C# 将两个二维数组混合成一个二维数组

我正在尝试将int以前的数组（1和2）存储在一个新数组中的结果。3可以用每个数组2显示来自数组1的每个结果，当我分别显示每个值的结果时，它们是可以的，但是当我尝试将它们混合到数组3中时，我得到了数组1中第一个值与数组2中所有值的正确答案，然后出现了很多零

下面是数组3的代码

for (int i = 0; i < result1.GetLength(0); i++)
          {
               for (int j = 0; j < result1.GetLength(1); j++)
               {
                   for (int k = 0; k < result2.GetLength(0); k++)
                    {
                      for (int m = 0; m < result2.GetLength(1); m++)
                       {

                            result3[i, j] = result1[i, j] + "," + result2[k, m];
                            Console.WriteLine(result3[i, j]);

                            counter++;
                        }
                    }

                }

            }

for（int i=0；i

这是全部代码

double[,] Cranelocations = { { -12.3256, 0.5344 }, { -12.3256, -0.4656 }, { -12.3256, -1.4656 }, { -12.3256, -2.4656 } };

double[,] Picklocation = { { -0.3256, -3.4656 }, { 0.6744, -3.4656 }, { 1.6744, -3.4656 }, { 2.6744, -3.4656 }, { 3.6744, -3.4656 }, { 4.6744, -3.4656 }, { 5.6744, -3.4656 } };

double[,] Setlocation = { { 20.62, 5.03 }, { 24.28, 5.03 }, { 28.40, 5.03 }, { 32.11, 5.03 }, { 35.99, 5.26 }, { 40.18, 5.26 } };

double[] Weights = { 11.7865, 14.7335, 15.1015, 10.7465 };

double[,] result1 = new double[Weights.Length * Cranelocations.GetLength(0), Picklocation.GetLength(0)];

double[,] result2 = new double[Weights.Length * Cranelocations.GetLength(0), Setlocation.GetLength(0)];

object[,] result3 = new object[result1.GetLength(0) * result1.GetLength(1), result2.GetLength(0) * result2.GetLength(1)];

            int counter = 0;

            for (int m = 0; m < Weights.Length; m++)
            {
                for (int i = 0; i < Cranelocations.GetLength(0); i++)
                {
                    for (int j = 0; j < Picklocation.GetLength(0); j++)
                    {


                        double x = Cranelocations[i, 0] - Picklocation[j, 0];
                        double y = Cranelocations[i, 1] - Picklocation[j, 1];

                        result1[i, j] = Weights[m] * (Math.Sqrt(Math.Pow(x, 2) + Math.Pow(y, 2)));


                    }


                }
            }

            Console.WriteLine("-----------------------------------------------------------------");

            for (int m = 0; m < Weights.Length; m++)
            {
                for (int i = 0; i < Cranelocations.GetLength(0); i++)
                {
                    for (int j = 0; j < Setlocation.GetLength(0); j++)
                    {


                        double x = Cranelocations[i, 0] - Setlocation[j, 0];
                        double y = Cranelocations[i, 1] - Setlocation[j, 1];

                        result2[i, j] = Weights[m] * (Math.Sqrt(Math.Pow(x, 2) + Math.Pow(y, 2)));


                    }

                }
            }


            for (int i = 0; i < result1.GetLength(0); i++)
            {
                for (int j = 0; j < result1.GetLength(1); j++)
                {
                    for (int k = 0; k < result2.GetLength(0); k++)
                    {
                        for (int m = 0; m < result2.GetLength(1); m++)
                        {

                            result3[i, j] = result1[i, j] + "," + result2[k, m];
                            Console.WriteLine(result3[i, j]);

                            counter++;

                        }
                    }

                }

            }

}

double[，]Cranelocations={-12.3256,0.5344}，{-12.3256，-0.4656}，{-12.3256，-1.4656}，{-12.3256，-2.4656}；
双[，]选取位置={-0.3256，-3.4656}，{0.6744，-3.4656}，{1.6744，-3.4656}，{2.6744，-3.4656}，{3.6744，-3.4656}，{4.6744，-3.4656}，{5.6744，-3.4656}；
双[，]集合位置={20.62,5.03}，{24.28,5.03}，{28.40,5.03}，{32.11,5.03}，{35.99,5.26}，{40.18,5.26}；
双[]权重={11.7865,14.7335,15.1015,10.7465}；
double[，]result1=新的double[Weights.Length*CranelLocations.GetLength（0），Picklocation.GetLength（0）]；
double[，]result2=新的double[Weights.Length*Cranelocations.GetLength（0），Setlocation.GetLength（0）]；
object[，]result3=新对象[result1.GetLength（0）*result1.GetLength（1），result2.GetLength（0）*result2.GetLength（1）]；
int计数器=0；
对于（int m=0；m

对于每个

m

您将

i

重置为0，然后再次从数组开始写入

当您增加

m

时，需要继续向前移动索引

组合这两个索引时也是如此。当您组合两个迭代以获得索引时，通常将第一个迭代乘以第二个迭代的长度，然后将它们相加

for (int m = 0; m < Weights.Length; m++)
{
    int offset = m * Cranelocations.GetLength(0);

    for (int i = 0; i < Cranelocations.GetLength(0); i++)
    {
        for (int j = 0; j < Picklocation.GetLength(0); j++)
        {
            double x = Cranelocations[i, 0] - Picklocation[j, 0];
            double y = Cranelocations[i, 1] - Picklocation[j, 1];

            result1[i + offset, j] = Weights[m] * (Math.Sqrt(Math.Pow(x, 2) + Math.Pow(y, 2)));
        }
    }
}

Console.WriteLine("-----------------------------------------------------------------");

for (int m = 0; m < Weights.Length; m++)
{
    int offset = m * Cranelocations.GetLength(0);

    for (int i = 0; i < Cranelocations.GetLength(0); i++)
    {
        for (int j = 0; j < Setlocation.GetLength(0); j++)
        {
            double x = Cranelocations[i, 0] - Setlocation[j, 0];
            double y = Cranelocations[i, 1] - Setlocation[j, 1];

            result2[i + offset, j] = Weights[m] * (Math.Sqrt(Math.Pow(x, 2) + Math.Pow(y, 2)));
        }
    }
}

for (int i = 0; i < result1.GetLength(0); i++)
{
    int iOffset = i * result1.GetLength(1);

    for (int j = 0; j < result1.GetLength(1); j++)
    {
        for (int k = 0; k < result2.GetLength(0); k++)
        {
            int kOffset = k * result2.GetLength(1);

            for (int m = 0; m < result2.GetLength(1); m++)
            {
                result3[iOffset + j, kOffset + m] = result1[i, j] + "," + result2[k, m];
                Console.WriteLine(result3[iOffset + j, kOffset + m]);

                counter++;
            }
        }
    }
}

for（int m=0；m

尝试将代码放入，以便我们可以看到结果及其不起作用的原因我使用结果3的目的是将数组结果1中的每个结果与数组结果2中的每个结果放在一起，并如下所示（，）。和