Date 如何将RESTAPI中Java类的当前日期传递给GraphQLAPI

我正在尝试从Springboot类调用GraphQLAPI。 它会抛出一个错误，如下所示，我知道这个问题是由于我发送到GraphQLAPI的日期造成的

如果我从postman调用相同的graphQL，它工作正常，数据也插入到数据库中。 邮递员正文中给出的输入如下所示

mutation{
    createAggrgtrApplctnByOrgid(orgid: "orgid",applctnnm:  "applctnnm",dispnm: "dispnm",applfortxt: "applfortxt",crtdbytxt: "crtdbytxt",updtdbytxt: "updtdbytxt",applctnid: "applctnid",loadts: "loadts",crtdts: "crtdts",updtdts: "updtdts",extrnlapplctnid: "extrnlapplctnid",isdeletedflg: isdeletedflg)
}

String gqlTemplate = resourceReader.asString(createAppGql);;
        DateTimeFormatter formatter = DateTimeFormatter.ofPattern(Constants.DATE_TIME_FORMAT);
        LocalDateTime dateTime = LocalDateTime.now();
        String formattedDateTime = dateTime.format(formatter);
        return txt.replace("orgid", applicationData.getOrganizationId())
                .replace("applctnnm", applicationData.getApplicationName())
                .replace("dispnm", applicationData.getApplicationDisplayName())
                .replace("applfortxt", "")
                .replace("crtdbytxt",applicationData.getRole())
                .replace("updtdbytxt", applicationData.getRole())
                .replace("loadts", "2020-06-28T16:48:37.000+0000")
                .replace("crtdts", "2020-06-28T16:48:37.000+0000")
                .replace("updtdts", "2020-06-28T16:48:37.000+0000")
                .replace("extrnlapplctnid", applicationData.getExternalApplicationId())
                .replace("isdeletedflg", "false" ); 
HttpEntity<String> entity = new HttpEntity<>(queryTemplate, headers);
ResponseEntity<AppDataResponse> response = restTemplate.exchange(appURL, HttpMethod.POST, entity,
                    AppDataResponse.class);

突变{createNewApplication（orgid:“test”，applctnnm:“mynewappl”，dispnm:“test”，applforText:“test”，crtdbytxt:“test”，updtdbytxt:“test”，applid:“test”，loadts:“2020-06-28T16:48:37.000+0000”，updtdtts:“2020-06-28T16:48:37.000+0000”，extrnlappctnid:“test”，isdeletdflg:true）

springbootapi中的graphql文件如下所示

mutation{
    createAggrgtrApplctnByOrgid(orgid: "orgid",applctnnm:  "applctnnm",dispnm: "dispnm",applfortxt: "applfortxt",crtdbytxt: "crtdbytxt",updtdbytxt: "updtdbytxt",applctnid: "applctnid",loadts: "loadts",crtdts: "crtdts",updtdts: "updtdts",extrnlapplctnid: "extrnlapplctnid",isdeletedflg: isdeletedflg)
}

String gqlTemplate = resourceReader.asString(createAppGql);;
        DateTimeFormatter formatter = DateTimeFormatter.ofPattern(Constants.DATE_TIME_FORMAT);
        LocalDateTime dateTime = LocalDateTime.now();
        String formattedDateTime = dateTime.format(formatter);
        return txt.replace("orgid", applicationData.getOrganizationId())
                .replace("applctnnm", applicationData.getApplicationName())
                .replace("dispnm", applicationData.getApplicationDisplayName())
                .replace("applfortxt", "")
                .replace("crtdbytxt",applicationData.getRole())
                .replace("updtdbytxt", applicationData.getRole())
                .replace("loadts", "2020-06-28T16:48:37.000+0000")
                .replace("crtdts", "2020-06-28T16:48:37.000+0000")
                .replace("updtdts", "2020-06-28T16:48:37.000+0000")
                .replace("extrnlapplctnid", applicationData.getExternalApplicationId())
                .replace("isdeletedflg", "false" ); 
HttpEntity<String> entity = new HttpEntity<>(queryTemplate, headers);
ResponseEntity<AppDataResponse> response = restTemplate.exchange(appURL, HttpMethod.POST, entity,
                    AppDataResponse.class);

我的Java文件中的代码如下所示

mutation{
    createAggrgtrApplctnByOrgid(orgid: "orgid",applctnnm:  "applctnnm",dispnm: "dispnm",applfortxt: "applfortxt",crtdbytxt: "crtdbytxt",updtdbytxt: "updtdbytxt",applctnid: "applctnid",loadts: "loadts",crtdts: "crtdts",updtdts: "updtdts",extrnlapplctnid: "extrnlapplctnid",isdeletedflg: isdeletedflg)
}

