C# 无法从Json C获取特定字符串#

这就是我的json的样子：

我创建了以下代码：

public class user
{
    public string username { get; set; }
    public int userid
    {
        get;
        set;
    }
    public string red
    {
        get;
        set;
    }

    public string acompaccompelted_setup
    {
        get;
        set;
    }
}

string url = "localhost/testingdata/file.json";
HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
string jsonValue = "";
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)  
{
    StreamReader reader = new StreamReader(response.GetResponseStream());
    json = reader.ReadToEnd();
}

user  listing = JsonConvert.DeserializeObject<user>(json);

Console.WriteLine(listing.username);
Console.ReadLine();

为了从URL获取数据，我使用了以下代码：

public class user
{
    public string username { get; set; }
    public int userid
    {
        get;
        set;
    }
    public string red
    {
        get;
        set;
    }

    public string acompaccompelted_setup
    {
        get;
        set;
    }
}

string url = "localhost/testingdata/file.json";
HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
string jsonValue = "";
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)  
{
    StreamReader reader = new StreamReader(response.GetResponseStream());
    json = reader.ReadToEnd();
}

user  listing = JsonConvert.DeserializeObject<user>(json);

Console.WriteLine(listing.username);
Console.ReadLine();

---

然后我得到了JSON的完整列表。但我只想提取用户名。我试图按照这里给出的步骤进行操作，但没有成功。我做错了什么？

定义一个包装器

UserInfo

类来表示整个对象，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

定义

用户

类，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

AccompledInfo

属性是一个复杂的对象。因此，定义一个新类来表示它，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

对所有嵌套对象遵循相同的模式。i、 e.为每个嵌套对象定义一个类，在

JsonProperty

属性中使用属性和属性名称

然后使用

jsonvert

反序列化，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

var user=JsonConvert.DeserializeObject（json）；

---

对象

user

现在具有预期的所有属性。

定义一个包装器

UserInfo

类来表示整个对象，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

定义

用户

类，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

AccompledInfo

属性是一个复杂的对象。因此，定义一个新类来表示它，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

对所有嵌套对象遵循相同的模式。i、 e.为每个嵌套对象定义一个类，在

JsonProperty

属性中使用属性和属性名称

然后使用

jsonvert

反序列化，如下所示：

class UserInfo
{
    [JsonProperty(PropertyName = "user", NullValueHandling = NullValueHandling.Ignore)]
    public User User { get; set; }
}

class User
{
    [JsonProperty(PropertyName = "userName", NullValueHandling = NullValueHandling.Ignore)]
    public string UserName { get; set; }
    [JsonProperty(PropertyName = "userId", NullValueHandling = NullValueHandling.Ignore)]
    public long  UserId { get; set; }
    [JsonProperty(PropertyName = "accompletedSetup", NullValueHandling = NullValueHandling.Ignore)]
    public string AccompletedSetup { get; set; }
    [JsonProperty(PropertyName = "accompletedInfo", NullValueHandling = NullValueHandling.Ignore)]
    public AccompletedInfo AccompletedInfo { get; set; }
}

class AccompletedInfo
{
}

var user = JsonConvert.DeserializeObject<UserInfo>(json);

var user=JsonConvert.DeserializeObject（json）；

---

对象

user

现在具有预期的所有属性。

我尝试应用该建议，但现在我得到这一行“var user=JsonConvert.DeserializeObject（jsonValue）；”以下错误：其他信息：无法将字符串转换为整数：85860803272478784。路径“user.userid”，第1行，位置135。。我尝试应用Convert.ToInt（32）请使用更大的数据类型，如

long

作为

UserId

属性。天哪！现在它工作了！你是个明星！我花了好几天来处理它！我从你的评论中学到了很多！请允许我再问你一个问题，因为这是我第一次处理JSON并大量阅读，但似乎我仍然错过了一些东西。前一个很有魅力。我试图访问这个复杂对象，我这样做是为了遵循您的建议：public accountedinfo accountedinfo{get；set；}class accountedinfo{[JsonProperty（PropertyName=“completed”，NullValueHandling=NullValueHandling.Ignore）]public string completed{get；set；}var user=JsonConvert.DeserializeObject（json）；但我得到了0值。为什么？我试图应用该建议，但现在我得到了这一行“var user=JsonConvert.DeserializeObject（jsonValue）”；以下错误：附加信息：无法将字符串转换为整数：85860803271478784.Path“user.userid”，第1行，位置135..我试图应用convert.ToInt（32）请为

UserId

属性使用更大的数据类型，如

long

。天哪！现在它工作了！你是个明星！我花了好几天时间处理它！我从你的评论中学到了很多！我可以再问你一个问题吗？因为这是我第一次处理JSON并阅读了很多内容，但似乎我仍然错过了一些东西。前一个问题很有效我试图访问这个复杂的对象，我这样做是为了遵循你的建议：public AccompletedInfo AccompletedInfo{get；set；}class AccompletedInfo{[JsonProperty（PropertyName=“completed”，NullValueHandling=NullValueHandling.Ignore）]public string completed{get；set；}var user=JsonConvert.DeserializeObject（json）；但我得到了0值。为什么？