C# 如何搜索和导航XML节点

我有以下XML：

<LOCALCELL_V18 ID = "0x2d100000">
  <MXPWR ID = "0x3d1003a0">100</MXPWR> 
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d140000">
  <MXPWR ID = "0x3d1403a0">200</MXPWR>  
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d180000">  
  <MXPWR ID = "0x3d1803a0">300</MXPWR>   
</LOCALCELL_V18> 

100
200
300

我想获得每个

的内部文本。但是，不允许使用ID#　查找内部文本，因为它并不总是相同的。这是我的密码：

XmlNodeList LocalCell = xmlDocument.GetElementsByTagName("LOCALCELL_V18");

foreach (XmlNode LocalCell_Children in LocalCell)
{
    XmlElement MXPWR = (XmlElement)LocalCell_Children;
    XmlNodeList MXPWR_List = MXPWR.GetElementsByTagName("MXPWR");
    for (int i = 0; i < MXPWR_List.Count; i++)
    {
       MaxPwr_form_str = MXPWR_List[i].InnerText;
    }
}

XmlNodeList LocalCell=xmlDocument.GetElementsByTagName（“LocalCell_V18”）；
foreach（XmlNode LocalCell_LocalCell中的子节点）
{
XmlElement MXPWR=（XmlElement）LocalCell_子项；
XmlNodeList MXPWR_List=MXPWR.GetElementsByTagName（“MXPWR”）；
对于（int i=0；i

如有任何意见，将不胜感激

我会用。它就是为这类问题设计的。比如：

using System.Xml;
using System.Xml.XPath;
....
string fileName = "data.xml"; // your file here
XPathDocument doc = new XPathDocument(fileName);
XPathNavigator nav = doc.CreateNavigator();

// Compile an xpath expression
XPathExpression expr = nav.Compile("./LOCALCELL_V18/MXPWR");
XPathNodeIterator iterator = nav.Select(expr);

// Iterate on the node set
while (iterator.MoveNext())
{
    string s = iterator.Current.Value;
}

当我在XML文件（包装在根节点中）上运行此操作时，我得到：

我会使用XLinq：

using System.Xml.Linq;

var xDoc = XDocument.Load("data.xml");

var mxpwrs = xDoc.Descendants("MXPWR");
foreach (var mxpwr in mxpwrs)
{
    Console.WriteLine(mxpwr.Value);
}

---

Linq的完美使用消除了对Xpath的需求。

using System.Xml.Linq;

var xDoc = XDocument.Load("data.xml");

var mxpwrs = xDoc.Descendants("MXPWR");
foreach (var mxpwr in mxpwrs)
{
    Console.WriteLine(mxpwr.Value);
}