C# 用于WPF显示的计时器，具有奇怪的行为

我用WPF制作了一个有几个按钮的面板。 当鼠标进入某个按钮时，会出现新按钮，并在鼠标离开1000毫秒后消失

但我有一个奇怪的行为：在某些情况下，1000毫秒在每次使用后变得越来越短

计时器事件

private void TimerEventProcessorForButtonA(Object myObject, EventArgs myEventArgs)
{
    _myTimerForButtonA.Stop(); 
    miniButton1.Visibility = System.Windows.Visibility.Hidden;
}

private void TimerEventProcessorForButtonB(Object myObject, EventArgs myEventArgs)
{
    _myTimerForButtonB.Stop(); 
    miniButton2.Visibility = System.Windows.Visibility.Hidden;
}

WaitTime函数调用计时器：

public void WaitThisTimeAndHideMiniButton1(int givenTime)
{
    _myTimerForButtonA = new System.Windows.Forms.Timer();
    _myTimerButtonA.Tick += new EventHandler(TimerEventProcessorForForButtonA);
    _myTimerForForButtonA.Interval = givenTime;
    _myTimerForForButtonA.Start();
}

public void WaitThisTimeAndHideMiniButton2(int givenTime)
{
    _myTimerForButtonB = new System.Windows.Forms.Timer();
    _myTimerForButtonB.Tick += new EventHandler(TimerEventProcessorForForButtonB);
    _myTimerForForButtonB.Interval = givenTime;
    _myTimerForForButtonB.Start();
}

“离开”按钮时发生的事件：

private void buttonA_MouseLeave(object sender, System.Windows.Input.MouseEventArgs e)
{
    Border button = sender as Border;
    button.Background = (SolidColorBrush)new BrushConverter().ConvertFromString(_colorOut);
    WaitThisTimeAndHideMiniButton1(1000); // hide minibuttons
}

private void buttonB_MouseLeave(object sender, System.Windows.Input.MouseEventArgs e)
{
    Border button = sender as Border;
    button.Background = (SolidColorBrush) new BrushConverter().ConvertFromString(_colorOut);
    WaitThisTimeAndHideMiniButton2(1000);
}

如代码中所述，我有buttonA和buttonB。当我输入buttonA时，miniButton1出现-它将在鼠标离开事件1000毫秒后消失。 buttonB和miniButton2一样

如果我只按进出按钮，一切都是正确的。和ButtonA一样。 问题：如果我输入/离开按钮A和B，那么这1000毫秒会越来越短。在我离开按钮A和B之前，迷你按钮也会消失。在我离开按钮之前，迷你按钮也会消失

每件事都表现得好像计时器在互相混淆。

---

你知道怎么解决吗？

所以基本上这是在鼠标离开时发生的：

creating the timer
starting the timer

当计时器过期时会发生这种情况：

stopping the timer

所以，若鼠标反复进入和离开一个按钮，它会不断创建和启动新的计时器。这会导致多个计时器同时运行

public void WaitThisTimeAndHideMiniButton1(int givenTime)
{
    if(_myTimerForButtonA != null && _myTimerForButtonA.Enabled)
    {
         _myTimerForButtonA.Stop();
    }
    _myTimerForButtonA = new System.Windows.Forms.Timer();
    _myTimerButtonA.Tick += new EventHandler(TimerEventProcessorForForButtonA);
    _myTimerForForButtonA.Interval = givenTime;
    _myTimerForForButtonA.Start();
}

---

尽管如评论中所述，此处存在更多问题，但这应该可以解决该问题。

每次触发

MouseLeave

事件时，如果您在1000毫秒内两次触发该事件，您将重新创建一个新的

计时器，在执行上一个
计时器的
勾选事件之前，您将重新创建一个新的
计时器
，这将使上一个
计时器
无限期运行

以下是在1000毫秒内两次触发
MouseLeave
事件时发生的情况：

1) MouseLeave: _myTimerForButtonA is assigned a new Timer instance (ie: Timer1), Tick event registered.
2) MouseLeave: _myTimerForButtonA is assigned a new Timer instance (ie: Timer2), Tick event registered.
3) Timer1.Tick event fires TimerEventProcessorForButtonA, whichs stops _myTimerForButtonA which points to Timer2.
4) Timer2.Tick event fires TimerEventProcessorForButtonA, whichs stops _myTimerForButtonA which points to Timer2 (and is already stopped).
5) Timer1.Tick event fires TimerEventProcessorForButtonA indefinitely, because Timer1 is not referenced anymore and no one will ever call `Stop` on it.

