C# 使用linq将带有子节点的XML转换为csv格式
我需要一些帮助,将带有子节点的XML转换为csv文件 以下是我的XML:C# 使用linq将带有子节点的XML转换为csv格式,c#,xml,linq,export-to-csv,C#,Xml,Linq,Export To Csv,我需要一些帮助,将带有子节点的XML转换为csv文件 以下是我的XML: <Main> <root> <Name>Sample name1</Name> <StreetAddress>Sample Address1</StreetAddress> <Service> <Type>Outlet</Type> <PhoneNumber&
<Main>
<root>
<Name>Sample name1</Name>
<StreetAddress>Sample Address1</StreetAddress>
<Service>
<Type>Outlet</Type>
<PhoneNumber></PhoneNumber>
<Openweekday>Closed</Openweekday>
</Service>
<Service>
<Type>Mall</Type>
<PhoneNumber></PhoneNumber>
<Openweekday>Closed</Openweekday>
</Service>
</root>
<root>
<Name>Sample name2</Name>
<StreetAddress>Sample Address2</StreetAddress>
<Service>
<Type>Shop</Type>
<PhoneNumber></PhoneNumber>
<Openweekday>Closed</Openweekday>
</Service>
</Main>
尝试了我从MSDN获得的代码。但它抛出一个空异常-
XElement custOrd = XElement.Load("xxx.xml");
string csv =
(from el in custOrd.Element("Main").Elements("root")
select
String.Format("{0},{1},{2},{3},{4},{5},{6},{7}",
(string)el.Attribute("Name"),
(string)el.Element("StreetAddress"),
(string)el.Element("Service").Element("Type"),
(string)el.Element("Service").Element("PhoneNumber"),
(string)el.Element("Service").Element("Openweekday"),
(string)el.Element("Service").Element("Type"),
(string)el.Element("Service").Element("PhoneNumber"),
(string)el.Element("Service").Element("Openweekday"),
Environment.NewLine
)
)
.Aggregate(
new StringBuilder(),
(sb, s) => sb.Append(s),
sb => sb.ToString()
);
Console.WriteLine(csv);
让我知道如何在linq中管理空值。实际问题是
custOrd
它本身已经引用了
,因此在custOrd
上调用元素(“Main”)
将返回null
,并调用元素(“root”)null
上的
肯定会触发null引用异常
要解决该问题,您可以将custOrd
更改为XDocument
类型:
XDocument custOrd = XDocument.Load("xxx.xml");
…或只需删除.Element(“Main”)
调用:
XElement custOrd = XElement.Load("xxx.xml");
string csv =
(from el in custOrd.Elements("root")
......
......
将
null
强制转换为字符串是安全的,但是如果有任何
没有子元素
您的代码将再次抛出null引用异常。正如其他人在加载或解析xml时提到的,main已经被引用,因此您的起点应该是root。
这将为您提供所需的结构
XElement dataSet1Tree = XElement.Parse(xml);
var dataSet1List = dataSet1Tree.Elements().Select(
root => new
{
Name = (string)root.Element("Name"),
StreetAddress = (string)root.Element("StreetAddress"),
Service = root.Elements("Service")
.Select(service => new
{
Type = (string)service.Element("Type"),
PhoneNumber = (string)service.Element("PhoneNumber"),
OpenWeekDay = (string)service.Element("Openweekday")
})
}).SelectMany(root => root.Service, (root, service) => new
{
Name = root.Name,
StreetAddress = root.StreetAddress ,
Type = service.Type,
PhoneNumber = service.PhoneNumber,
OpenWeekDay = service.OpenWeekDay
}).Aggregate("",(sb,s)=> sb +=string.Format("{0},{1},{2},{3},{4}",
s.Name,
s.StreetAddress,
s.Type,
s.PhoneNumber,
s.OpenWeekDay)+"\r\n");
Console.WriteLine(dataSet1List);
@paqogomez的可能重复-如何在linq中为每个元素管理null?当服务节点丢失时,如何处理?我是linq的新手。@paqogomez-你添加的重复参考帖子没有回答我的问题?你能把它移走让其他人帮我吗?除了你没人看到,尽管其他人可以投票决定它是否真的是重复的。到目前为止,只有一个人同意我的观点。至于你的问题,在我看来,内联if语句可以解决你的问题。类似于
el.Element(“服务”).Element(“电话号码”)==null?“”:el.Element(“服务”).Element(“电话号码”)代码>,我提供的重复链接中很好地介绍了内联语句。
XElement dataSet1Tree = XElement.Parse(xml);
var dataSet1List = dataSet1Tree.Elements().Select(
root => new
{
Name = (string)root.Element("Name"),
StreetAddress = (string)root.Element("StreetAddress"),
Service = root.Elements("Service")
.Select(service => new
{
Type = (string)service.Element("Type"),
PhoneNumber = (string)service.Element("PhoneNumber"),
OpenWeekDay = (string)service.Element("Openweekday")
})
}).SelectMany(root => root.Service, (root, service) => new
{
Name = root.Name,
StreetAddress = root.StreetAddress ,
Type = service.Type,
PhoneNumber = service.PhoneNumber,
OpenWeekDay = service.OpenWeekDay
}).Aggregate("",(sb,s)=> sb +=string.Format("{0},{1},{2},{3},{4}",
s.Name,
s.StreetAddress,
s.Type,
s.PhoneNumber,
s.OpenWeekDay)+"\r\n");
Console.WriteLine(dataSet1List);