String gqlTemplate = resourceReader.asString(createAppGql);;
        DateTimeFormatter formatter = DateTimeFormatter.ofPattern(Constants.DATE_TIME_FORMAT);
        LocalDateTime dateTime = LocalDateTime.now();
        String formattedDateTime = dateTime.format(formatter);
        return txt.replace("orgid", applicationData.getOrganizationId())
                .replace("applctnnm", applicationData.getApplicationName())
                .replace("dispnm", applicationData.getApplicationDisplayName())
                .replace("applfortxt", "")
                .replace("crtdbytxt",applicationData.getRole())
                .replace("updtdbytxt", applicationData.getRole())
                .replace("loadts", "2020-06-28T16:48:37.000+0000")
                .replace("crtdts", "2020-06-28T16:48:37.000+0000")
                .replace("updtdts", "2020-06-28T16:48:37.000+0000")
                .replace("extrnlapplctnid", applicationData.getExternalApplicationId())
                .replace("isdeletedflg", "false" ); 
HttpEntity<String> entity = new HttpEntity<>(queryTemplate, headers);
ResponseEntity<AppDataResponse> response = restTemplate.exchange(appURL, HttpMethod.POST, entity,
                    AppDataResponse.class);

String gqlTemplate=resourceReader.asString（createAppGql）；；
DateTimeFormatter formatter=DateTimeFormatter.of模式（常数.DATE\u TIME\u格式）；
LocalDateTime dateTime=LocalDateTime.now（）；
字符串formattedDateTime=dateTime.format（格式化程序）；
返回txt.replace（“orgid”，applicationData.getOrganizationId（））
.replace（“applctnnm”，applicationData.getApplicationName（））
.replace（“dispnm”，applicationData.getApplicationDisplayName（））
.replace（“applforText”，即“”）
.replace（“crtdbytxt”，applicationData.getRole（））
.replace（“updtdbytxt”，applicationData.getRole（））
.替换（“荷载”，“2020-06-28T16:48:37.000+0000”）
.替换（“crtdts”，“2020-06-28T16:48:37.000+0000”）
.替换（“UPDTS”，“2020-06-28T16:48:37.000+0000”）
.replace（“extrnlappctnid”，applicationData.getExternalApplicationId（））
.替换（“isdeletedflg”、“false”）；
HttpEntity=新的HttpEntity（queryTemplate，Header）；
ResponseEntity response=restTemplate.exchange（appURL、HttpMethod.POST、entity、，
AppDataResponse.class）；

请某人帮助我解决这个问题。如何将日期从java类传递到GraphQLAPI

谢谢！ Ram

您的

txt.replace（）

没有替换txt字符串的正确部分

您的graphql文本是：

mutation{
    createAggrgtrApplctnByOrgid(
        orgid: "orgid",
        applctnnm:  "applctnnm",
        dispnm: "dispnm",
        applfortxt: "applfortxt",
        crtdbytxt: "crtdbytxt",
        updtdbytxt: "updtdbytxt",
        applctnid: "applctnid",
        loadts: "loadts",
        crtdts: "crtdts",
        updtdts: "updtdts",
        extrnlapplctnid: "extrnlapplctnid",
        isdeletedflg: isdeletedflg)
}

执行

txt.replace（“UPDTS”，“2020-06-28T16:48:37.000+0000”）

时，您将在2020-06-28T16:48:37.000+0000之前替换所有出现的

UPDTS

你的变异变成：

mutation{
    createAggrgtrApplctnByOrgid(
        orgid: "orgid",
        applctnnm:  "applctnnm",
        dispnm: "dispnm",
        applfortxt: "applfortxt",
        crtdbytxt: "crtdbytxt",
        updtdbytxt: "updtdbytxt",
        applctnid: "applctnid",
        loadts: "loadts",
        crtdts: "crtdts",
        2020-06-28T16:48:37.000+0000: "2020-06-28T16:48:37.000+0000",
        extrnlapplctnid: "extrnlapplctnid",
        isdeletedflg: isdeletedflg)
}

这是无效的，因为2020-06-28T16:48:37.000+0000不是有效的字段名！您需要避免替换字段名，而只替换值

---

我还建议使用适当的graphql客户端库，例如，而不是手动更新查询。

我应该承认，我太愚蠢了，没有注意到键和值都有相同的字符集。感谢AllirionX的快速思考，尽管我之前和另一位朋友注意到了这一点。投了赞成票！：-）@AllirionX这里是我类似的错误：我如何修复它？