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C# 如何将openFileDialog1.FileName分配给FileInfo[]?_C#_.net_Winforms - Fatal编程技术网

C# 如何将openFileDialog1.FileName分配给FileInfo[]?

C# 如何将openFileDialog1.FileName分配给FileInfo[]?,c#,.net,winforms,C#,.net,Winforms,选择文件名后不存在 文件名没有属性Select为其添加命名空间 FileInfo[] fi = this.openFileDialog1.FileNames.Select(f => new FileInfo(f)).ToArray(); using System.Linq;

选择文件名后不存在 文件名没有属性Select

为其添加命名空间

FileInfo[] fi = this.openFileDialog1.FileNames.Select(f => new FileInfo(f)).ToArray();
using System.Linq;