C# 计算两个数组的数目之差

对于A中的每个数字和B中的每个数字，如果其差值大于3，则添加新数字

A={6,7,10}
B={2,3}
result={4,5,4,8,7}

例如：

6-2=4真加4

6-3=3假

7-2=5真加5

我的尝试：

  var result = A.Select((a, i) => new
  {
   desired = a - B[i] > 3 ? a - B[i] :0

   });

---

听起来你想要：

var query = from a in A
            from b in B
            let diff = a - b
            where diff > 3
            select diff;

或者用点表示法，非常整齐地掉出来：

var query = A.SelectMany(a => B, (a, b) => a - b)
             .Where(x => x > 3);

使用您的测试数据：

using System;
using System.Linq;

class Test
{
    public static void Main()        
    {
        int[] A = {6, 7, 10};
        int[] B = {2, 3};

        var query = A.SelectMany(a => B, (a, b) => a - b)
                     .Where(x => x > 3);

        foreach (var result in query)
        {
            Console.WriteLine(result);
        }
    }
}

---

听起来你想要：

var query = from a in A
            from b in B
            let diff = a - b
            where diff > 3
            select diff;

或者用点表示法，非常整齐地掉出来：

var query = A.SelectMany(a => B, (a, b) => a - b)
             .Where(x => x > 3);

使用您的测试数据：

using System;
using System.Linq;

class Test
{
    public static void Main()        
    {
        int[] A = {6, 7, 10};
        int[] B = {2, 3};

        var query = A.SelectMany(a => B, (a, b) => a - b)
                     .Where(x => x > 3);

        foreach (var result in query)
        {
            Console.WriteLine(result);
        }
    }
}

也许你在找也许你在找