我可以通过停止
MouseEnter
事件上的计时器来修复您的代码

    private void TimerEventProcessorForButtonA(Object myObject, EventArgs myEventArgs)
    {
        Debug.WriteLine("TimerEventProcessorForButtonA");
        _myTimerForButtonA.Stop();
        _myTimerForButtonA.Dispose();
        miniButton1.Visibility = System.Windows.Visibility.Hidden;
    }

    private void TimerEventProcessorForButtonB(Object myObject, EventArgs myEventArgs)
    {
        Debug.WriteLine("** TimerEventProcessorForButtonB");
        _myTimerForButtonB.Stop();
        _myTimerForButtonB.Dispose();
        miniButton2.Visibility = System.Windows.Visibility.Hidden;
    }

    public void WaitThisTimeAndHideMiniButton1(int givenTime)
    {
        _myTimerForButtonA = new System.Windows.Forms.Timer();
        _myTimerForButtonA.Tick += new EventHandler(TimerEventProcessorForButtonA);
        _myTimerForButtonA.Interval = givenTime;
        _myTimerForButtonA.Start();
    }

    public void WaitThisTimeAndHideMiniButton2(int givenTime)
    {
        _myTimerForButtonB = new System.Windows.Forms.Timer();
        _myTimerForButtonB.Tick += new EventHandler(TimerEventProcessorForButtonB);
        _myTimerForButtonB.Interval = givenTime;
        _myTimerForButtonB.Start();
    }

    private void buttonA_MouseLeave(object sender, System.Windows.Input.MouseEventArgs e)
    {
        Border button = sender as Border;
        button.Background = (SolidColorBrush)new BrushConverter().ConvertFromString(_colorOut);
        WaitThisTimeAndHideMiniButton1(1000); // hide minibuttons
    }

    private void buttonB_MouseLeave(object sender, System.Windows.Input.MouseEventArgs e)
    {
        Border button = sender as Border;
        button.Background = (SolidColorBrush)new BrushConverter().ConvertFromString(_colorOut);
        WaitThisTimeAndHideMiniButton2(1000);
    }

    private void buttonA_MouseEnter(object sender, System.Windows.Input.MouseEventArgs e)
    {
        if (_myTimerForButtonA?.Enabled == true)
            _myTimerForButtonA.Stop();
        miniButton1.Visibility = System.Windows.Visibility.Visible;
    }

    private void buttonB_MouseEnter(object sender, System.Windows.Input.MouseEventArgs e)
    {
        if (_myTimerForButtonB?.Enabled == true)
            _myTimerForButtonB.Stop();
        miniButton2.Visibility = System.Windows.Visibility.Visible;
    }

正如你在文章的评论中所说，你不应该每次都创建一个新的
计时器，你应该在完成后处理它。此外，在WPF项目中引用表单是一个坏主意，除非真的有必要，否则很少有必要。您可能需要阅读有关UI动画的内容。
类
System.Windows.Forms.Timer
实现
IDisposable
。在创建新实例之前，是否要先处理以前的每个实例？不这样做可能会导致您的问题。你能试试看这是否能解决问题吗？需要水晶球应用程序。由于重复创建计时器对象，您遇到了麻烦。坏主意不止一种，你抱怨的是，前一个计时器对象仍然在愉快地滴答作响，所以按钮消失得太快了。更糟糕的是，它从未停止过，因为您无法再调用它的Stop（）方法。仅在窗口的构造函数中创建一次计时器对象。使用Closed事件来处置它们。请查看Dispatchermer。不要在WPF应用程序中使用
System.Windows.Forms.Timer
。改用
System.Windows.Threading.dispatchermer
。不需要处理调度程序。如前所述，只创建一次计时器实例。然后反复启动和停止一个现有的计时器。正如前面提到的，我创建了计时器1次，只需使用停止和启动，它就可以工作了@克莱门斯：为什么WPF中不能使用System.Windows.Forms.Timer（实际上它不是winform，但会引发哪个问题）？请阅读此处的备注：