Data binding 如何从Post方法响应解析xml字符串？

我有一个从Post方法返回的xml字符串：

private static void GetResponseCallback(IAsyncResult asynchronousResult)
{
    HttpWebRequest request = (HttpWebRequest)asynchronousResult.AsyncState;

    // End the operation
    HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(asynchronousResult);
    HttpStatusCode rcode = response.StatusCode;

    var stream = new GZipInputStream(response.GetResponseStream());
    using (StreamReader reader = new StreamReader(stream))
    {
        responseString = reader.ReadToEnd();                
    }          

    response.Close();
}

responseString是我想要解析的字符串，使用下面的parseXmlString类。但是，由于静态错误，我无法直接调用方法parseXmlString。如何将responseString传递给parseXmlString方法，让它们解析并绑定到listBox。或者无论如何，有相同的结果将是伟大的

void parseXmlString()
{
    byte[] byteArray = Encoding.UTF8.GetBytes(responseString);
    MemoryStream str = new MemoryStream(byteArray);
    str.Position = 0;

    XDocument xdoc = XDocument.Load(str);

    var data = from query in xdoc.Descendants("tracks").Elements("item")
               select new searchResult
               {
                   artist = (string)query.Element("artist"),
                   album = (string)query.Element("album"),
                   track = (string)query.Element("track"),
                   //   artistA = (string)query.Element("artists").Element("artist"),
               };
    //  ListBox lb = new ListBox();

    listBox1.ItemsSource = data;

    var data1 = from query in xdoc.Descendants("artists").Elements("item")
                select new searchResult
                {
                    artistA = (string)query.Element("artist"),
                };
    listBox2.ItemsSource = data1;
}

---

你的方法是逆向逻辑。您知道可以在方法上有返回值，对吗？-）

您需要做的是让您的

ParseXmlString

方法将

responseString

作为参数，并让它返回创建的

IEnumerable

，如下所示：

private IEnumerable<SearchResult> ParseXmlString(responseString)
{
    XDocument xdoc = XDocument.Load(responseString);

    var data =
        from query in xdoc.Descendants("tracks").Elements("item")
        select new SearchResult
        {
           Artist = (string)query.Element("artist"),
           Album = (string)query.Element("album"),
           Track = (string)query.Element("track"),
        };

    return
        from query in xdoc.Descendants("artists").Elements("item")
        select new SearchResult
        {
           ArtistA = (string)query.Element("artist"),
        };
}

---

如果您需要对回调有一些基本的了解，您可以看到这个答案：

我应该将GetResponseAsync（…添加到哪里？正如我所说的，您需要重新编写异步代码以进行回调，这样您就可以在回调完成时收到通知。（还请记住，您需要使用

调度程序

，因为HttpWebRequest不在UI线程上运行）。如果需要了解回调如何工作，请阅读最后一个链接。

// This being your method to get the async response
GetResponseAsync(..., responseString =>
{
    var searchResults = ParseXmlString(responseString);
    listBox2.ItemsSource = searchResults;
})