C# 如何在Linq提取方法中使用order by和group by？

我有一个

person

列表，其中包含

person

有一个

weight

和一个

age

属性

Person.cs

：

public class Person
{
    public int Weight { get; set; }
    public int Age { get; set; }
}

List<Person> personList = new List<Person>();

personList.Add(new Person { Age = 15, Weight = 68 });
personList.Add(new Person { Age = 19, Weight = 75 });
personList.Add(new Person { Age = 17, Weight = 68 });
personList.Add(new Person { Age = 15, Weight = 55 });
personList.Add(new Person { Age = 15, Weight = 53 });
personList.Add(new Person { Age = 17, Weight = 88 });
personList.Add(new Person { Age = 19, Weight = 45 });
personList.Add(new Person { Age = 20, Weight = 88 });

//Grouped person list 
List<People> GroupedPersonList = new List<People>();

GroupedPersonList = personList.OrderBy(x => x.Weight).????

Program.cs

：

public class Person
{
    public int Weight { get; set; }
    public int Age { get; set; }
}

List<Person> personList = new List<Person>();

personList.Add(new Person { Age = 15, Weight = 68 });
personList.Add(new Person { Age = 19, Weight = 75 });
personList.Add(new Person { Age = 17, Weight = 68 });
personList.Add(new Person { Age = 15, Weight = 55 });
personList.Add(new Person { Age = 15, Weight = 53 });
personList.Add(new Person { Age = 17, Weight = 88 });
personList.Add(new Person { Age = 19, Weight = 45 });
personList.Add(new Person { Age = 20, Weight = 88 });

//Grouped person list 
List<People> GroupedPersonList = new List<People>();

GroupedPersonList = personList.OrderBy(x => x.Weight).????

---

在LINQ提取方法中如何实现这一点？

您可以像这样使用

GroupBy

：

var GroupedPersonList = personList.GroupBy(x => x.Age , (key,element) => new
{
    Age = key,
    Weight = element.Max(c=>c.Weight)
});

…或类似

var groupedData = from person in people
                  orderby person.Age
                  group person by person.Age into ageGroup
                  select new { Age = ageGroup.Key, MaxWeight = ageGroup.Max(p => p.Weight) };

groupedData.ToList().ForEach(g =>
{
    Console.WriteLine("{0}, {1}", g.Age, g.MaxWeight);
});

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谢谢，祝你今天愉快谢谢，祝你今天愉快