描述属性的C#强类型属性成员

我想知道是否可以声明一个属性属性，该属性描述了一个需要强类型的属性，理想情况下可以使用intellisense来选择该属性。类类型通过将成员声明为TypeType 但如何获取属性作为参数，以便“PropName”不被引用且是强类型的

到目前为止：Attibute类和示例用法如下

 [AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
 public class MyMeta : Attribute{
   public Type SomeType { get; set; }  // works they Way I like.
   // but now some declaration for a property that triggers strong typing 
   // and ideally intellisense support, 
   public PropertyInfo Property { get; set; }    //almost, no intellisence type.Prop "PropName" is required
   public ? SomeProp {get;set;}  //   <<<<<<< any ideas of nice type to define a property
 }

public class Example{
  [MyMeta(SomeType = typeof(SomeOtherClass))]   //is strongly typed and get intellisense support...
  public string SomeClassProp { get; set; }
  [MyMeta(SomeProp = Class.Member)]   // <<< would be nice....any ideas ?
  public string ClassProp2 { get; set; }
  // instead of
  [MyMeta(SomeProp = typeof(T).GetProperty("name" )]   // ... not so nice
  public string ClassProp3 { get; set; }
}

指的是

public class Utilities{
  public static string PropNameAsExpr<TPoco, TProp>(Expression<Func<TPoco, TProp>> prop)
    {
        //var tname = typeof(TPoco);
        var body = prop.Body as System.Linq.Expressions.MemberExpression;
        return body == null ? null : body.Member.Name;
    }
 }

公共类实用程序{
公共静态字符串PropNameAsExpr（表达式属性）
{
//var tname=类型（TPoco）；
var body=prop.body作为System.Linq.Expressions.MemberExpression；
返回body==null？null:body.Member.Name；
}
}

不，不可能。您可以使用

typeof

作为类型名称，但必须使用字符串作为成员名称。这是您所能得到的：

[AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
 public class MyMeta : Attribute{
   public Type SomeType { get; set; }
   public string PropertyName {get;set;}
   public PropertyInfo Property { get { return /* get the PropertyInfo with reflection */; } } 
 }

public class Example{
  [MyMeta(SomeType = typeof(SomeOtherClass))]   //is strongly typed and get intellisense support...
  public string SomeClassProp { get; set; }
  [MyMeta(SomeType = typeof(SomeOtherClass), PropertyName = "SomeOtherProperty")]
  public string ClassProp2 { get; set; }
}

---

好的，谢谢，这不是我希望看到的答案。没有强输入成员作为参数：-（我将标记为答案，直到有人证明你错了；-）再过7分钟

[AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
 public class MyMeta : Attribute{
   public Type SomeType { get; set; }
   public string PropertyName {get;set;}
   public PropertyInfo Property { get { return /* get the PropertyInfo with reflection */; } } 
 }

public class Example{
  [MyMeta(SomeType = typeof(SomeOtherClass))]   //is strongly typed and get intellisense support...
  public string SomeClassProp { get; set; }
  [MyMeta(SomeType = typeof(SomeOtherClass), PropertyName = "SomeOtherProperty")]
  public string ClassProp2 { get; set; }
}