C# 为每个用户生成个人id

无论如何，我可以用c生成一个唯一的序列号。我们正在开发一个网站，在注册时为每个用户分配一个个人id。。。我需要生成一个14位的字符串

For eg.

AA 01 201 210 22

AA 02 201 210 22

.

.

AA 99 201 210 22

then it should start from

AB 01 201 210 22

AB 02 201 210 22 and so on...

Last 8 digits are current date...

Thanks....



private string ConvertDecString(int value)
       {
            string CHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
            string retVal = string.Empty;
            int remainder = 0;
            do
            {
                remainder = value % 26;
                retVal = CHARS.Substring(remainder, 1) + retVal;
                value = (value / 26) - 1;
            }
            while ((value + 1) > 0);
            return retVal;
        }


public string GetCurrentDate()
    {
        string todaydate = System.DateTime.Now.Year.ToString() + System.DateTime.Now.Month.ToString() + System.DateTime.Now.Day.ToString();
        return todaydate;
    }

    private Random _random = new Random();

    public int RadomNum()
    {
        return _random.Next(10, 99);
    }

private string GetActualDate()
    {
        string Year = System.DateTime.Now.Year.ToString();
        string ActualDate1 = Year + GetProperMonth() + GetProperDay();
        int n = Convert.ToInt32(ActualDate1);
        string ActualDate = String.Format("{0:000 000 00}", n);
        return ActualDate;
    }

    private string GetProperMonth()
    {
        string Month = System.DateTime.Now.Month.ToString();
        string MonthNo = "";

        if (Month == "1")
        {
            MonthNo = "01";
        }
        else if (Month == "2")
        {
            MonthNo = "02";
        }
        else if (Month == "3")
        {
            MonthNo = "03";
        }
        else if (Month == "4")
        {
            MonthNo = "04";
        }
        else if (Month == "5")
        {
            MonthNo = "05";
        }
        else if (Month == "6")
        {
            MonthNo = "06";
        }
        else if (Month == "7")
        {
            MonthNo = "07";
        }
        else if (Month == "8")
        {
            MonthNo = "08";
        }
        else if (Month == "9")
        {
            MonthNo = "09";
        }
        else
        {
            MonthNo = Month;
        }
        return MonthNo;
    }


    private string GetProperDay()
    {
        string Day = System.DateTime.Now.Day.ToString();
        string DayNo = "";

        if (Day == "1")
        {
            DayNo = "01";
        }
        else if (Day == "2")
        {
            DayNo = "02";
        }
        else if (Day == "3")
        {
            DayNo = "03";
        }
        else if (Day == "4")
        {
            DayNo = "04";
        }
        else if (Day == "5")
        {
            DayNo = "05";
        }
        else if (Day == "6")
        {
            DayNo = "06";
        }
        else if (Day == "7")
        {
            DayNo = "07";
        }
        else if (Day == "8")
        {
            DayNo = "08";
        }
        else if (Day == "9")
        {
            DayNo = "09";
        }
        else
        {
            DayNo = Day;
        }
        return DayNo;
    }

    public string GeneratePatientNumber(string Alpha)
        {
            return ConvertDecString(Convert.ToInt16(Alpha)) + " " + RadomNum() + " " + GetActualDate();
        }

GeneratePatientNumber(string Alpha) - this method generates 12 digit personal id...

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您可以使用Guid类创建唯一的32个字符长度的字符串

Guid g;
g = Guid.NewGuid();
Console.WriteLine(g);
Console.WriteLine(Guid.NewGuid());

---

C&p from:

那么你的问题是什么？您希望社区提供代码吗？这似乎不是一个复杂的问题：它是一个包含日期和递增计数器的格式化字符串。你试过什么？到目前为止你试过任何方法吗？我试过一个代码，它给我一个序列，比如一个2位数的随机数字…n然后是日期…你能发布你目前拥有的代码吗？从OP:“我需要生成一个14位数的字符串”。它给出了一个错误，说不能在这一行隐式地将int类型转换为char：char letter1='a'+n/10/26/26%26;好啊我添加了类型转换。非常感谢，伙计。。。。但我们的要求是在AA 99之后，它应该从AB 01开始，以此类推。。。。每一天都从AA 01开始，第一个注册用户的那一天..如何管理所有这些事情。。。谢谢。@punit这是一个问答网站，不是一个让人们为你编写代码的地方。Anthony为您提供了一个非常合理的基础，让您继续使用并使其成为您自己的。只需重置_firstDigitCounter，我只是为了测试而做的。我想根据某个注册表id生成一个字符串…即，我要将int作为参数传递给函数。。。。

public string GetPersonalId (int n)
{
    char letter1 = (char)('A' + ((n / 10 / 26 / 26) % 26));
    char letter2 = (char)('A' + ((n / 10 / 26) % 26));
    char digit1 = (char)('0' + ((n / 10) % 10));
    char digit2 = (char)('0' + ((n) % 10));

    string dateString = string.Format("{0:yyyyMMdd}", DateTime.Today)
        .Insert(6, " ")
        .Insert(3, " ");

    return string.Format("{0}{1} {2}{3} {4}",
        letter1, letter2, digit1, digit2, dateString);
}

public GetNextSequenceForToday()
{
    SqlCommand query = new SqlCommand()
    query.CommandText =
       "SELECT COUNT(*) FROM [Users] " +
       "WHERE [Date] >= @today AND [Date] < @tomorrow";
    query.Parameters.Add("@today", DateTime.Today);
    query.Parameters.Add("@tomorrow", DateTime.Today.AddDays(1));

    int count = Convert.ToInt32(query.ExecuteScalar());

    return count + 1;
}

public class IDGenerator { private int _firstLetter = 0; private int _secondLetter = 0; private int _firstDigitCounter = 90; private string _chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; public string NewID() { return twoLetters(); } private string twoLetters() { _firstDigitCounter += 1; if (_firstDigitCounter == 99) { _firstDigitCounter = 0; _secondLetter += 1; } if (_secondLetter > _chars.Length) { _secondLetter = 0; _firstLetter += 1; } return _chars.Substring(_firstLetter, 1) + _chars.Substring(_secondLetter, 1) + " " + _firstDigitCounter.ToString("00") + " " + DateTime.Now.Year.ToString().Insert(3, " ") + DateTime.Now.Date.ToString("MM dd"); } }