C# 通过id与linq连接集合

我有一个对象集合

var myData = new[]
{
    new {
        ID = "1285",
        COUNT = 45
    },
    new {
        ID = "1286",
        COUNT = 156
    },
    new {
        ID = "1287",
        COUNT = 965
    }
};

我的另一个收藏来自另一个数据源，如下所示：

var incomingData = new[]
{
    new {
        ID = "1285",
        LOCATION = "City-1"
    },
    new {
        ID = "1286",
        LOCATION = "City-2"
    },
    new {
        ID = "1287",
        LOCATION = "City-3"
    }
};

var result= 
    (
        from data in myData
        join inData in incomingData
            on data.ID equals inData.ID
        select new
        {
            data.ID,
            inData.LOCATION,
            data.COUNT
        }
    ).ToList();

我想用COUNT属性按Id更改传入数据

var NewData = new[]
{
    new {
        ID = "1285",
        LOCATION = "City-1",
        COUNT = 45
    },
    new {
        ID = "1286",
        LOCATION = "City-2",
        COUNT = 156
    },
    new {
        ID = "1287",
        LOCATION = "City-3",
        COUNT = 965
    }
};

---

如何使用linq labda函数实现这一点。我不想使用foreach循环。（

myData

和

incomingData

收集长度可能不同）

只需使用如下普通连接语句：

var incomingData = new[]
{
    new {
        ID = "1285",
        LOCATION = "City-1"
    },
    new {
        ID = "1286",
        LOCATION = "City-2"
    },
    new {
        ID = "1287",
        LOCATION = "City-3"
    }
};

var result= 
    (
        from data in myData
        join inData in incomingData
            on data.ID equals inData.ID
        select new
        {
            data.ID,
            inData.LOCATION,
            data.COUNT
        }
    ).ToList();

---

简单易读

只需使用以下普通连接语句：

var incomingData = new[]
{
    new {
        ID = "1285",
        LOCATION = "City-1"
    },
    new {
        ID = "1286",
        LOCATION = "City-2"
    },
    new {
        ID = "1287",
        LOCATION = "City-3"
    }
};

var result= 
    (
        from data in myData
        join inData in incomingData
            on data.ID equals inData.ID
        select new
        {
            data.ID,
            inData.LOCATION,
            data.COUNT
        }
    ).ToList();

---

简单易读

如果集合长度不同，那么一个集合中的元素在另一个集合中不会出现，该怎么办？只有匹配的项目才会出现？我明白了，谢谢：）我想我想我已经想得太多了！如果集合的长度不同，那么一个集合中没有出现在另一个集合中的元素会发生什么情况？只有匹配的项目才会出现？我明白了，谢谢：）我想我考虑得太多了！“简单易懂”-非常好！“简单易懂”-非常好！