选项:
- 求和前使用
.Where()
子句筛选grp
- 在
.Sum()
我认为前者更可读,后者更匹配SQL。根据您的提供者的不同,它们可能会转换为不同的SQL。如果性能有问题,请确保评估结果SQL
from pr in this.context.ComputedPrSet
where
pr.Date.Equals(date) && pr.Scenario.Equals(scenario)
group pr by new { pr.Date, pr.Scenario }
into grp
select new
{
grp.Key.Date,
grp.Key.Scenario,
TruePositiveCount = grp.Where(x => x.outcome == 0).Sum(x => x.SamplingWeight),
FPCount = grp.Sum(x => x.outcome == 1 ? x.SamplingWeight : 0),
};
第三个选项是在DB中按日期、场景和结果分组,然后重新将Select()
放入代码中所需的对象中,如下所示:
this.Context.ComputedPrSet
.Where(pr => pr.Date == date && pr.Scenario == scenario)
.GroupBy(pr => new { pr.Date, pr.Scenario, pr.Outcome })
.Select(grp => new {
grp.Key.Date,
grp.Key.Scenario,
grp.Key.Outcome,
Count = grp.Sum(pr => pr.SamplingWeight)
})
.AsEnumerable()
// .AsEnumerable() will "close" the query in LINQ.
// Further operations are done via LINQ to Objects after fetching the prior results from your DB
.GroupBy(e => new { e.Date, e.Scenario })
.Select(g => new {
g.Key.Date,
g.Key.Scenario,
TruePositiveCount = g.FirstOrDefault(e => e.Outcome == 0),
FPCount = g.FirstOrDefault(e => e.Outcome == 1),
});
您有两个容易看到的选项:
- 求和前使用
.Where()
子句筛选grp
- 在
.Sum()
我认为前者更可读,后者更匹配SQL。根据您的提供者的不同,它们可能会转换为不同的SQL。如果性能有问题,请确保评估结果SQL
from pr in this.context.ComputedPrSet
where
pr.Date.Equals(date) && pr.Scenario.Equals(scenario)
group pr by new { pr.Date, pr.Scenario }
into grp
select new
{
grp.Key.Date,
grp.Key.Scenario,
TruePositiveCount = grp.Where(x => x.outcome == 0).Sum(x => x.SamplingWeight),
FPCount = grp.Sum(x => x.outcome == 1 ? x.SamplingWeight : 0),
};
第三个选项是在DB中按日期、场景和结果分组,然后重新将Select()
放入代码中所需的对象中,如下所示:
this.Context.ComputedPrSet
.Where(pr => pr.Date == date && pr.Scenario == scenario)
.GroupBy(pr => new { pr.Date, pr.Scenario, pr.Outcome })
.Select(grp => new {
grp.Key.Date,
grp.Key.Scenario,
grp.Key.Outcome,
Count = grp.Sum(pr => pr.SamplingWeight)
})
.AsEnumerable()
// .AsEnumerable() will "close" the query in LINQ.
// Further operations are done via LINQ to Objects after fetching the prior results from your DB
.GroupBy(e => new { e.Date, e.Scenario })
.Select(g => new {
g.Key.Date,
g.Key.Scenario,
TruePositiveCount = g.FirstOrDefault(e => e.Outcome == 0),
FPCount = g.FirstOrDefault(e => e.Outcome == 1),
});
grp.Where(x=>x.output==1).Sum(x=>x.SamplingWeight)
grp.Where(x=>x.output==1).Sum(x=>x.SamplingWeight)