C# 将数字字符串读入网格/矩阵

有人能告诉我如何将这个网格读入像[I][j]这样的数组吗？我在谷歌上搜索过，但似乎找不到任何有用的东西。非常感谢你的帮助

static void Main(string[] args)
    {
       String grid =    "08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08" +
                        "49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00" +
                        "81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65" +
                        "52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91" +
                        "22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80" +
                        "24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50" +
                        "32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70" +
                        "67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21" +
                        "24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72" +
                        "21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95" +
                        "78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92" +
                        "16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57" +
                        "86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58" + 
                        "19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40" +
                        "04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66" +
                        "88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69" +
                        "04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36" +
                        "20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16" +
                        "20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54" +
                        "01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48";

     int[] a = new int[20];

        for(int i=0;i<20;i++)
            for (int j = 1; j < 20; j++)
            {

            }


    }

static void Main（字符串[]args）
{
字符串网格=“08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08”+
"49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00" +
"81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65" +
"52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91" +
"22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80" +
"24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50" +
"32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70" +
"67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21" +
"24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72" +
"21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95" +
"78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92" +
"16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57" +
"86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58" + 
"19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40" +
"04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66" +
"88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69" +
"04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36" +
"20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16" +
"20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54" +
"01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48";
int[]a=新的int[20]；
对于（int i=0；i考虑在每个“行”的末尾添加一个空格，如下所示：

String grid =    "08 02 .. 91 08 " +
                 "01 70 .. 67 48 ";
                             // ^-- add space here 

这将允许使用
string.Split
将字符串简单地转换为一维字符串数组

string grid = "08 02 .. 91 08";       // every number is space-separated now
string[] gridArray = grid.Split(" "); // -> ["08", "02", .. "91", "08"]

（即使不保证额外的空间，也可以使用正则表达式split实现1D数组：
var gridArray=Regex.split（grid），（？：\s |）（？考虑在每个“行”的末尾添加一个空间，例如：

String grid =    "08 02 .. 91 08 " +
                 "01 70 .. 67 48 ";
                             // ^-- add space here 

这将允许使用
string.Split
将字符串简单地转换为一维字符串数组

string grid = "08 02 .. 91 08";       // every number is space-separated now
string[] gridArray = grid.Split(" "); // -> ["08", "02", .. "91", "08"]

（即使没有确保额外的空格，也可以使用正则表达式拆分实现1D数组：
var gridArray=Regex.split（grid，（？：\s |）（？）正如注释中建议的那样，您可以简单地分隔数字并使用拆分字符串。例如：

    private static void Main(string[] args)
    {
        String grid = "08,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,08," +
                      "49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00," +
                      "81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65," +
                      "52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91," +
                      "22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80," +
                      "24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50," +
                      "32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70," +
                      "67,26,20,68,02,62,12,20,95,63,94,39,63,08,40,91,66,49,94,21," +
                      "24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72," +
                      "21,36,23,09,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95," +
                      "78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,09,53,56,92," +
                      "16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57," +
                      "86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58," +
                      "19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40," +
                      "04,52,08,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66," +
                      "88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69," +
                      "04,42,16,73,38,25,39,11,24,94,72,18,08,46,29,32,40,62,76,36," +
                      "20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16," +
                      "20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54," +
                      "01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48";

        var splitstring = grid.Split(',');
        var a = new int[20,20];

        const int rowCount = 19; //counts 0 as 1
        var rowIndex = 0;
        var colIndex = 0;

        foreach (var s in splitstring)
        {
            if (rowIndex > rowCount)
            {
                rowIndex = 0;
                colIndex++;
            }
            a[colIndex, rowIndex] = Int32.Parse(s);
            rowIndex++;
        }
    }

请注意，如果解析失败，
Int32.Parse
将引发异常。您可以改为使用
Int32.TryParse
并使用out值作为结果。这取决于您要执行的操作。
根据注释中的建议，您可以简单地分隔数字并使用拆分字符串。例如：

    private static void Main(string[] args)
    {
        String grid = "08,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,08," +
                      "49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00," +
                      "81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65," +
                      "52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91," +
                      "22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80," +
                      "24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50," +
                      "32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70," +
                      "67,26,20,68,02,62,12,20,95,63,94,39,63,08,40,91,66,49,94,21," +
                      "24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72," +
                      "21,36,23,09,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95," +
                      "78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,09,53,56,92," +
                      "16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57," +
                      "86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58," +
                      "19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40," +
                      "04,52,08,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66," +
                      "88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69," +
                      "04,42,16,73,38,25,39,11,24,94,72,18,08,46,29,32,40,62,76,36," +
                      "20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16," +
                      "20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54," +
                      "01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48";

        var splitstring = grid.Split(',');
        var a = new int[20,20];

        const int rowCount = 19; //counts 0 as 1
        var rowIndex = 0;
        var colIndex = 0;

        foreach (var s in splitstring)
        {
            if (rowIndex > rowCount)
            {
                rowIndex = 0;
                colIndex++;
            }
            a[colIndex, rowIndex] = Int32.Parse(s);
            rowIndex++;
        }
    }

请注意，如果解析失败，
Int32.Parse
将引发异常。您可以改为使用
Int32.TryParse
并使用out值作为结果。这取决于您要执行的操作。
我看到了代码的良好开端，但没有“提取”数字的功能。为了简化此问题，请编写字符串，使每个“行”都也以空格结尾：
“01..48”+
。然后可以在基于i和j以及
字符串的特定偏移量处找到每个数字。子字符串
可用于直接提取它；或
字符串。拆分（“”
可用于将原始字符串转换为也可以索引（基于i和j）的1D数组或者迭代。我是一个初学者，正在做Euler项目。到了这里，我似乎找不到任何东西来提取数字。我只找到了java提取方法，但在这一个上，似乎没有找到。我做了int[][]a=new int[][]；但这给了我一个错误，我不知道如何创建一个具有2个坐标的数组……数组在创建时必须给定一个大小，因为它们的大小以后不能更改。在C#中，
new int[20][]
（类型为
int[][]
）将创建一个锯齿状数组（创建可容纳20个数组的数组，每个子数组为空，以后必须显式创建）和
newint[20,20]
（类型
int[，]
）将创建一个。m维数组功能非常适合此任务。您的主要问题是，每行的最后一个数字将与下一行的第一个数字合并；两者之间没有分隔符。正如@user2864740所指出的，u应该在每个字符串的末尾放置某种分隔符。我在or中修复了此问题原始代码。我创建了int[，]a=new int[20,20]。现在我需要从字符串中减去值，并使用parseint将它们转换为整数。我现在的问题是如何提取它们，因为我知道如何转换它们。我看到了代码的良好开端，但没有什么可以“提取”的数字。为了简化此问题，请编写字符串，使每个“行”也以空格结尾：
“01..48”+
。然后可以在基于i和j的特定偏移量处找到每个数字，并
字符串。可以使用子字符串
直接提取它；或者
字符串.Split（“”）
可用于将原始字符串转换为1D数组，该数组也可以被索引（基于i和j）或迭代。我是一名初学者，正在进行Euler项目。到了这里，我似乎找不到任何东西来提取数字。我只找到了java提取方法，但在这一个上，似乎没有找到。我找到了int[][]a=new int[]；但这给了我一个错误，我不知道如何拥有一个具有2个坐标的数组……数组在创建时必须给定一个大小，因为它们的大小以后不能更改。在C#，
ne中