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C# 如何在C中从JSON节点路径创建JSON对象#_C#_Arrays_Json_Json.net_Json Path Expression - Fatal编程技术网

C# 如何在C中从JSON节点路径创建JSON对象#

C# 如何在C中从JSON节点路径创建JSON对象#,c#,arrays,json,json.net,json-path-expression,C#,Arrays,Json,Json.net,Json Path Expression,我想从键值对映射JSON路径属性,以在C#中生成JSON对象,其中路径包含嵌套数组索引路径 输入: Dictionary<string, string> properties = new Dictionary<string, string>(); properties.put("id", "1"); properties.put("name", "sample_name"); properti

我想从键值对映射JSON路径属性,以在C#中生成JSON对象,其中路径包含嵌套数组索引路径

输入:

Dictionary<string, string> properties = new Dictionary<string, string>();
properties.put("id", "1");
properties.put("name", "sample_name");
properties.put("category.id", "1");
properties.put("category.name", "sample");
properties.put("tags[0].id", "1");
properties.put("tags[0].name", "tag1");
properties.put("tags[1].id", "2");
properties.put("tags[1].name", "tag2");
properties.put("status", "available");
使用它可以很容易地实现,如:

JavaPropsMapper javaPropsMapper = new JavaPropsMapper();
JsonNode json = javaPropsMapper.readMapAs(properties, JsonNode.class);

如何在C#中实现这个想法,以便我能够从给定的JSON路径节点生成JSON对象。

您可以创建一个序列化的匿名对象

            var values = new { 
                id = "id",
                name = "name",
                category = new { id = 1, name = "sample"},
                tags = new { id = 0, name = "sample" },
                status = "available"
            }; 
            string json = JsonConvert.SerializeObject(values);

您使用的是哪个JSON serialiser?我使用的是Newtonsoft JSON Serializer类似的问题:首先,如何解析字典中的给定表达式,例如标记[0].id。我的输入本质上是动态的。我可以得到生成JSON节点所需的任何类型的表达式
            var values = new { 
                id = "id",
                name = "name",
                category = new { id = 1, name = "sample"},
                tags = new { id = 0, name = "sample" },
                status = "available"
            }; 
            string json = JsonConvert.SerializeObject(values);