C# 在结构c中填充数组#
我试图用一些值填充结构中包含的数组,但无论我怎么做,都会不断出错 我的结构是这样的C# 在结构c中填充数组#,c#,arrays,struct,assign,C#,Arrays,Struct,Assign,我试图用一些值填充结构中包含的数组,但无论我怎么做,都会不断出错 我的结构是这样的 public struct boardState { public int structid; public char[] state; } boardState _state_ = new boardState(); _state_.structid = 1; _state_.state[9] = {'o','-','-','-'
public struct boardState
{
public int structid;
public char[] state;
}
boardState _state_ = new boardState();
_state_.structid = 1;
_state_.state[9] = {'o','-','-','-','o','-','-','-','-','o'};
在初始值设定项中,我正在创建一个新的boardState,并尝试用如下值填充它
public struct boardState
{
public int structid;
public char[] state;
}
boardState _state_ = new boardState();
_state_.structid = 1;
_state_.state[9] = {'o','-','-','-','o','-','-','-','-','o'};
structid似乎工作正常,但我在{'o','-'etc}告诉我'时出错;期望'。我已经阅读了上面的代码并确保没有;'缺少(由没有此行的程序运行确认),因此我猜您不能以这种方式分配给数组。如何分配给状态数组
编辑:-添加了我遗漏的逗号,但仍然得到相同的错误。您遗漏了一个逗号,语法已关闭 发件人:
_state_.state[9] = {'o','-','-','-','o','-','-','-','-''o'};
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
至:
_state_.state[9] = {'o','-','-','-','o','-','-','-','-''o'};
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
您缺少一个逗号,语法已关闭 发件人:
_state_.state[9] = {'o','-','-','-','o','-','-','-','-''o'};
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
至:
_state_.state[9] = {'o','-','-','-','o','-','-','-','-''o'};
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
您不需要
[9]
。它尝试将数组分配给单个字符。相反,只需使用以下命令:
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
您不需要
[9]
。它尝试将数组分配给单个字符。相反,只需使用以下命令:
_state_.state = new char [] {'o','-','-','-','o','-','-','-','-','o'};
谢谢你指出这一点。我加了那个逗号,但还是有同样的错误。谢谢你指出这一点。我添加了逗号,但我仍然得到相同的错误提示:请考虑使用类而不是结构。或者请确认您知道在C#中使用struct的后果是什么()我只想说我同意Alexei的观点,并补充说您有一个可变的struct,这通常被认为是一个坏主意。此外,通过在结构中有一个对象,结构的大部分目的都消失了。或者请确认您知道在C#中使用struct的后果是什么()我只想说我同意Alexei的观点,并补充说您有一个可变的struct,这通常被认为是一个坏主意。而且,通过在结构中拥有一个对象,结构的大部分用途都消失了。