C# 如何使用Odata从嵌套在列表中的动态数据中进行筛选?
json文件示例C# 如何使用Odata从嵌套在列表中的动态数据中进行筛选?,c#,json,dynamic,filter,odata,C#,Json,Dynamic,Filter,Odata,json文件示例 { "ProjectName": "14010-00 General Expenses", "ClientName": "Whiting", "Created": "2015-06-26T21:06:17.721Z", "Data": { "function": "LIT", "tag": "1461", "rack": "1", "slot": "4", "channel": "1"
{
"ProjectName": "14010-00 General Expenses",
"ClientName": "Whiting",
"Created": "2015-06-26T21:06:17.721Z",
"Data": {
"function": "LIT",
"tag": "1461",
"rack": "1",
"slot": "4",
"channel": "1"
}
},
{
"ProjectName": "104021-00 CPF",
"ClientName": "Bonanza Creek",
"Created": "2015-06-26T21:03:20.732Z",
"Data": {
"tag": "200",
"function": "FT",
"basemodel": "FT-200",
"shortdescription": ""
}
}
我想根据数据的内容进行过滤,但是不同的组件之间差异很大。因此Component.cs文件
public class Component{
public string ClientName{get; set;}
public string ProjectName{get; set;}
...
public IDictionary<string, object> Data { get; set; }
}
将工作;但是,查询在上失败
~/component?$filter=Data/function eq 'FT'
并给出了误差响应
“属性“函数”的属性访问的父值不是单个值。属性访问只能应用于单个值。”然后重试
~/component?$filter=Data/any(d: d/function eq 'FT')
给出错误响应
在类型“System.Collections.Generic.KeyValuePair\u 2OfString\u对象”上找不到名为“function”的属性。
那么,如何根据动态创建的数据对象内部的对象进行过滤,而这些对象并不总是存在的呢?您使用的是Web API OData吗?如果是,
数据
只是动态属性的容器。它不应该出现在有效载荷中。所以你的有效载荷应该是:
{
"Id": "558dbec9940bc716801a95d4",
"FacilityName": "Ray",
"ProjectName": "14010-00 General Expenses",
"ClientName": "Whiting",
"ProjectNames": [],
"Name": "IoList",
"Created": "2015-06-26T21:06:17.721Z",
"Updated": "2015-06-26T21:06:17.721Z",
"function": "LIT",
"tag": "1461",
"rack": "1",
"slot": "4",
"channel": "1"
},{ ...
我建议您使用OData作为数据源,并在对象上使用linq查询,这将自动生成URL中应用的过滤器作为输出。但它是否无法处理仍然存在的数据容器?数据容器?你是指odata客户端吗?不是,我是指包含功能、标签、机架等的数据对象。我认为您可以为“Data”属性创建一个开放的复杂类型来满足您的需求。
{
"Id": "558dbec9940bc716801a95d4",
"FacilityName": "Ray",
"ProjectName": "14010-00 General Expenses",
"ClientName": "Whiting",
"ProjectNames": [],
"Name": "IoList",
"Created": "2015-06-26T21:06:17.721Z",
"Updated": "2015-06-26T21:06:17.721Z",
"function": "LIT",
"tag": "1461",
"rack": "1",
"slot": "4",
"channel": "1"
},{ ...