C# 尝试以其他表单访问listview项
这是我的表格。这里有一个名为ListViewSelectedItems的listview集合,用于以另一种形式访问我的listview1项C# 尝试以其他表单访问listview项,c#,.net,winforms,listview,C#,.net,Winforms,Listview,这是我的表格。这里有一个名为ListViewSelectedItems的listview集合,用于以另一种形式访问我的listview1项 using System; using System.Windows.Forms; using System.Data.SqlClient; using static System.Windows.Forms.VisualStyles.VisualStyleElement; namespace sundayschoolproject {
using System;
using System.Windows.Forms;
using System.Data.SqlClient;
using static System.Windows.Forms.VisualStyles.VisualStyleElement;
namespace sundayschoolproject
{
public partial class Form1 : Form
{
string con = ("Data Source =ZTABASSUM\\SQLEXPRESS01;Initial Catalog= Sunday School;Integrated Security=True");
public System.Windows.Forms.ListView.SelectedListViewItemCollection ListViewSelectedItems
{
get { return listView1.SelectedItems; }
}
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
listView1.GridLines = true;
listView1.View = View.Details;
//Add Columns
listView1.Columns.Add("ParentName", 100);
listView1.Columns.Add("Address", 150);
listView1.Columns.Add("City", 100);
listView1.Columns.Add("State", 50);
listView1.Columns.Add("Zipcode", 100);
listView1.Columns.Add("Phone", 150);
}
private void button1_Click(object sender, EventArgs e)
{
string sql = ("Select * from Family");
SqlConnection connection = new SqlConnection(con);
SqlCommand cmd = new SqlCommand(sql, connection);
connection.Open();
SqlDataReader dr = cmd.ExecuteReader();
listView1.Items.Clear();
while (dr.Read())
{
ListViewItem lv = new ListViewItem(dr.GetString(0));
lv.SubItems.Add(dr.GetString(1));
lv.SubItems.Add(dr.GetString(2));
lv.SubItems.Add(dr.GetString(3));
lv.SubItems.Add(dr.GetString(4));
lv.SubItems.Add(dr.GetString(5));
listView1.Items.Add(lv);
}
dr.Close();
connection.Close();
}
//registered a listview1_click handler and then if name is clicked, a new form pops up
private void listView1_Click(object sender, EventArgs e)
{
if (listView1.SelectedItems.Count > 0)
{
Form2 frm = new Form2();
frm.Show();
MessageBox.Show("You clicked " + listView1.SelectedItems[0].Text);
ListViewItem item1 = listView1.SelectedItems[0];
MessageBox.Show("Person's phone number is " + item1.SubItems[5].Text);
}
else
{
MessageBox.Show("Please select an item");
}
}
}
}
这是我的表格2,名为frm。在这里,我创建了一个名为otherForm的form1实例
using System;
using System.Data;
using System.Windows.Forms;
using System.Data.SqlClient;
namespace sundayschoolproject
{
public partial class Form2 : Form
{
public Form2()
{
InitializeComponent();
Text = "Form2";
}
SqlConnection connection = new SqlConnection("Data Source=ZTABASSUM\\SQLEXPRESS01;Initial Catalog= Sunday School;Integrated Security=True");
SqlCommand comm;
SqlDataReader dreader;
private void frm_Load(object sender, EventArgs e)
{
connection.Open();
MessageBox.Show(otherForm.hello);
MessageBox.Show(otherForm.ListViewSelectedItems[0].Text);
}
}
但是,第二个消息框不会在索引处显示所选项目,表示索引超出范围?即使那里有一个项目。非常感谢你的帮助 你应该用自己的话意识到这个问题。你说: 在这里,我创建了我的form1的一个实例 您不需要创建该表单的新实例,因为它是一个新实例,一个不同的实例 您需要向
Form2
的构造函数传递Form1
的实例,该实例包含您正在处理的数据(状态)
public Form2(Form1 form1)
{
InitializeComponent();
Text = "Form2";
otherForm = form1;
}
来电者:
Form2 form2 = new Form2(this);
可以调用者到哪里去了?您如何启动
Form2
?这不是在表格1
中的某个点或事件中吗?您正在创建的表单可能是调用.Show
或.ShowDialog
。哦,是的!我懂了!非常感谢!你为什么不选择一个被接受的答案就离开你的问题?这是一个简单的点击:。。。是的,我对答案投了赞成票?勾选此链接:您需要勾选(向下投票按钮)下方的复选标记,以便将其标记为正确答案(绿色复选标记)