C# 获取ViewColumn的BaseColumn

假设这一观点：

SELECT
 [Pr].[Id],
 [Pr].[Title],
 [Pr].[Category_Id] AS [CategoryId],
 [Pr].[IsScanAllowed],
 [Pr].[MaxLevelOfRegistration],
 [Cat].[Title] AS [Category],
 [Cat].[MajorCategory_Id] AS [MajorCategoryId],
 [Mc].[Title] AS [MajorCategory]
 [Cat].[Title]+[Pr].[Title] AS [FullProduct]
FROM [Products].[Product] AS [Pr]
INNER JOIN [Products].[Category] AS [Cat] ON [Pr].[Category_Id] = [Cat].[Id]
INNER JOIN [Products].[MajorCategory] AS [Mc] ON [Cat].[MajorCategory_Id] = [Mc].[Id];

---

因此，除了作为计算列的

[FullProduct]

之外，是否有任何方法可以找到此视图中每个列的基列？所有其他列都有一个基列。类似于这样：

BaseOf（MajorCategoryId）是[Products].[MajorCategory].[Id]

我尝试使用

Microsoft.SqlServer.Management.Smo

但我找不到任何东西，有人知道吗？

因为它没有传回客户端，但您可以构造列名来显示它——如下所示：

SELECT
 [Pr].[Id] AS [Products_Id],
 [Pr].[Title] AS [Products_Title],
 [Pr].[Category_Id] AS [Products_CategoryId],
 [Pr].[IsScanAllowed] AS [Products_IsScanAllowed],
 [Pr].[MaxLevelOfRegistration] [Products_MaxLevelOfRegistration],
 [Cat].[Title] AS [Category_Title],
 [Cat].[MajorCategory_Id] AS [Category_MajorCategoryId],
 [Mc].[Title] AS [MajorCategory_Title]
 [Cat].[Title]+[Pr].[Title] AS [FullProduct]
FROM [Products].[Product] AS [Pr]
INNER JOIN [Products].[Category] AS [Cat] ON [Pr].[Category_Id] = [Cat].[Id]
INNER JOIN [Products].[MajorCategory] AS [Mc] ON [Cat].[MajorCategory_Id] = [Mc].[Id];

然后，要查看该表，您可以在

上获取拆分中的第一项


您还可以使用SQL元数据下载视图的源代码，并对其进行解析，但这对我来说似乎是一项艰巨的工作。
由于它没有传回客户端，因此无法知道这一点，但您可以构造列名来显示它——如下所示：

SELECT
 [Pr].[Id] AS [Products_Id],
 [Pr].[Title] AS [Products_Title],
 [Pr].[Category_Id] AS [Products_CategoryId],
 [Pr].[IsScanAllowed] AS [Products_IsScanAllowed],
 [Pr].[MaxLevelOfRegistration] [Products_MaxLevelOfRegistration],
 [Cat].[Title] AS [Category_Title],
 [Cat].[MajorCategory_Id] AS [Category_MajorCategoryId],
 [Mc].[Title] AS [MajorCategory_Title]
 [Cat].[Title]+[Pr].[Title] AS [FullProduct]
FROM [Products].[Product] AS [Pr]
INNER JOIN [Products].[Category] AS [Cat] ON [Pr].[Category_Id] = [Cat].[Id]
INNER JOIN [Products].[MajorCategory] AS [Mc] ON [Cat].[MajorCategory_Id] = [Mc].[Id];

然后，要查看该表，您可以在
上获取拆分中的第一项


您还可以使用SQL元数据下载视图的源代码，并对其进行解析，但这对我来说似乎是一项艰巨的工作