C# 如何通过读取xml文件从C中的Dataset和Datatables创建HTML表
我对C语言非常陌生,我正在阅读C语言中的XML文件,希望以表格形式在邮件中发送XML文件数据 XML文件是:C# 如何通过读取xml文件从C中的Dataset和Datatables创建HTML表,c#,xml,c#-4.0,C#,Xml,C# 4.0,我对C语言非常陌生,我正在阅读C语言中的XML文件,希望以表格形式在邮件中发送XML文件数据 XML文件是: <log> <logentry version='123'> <author>Dexter</author> <date>12 July 2017</date> <paths> <path action="M">C:\Desktop</pa
<log>
<logentry version='123'>
<author>Dexter</author>
<date>12 July 2017</date>
<paths>
<path action="M">C:\Desktop</path>
<path action="N">C:\Documents\test.txt</path>
</paths>
<msg>Added New file</msg>
</logentry>
<logentry version='124'>
<author>Dexter2</author>
<date>11 July 2017</date>
<paths>
<path action="M">C:\Desktop\Test\mail.cp</path>
</paths>
<msg>Added New file in test folder</msg>
</logentry>
</log>
假设您希望我们的邮件使用HTML,您只需要构建一个包含HTML的字符串。循环遍历数据集,并使用标记中数据集的值为每一行创建HTML
尝试一下,如果您有问题,请发布代码并解释您的问题。以下代码将创建DataTable
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
DataTable dt = new DataTable();
dt.Columns.Add("version", typeof(int));
dt.Columns.Add("date", typeof(DateTime));
dt.Columns.Add("author", typeof(string));
dt.Columns.Add("msg", typeof(string));
dt.Columns.Add("paths", typeof(string));
dt.Columns.Add("action", typeof(string));
XDocument doc = XDocument.Load(FILENAME);
foreach(XElement logentry in doc.Descendants("logentry"))
{
foreach(XElement path in logentry.Descendants("path"))
{
dt.Rows.Add(new object[] {
(int)logentry.Attribute("version"),
(DateTime)logentry.Element("date"),
(string)logentry.Element("author"),
(string)logentry.Element("msg"),
(string)path.FirstNode.ToString(),
(string)path.Attribute("action")
});
}
}
}
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
DataTable dt = new DataTable();
dt.Columns.Add("version", typeof(int));
dt.Columns.Add("date", typeof(DateTime));
dt.Columns.Add("author", typeof(string));
dt.Columns.Add("msg", typeof(string));
dt.Columns.Add("paths", typeof(string));
dt.Columns.Add("action", typeof(string));
XDocument doc = XDocument.Load(FILENAME);
foreach(XElement logentry in doc.Descendants("logentry"))
{
foreach(XElement path in logentry.Descendants("path"))
{
dt.Rows.Add(new object[] {
(int)logentry.Attribute("version"),
(DateTime)logentry.Element("date"),
(string)logentry.Element("author"),
(string)logentry.Element("msg"),
(string)path.FirstNode.ToString(),
(string)path.Attribute("action")
});
}
}
}
}
}